2 ) 3( x + 1 ) = 96 - 42

3( x + 1 ) = 54

x + 1 = 54 : 3

x + 1 = 18

x = 18 - 1

x = 17

1 ) a và b tìm : + có bao nhiu số trog dãy số đó

                      + tìm TBC

                      + nhân 2 cái lại

đó là cách của tớ .

lớp 6 học căn đâu

Bài 1

a, 32.(-64) - 64. 68

= -64.(32 + 68)

= -64 .100

= - 6400

b, -54.76 + 12.(-76) - 76.34

= -76.(54 + 12 + 34)

= -76.100

= -7600

19- 42.(-19) + 38.5

= 19 + 42.19 + 19.2.5

= 19.(1 + 42 + 10)

= 19.53

= 1007

d, 2.(-25).(-4).(-50)

= (2.(-50)). ((-25).(-4))

= -100 . 100

= -10000

B4

a)x=10

b)x=3

c)x=11

d)x=8

1.

a. 

11 + x : 5 = 13 

x : 5 = 13 - 11

x : 5 = 2

x      = 2 . 5

x      = 10

Bài 4: Tìm x, biết:
a) 11 + x : 5 = 13   

            x : 5 = 2

                 x = 10

b) 15 + (7 – x) = 19

               7 - x = 4

                    x = 3
c) 12 + 3.(x – 5) = 30   

           3 ( x - 5 ) = 18

                  x - 5 = 6

                       x = 11

 d) 17 + (x + 4) : 3 = 21

           ( x + 4 ) : 3 = 4

                    x + 4 = 12

                          x = 8

\(A=\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{99}}\)

\(\Rightarrow\dfrac{A}{3}=\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{100}}\)

\(\Rightarrow A-\dfrac{A}{3}=\dfrac{2A}{3}=\left(\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{99}}\right)-\left(\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{100}}\right)\)

\(\Rightarrow\dfrac{2A}{3}=\left(\dfrac{1}{3^2}-\dfrac{1}{3^2}\right)+\left(\dfrac{1}{3^3}-\dfrac{1}{3^3}\right)+...+\left(\dfrac{1}{3^{99}}-\dfrac{1}{3^{99}}\right)+\left(\dfrac{1}{3}-\dfrac{1}{3^{100}}\right)=\dfrac{1}{3}-\dfrac{1}{3^{100}}\)

\(\Rightarrow2A=3\cdot\left(\dfrac{1}{3}-\dfrac{1}{3^{100}}\right)\)

\(\Rightarrow\text{A}=\dfrac{1-\dfrac{1}{3^{99}}}{2}\)

\(\Rightarrow A=\dfrac{1}{2}-\dfrac{1}{2.3^{99}}< \dfrac{1}{2}\)

a,\(\left(x-15\right):50+22=24\)

\(< =>\frac{\left(x-15\right)}{50}=2< =>x-15=100\)

\(< =>x=100+15=115\)

b,\(42-\left(2x+32\right)+12:2=6\)

\(< =>42-2x-32=0\)

\(< =>10-2x=0< =>x=\frac{10}{2}=5\)

Làm nốt :

c) \(134-2\left\{156-6\cdot\left[54-2\cdot\left(9+6\right)\right]\right\}\cdot x=86\)

=> 134 - 2{156 - 6 . [54 - 2 . 15]} . x = 86

=> 134 - 2{156 - 6 . [54 - 30]} . x = 86

=> 134 - 2{156 - 6. 24} . x = 86

=> 134 - 2{156 - 144} . x = 86

=> 134 - 2.12 . x = 86

=> 134 - 24 . x = 86

=> 24.x = 48

=> x = 2

Bài 2 : a) 120 : [21 - (4x - 4)] = 2³.3

=> 120 : [21 - (4x - 4)] = 8.3

=> 120 : [21 - (4x - 4)] = 24

=> 21 - (4x - 4) = 5

=> 4x - 4 = 16

=> 4x = 20

=> x = 5

b) 3.[205 - (x - 9)] - 486 = 0

=> 3.[205 - (x - 9)] = 486

=> 205 - (x - 9) = 162

=> x - 9 = 205 - 162 = 43

=> x = 43 + 9 = 52

c) 204 - 2{200 - 5.[64 - 2.(11 + 6)]} . x = 4

=> 204 - 2{200 - 5.[64 - 2.17]} . x = 4

=> 204 - 2{200 - 5 .[64 - 34]}.x = 4

=> 204 - 2{200 - 5.30} . x = 4

=> 204 - 2{200 - 150}.x = 4

=> 204 - 2.50 . x = 4

=> 2.50.x = 200

=> 100.x = 200

=> x = 2

C1:

a. 786 x ( 32 +68)

= 786 x  100

= 78600

b. 2904 x 15 + 2904 x 35

= 43560 + 101640

= 145200

c.436 x 72 - 436 x 42

= 31392 - 18312

= 13080

d.194 x (87-7)

= 194 x 80

=15520

e.3332 : (4x49)

= 3332 : 196

= 17

f. 72 : 9 : 8

= (72 : 9) :8

= 1

g. (15 x 24) : 6

= 360 :6

= 60

m. 25 x(36 :9)

= 25 x 4

= 100

Cách 2:

a.786 x 32 + 786 x 68

= 25152 + 53448

= 78600

b. 2904 x ( 15 + 35)

= 2904 x 50

= 145200

c.436 x (72 -42)

= 436 x 30

= 13080

d.194 x 87 - 194 x7

= 16878 - 1358

= 15520

e. 3332 : (4 x 49)

= 3332 : 4 : 49

= 833 : 49 = 17

f. 72 : 9 :8

= 72 : (9 x8)

= 72 : 72

=1

g. (15 x 24) :6 

= 15 x (24 :6)

= 15 x 4

= 60

m. 25 x (36 :9)

= ( 25 x36 ):9

= 900 : 9

=100