D=|-347|+(-40)+3150+(-307)

=347-40+3150-307=3150

R =|-129|-119+|2-31|

=129-119+31-2=39

R =|-129|-119+|2-31|

Q= 100+98+96+...+4+2-97-95-...-3-1

Giải:

\(A=\left[\left(-8\right)+\left(-7\right)\right]+\left(-10\right)=\left(-15\right)+\left(-10\right)=\left(-25\right)\) 

\(B=-\left(-299\right)+\left(-219\right)+\left(-401\right)+12=299-219-401+12=-309\) 

\(C=555+\left(-100\right)+\left(-80\right)+\left|-333\right|=555-100-80+333=708\) 

\(D=\left|-347\right|+\left(-40\right)+3150+\left(-307\right)=347-40+3150-307=2456\) 

\(E=98.42-\left\{50.\left[\left(18-2^3\right):2+3^2\right]\right\}\) 

\(E=4116-\left\{50.\left[\left(18-8\right):2+9\right]\right\}\) 

\(E=4116-\left\{50.\left[10:2+9\right]\right\}\)

\(E=4116-\left\{50.\left[5+9\right]\right\}\) 

\(E=4116-\left\{50.14\right\}\) 

\(E=4116-700\) 

\(E=3416\) 

\(F=-80-\left[-130-\left(12-4^2\right)\right]+2008^0\) 

\(F=-80-\left[-130-\left(12-16\right)\right]+1\) 

\(F=-80-\left[-130-\left(-4\right)\right]+1\) 

\(F=-80-\left(-126\right)+1\) 

\(F=47\) 

\(G=1000+\left(-670\right)+297+\left(-330\right)=1000-670+297-330=297\) 

\(H=1024:2^4+140:\left(38+2^5\right)-7^{23}:7^{21}\) 

\(H=2^{10}:2^4+140:\left(38+32\right)-7^2\) 

\(H=2^6+140:70-49\) 

\(H=64+2-49\) 

\(H=17\) 

\(I=\left|-129\right|-119+\left|2-31\right|=129-119+\left|-29\right|=10+29=39\) 

\(K=219+573+381-173\) 

\(K=\left(219+381\right)+\left(573-173\right)\)

\(K=600+400\) 

\(K=1000\)

\(L=36.33-105.11+22.15\) 

\(L=36.33-35.3.11+11.2.3.5\) 

\(L=36.33-35.33+33.10\) 

\(L=33.\left(36-35+10\right)\) 

\(L=33.11\) 

\(L=363\) 

\(N=160-\left(2^3.5^2-6.25\right)\) 

\(N=160-\left[25.\left(8-6\right)\right]\) 

\(N=160-\left[25.2\right]\) 

\(N=160-50\) 

\(N=110\) 

\(O=\left(44.52.60\right):\left(11.13.15\right)=137280:2145=64\) 

\(P=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).\left(2^4-4^2\right)=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).0=0\)  

\(Q=100+98+96+...+4+2-97-95-...-3-1\) 

\(Q=100+\left(98-97\right)+\left(96-95\right)+...+\left(4-3\right)+\left(2-1\right)\) 

\(Q=100+1+1+...+1+1\) 

Vì có 98:2=49 số 1

\(\Rightarrow Q=100+49\) 

\(Q=149\)

a.

\(555+\left(-100\right)+\left(-80\right)+\left|-333\right|=555-100-80+333=708\)

b.

\(\left|-347\right|+\left(-40\right)+3150+\left(-307\right)=347-40+3150-307=3150\)

c.

\(1024\div2^4+140\div\left(38+2^5\right)-7^{23}\div7^{21}=2^{10}\div2^4+140\div\left(38+32\right)-7^2=2^6+140\div70-49=64+2-49=17\)

d.

\(\left(2^{17}+15^4\right)\times\left(3^{19}-2^{17}\right)\times\left(2^4-4^2\right)=\left(2^{17}+15^4\right)\times\left(3^{19}-2^{17}\right)\times\left(16-16\right)=\left(2^{17}+15^4\right)\times\left(3^{19}-2^{17}\right)\times0=0\)

sao mk ko thấy đáp số vậy bn , an làm chi tiết đ/s cho mk vs

C = 555 - 100 - 80 + 333 = 708

D = 98 . 42 - { 50 . (5 + 9)} = 4116 - 700 = 3416

E = 129 - 199 + 29 = - 41

F = (- 54).(-9) + 35.(-20) = 486 - 700 = - 214

G = - 25 . 30 - 75 . 20 =  - 750 - 1500 = - 2250

M = - 12 . (-11) + 2 . (-9) = 132 - 18 = 114

C=42

D=48,28

E= 41

mình tính từng đó thôi lớp 5 mà

Mấy bài này dễ màNguyễn Thanh Hằng

a, 120
b,10
c,-100
d,0

a) (-125) + 100 + 80 + 125 + 20

= [(-125) + 125] + (80 + 20) + 100

= 0 + 100 + 100

= 200

b) 27 + 55 + (-17) + (-55)

= [27 + (-17)] + [55 + (-55)]

= (27 - 17) + 0

= 10

c) (-92) + (-251) + (-8) + 251

= [(-251) + 251] + [(-92) + (-8)]

= 0 - 100

= -100

d) (-31) + (-95) + 131 + (-5)

= [(-31) + 131) + [(-95) + (-5)]

= 100 + (-100)

= 0 

Hok tốt

a) -125 + 100 + 80 + 125 + 20

= ( -125 + 125 ) + ( 80 + 20 ) + 100

= 0 + 100 + 100

= 200

b) 27 + 55 + (-17) + (-55)

= [ 27 + (-17) ] + [ 55 +(-55) ]

= 10 + 0 

= 10

c) -92 + (-251) + (-8) + 251

= [ -92 + (-8) ] + ( -251 + 251 )

= -100 + 0 

= -100

d) -31 + (-95) + 131 + (-5)

= ( -31 + 131 ) + [ -95 + (-5) ]

= 100 + (-100) = 0

\(347+\left(-40\right)+3150+\left(-307\right)\)

\(=\left(347-40-3-7\right)+3150\)

\(=0+3150\)

\(=3150\)

\(347+\left(-40\right)+3150+\left(-307\right)\)

\(=\left(347-307\right)+\left(-40+3150\right)\)

\(=40+3110\)

\(=3150\)

có thể viết rõ hơn ko mình ko hiểu