\(A=1-3+5-7+......-2019+2021-2023\)

\(A=\left(1-3\right)+\left(5-7\right)+....+\left(2021-2023\right)\)

\(A=-2+\left(-2\right)+....+\left(-2\right)\left(506 cặp\right)\)

\(A=-2.506\)

\(A=-1012\)

*) A=(1-3)+(5-7)+....+(2021-2023)

<=> A=-2+(-2)+...+(-2)

Dãy A có (2023-1):2+1=1012 số số hạng 

=> Có 506 số (-2)

=> A=(-2).506=-1012

\(B=1+2-3-4+5+6-7-8+......+2017+2018-2019-2020\)

\(B=\left(1+2-3-4\right)+\left(5+6-7-8\right)+.....+\left(2017+2018-2019-2020\right)\)

\(B=-4+\left(-4\right)+.....+\left(-4\right)\left(505 cặp\right)\)

\(B=-4.505\)

\(B=-2020\)

S=1+(2-3)+(-4+5)+(6-7)+(-8+9)+...+(-2020+2021)
S=1-1+1-1+1+...+1
S=1+0+0+...+0
S=1

\(S=1+2-3-4+...+2017+2018-2019-2020+2021\\ S=\left(1+2-3-4\right)+...+\left(2017+2018-2019-2020\right)+2021\\ S=\left(-4\right)+\left(-4\right)+\left(-4\right)+...+-4+2021\\ S=505.\left(-4\right)+2021\\ S=-2020+2021\\ S=1\)

ra kết quả luôn hả

A = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ... + 2018 – 2019 - 2020 + 2021 
 
A = (1 + 2 - 3 - 4) + ... + (2017 + 2018 – 2019 - 2020) + 2021
 
A = (-4) + ... + (-4) + 2021 + 
 
2020 : 4 = 505
 
A = (-4) . 505 + 2021 
 
A = (-2020) + 2021 
 
A = 1

Vậy A=1

Mình gửi bạn nha !!!!!

Ta có: \(S=1+2-3-4+5+6-...+2018-2019-2020+2021\)

\(=\left(-4\right)\cdot505+2021\)

=2021-2020

=1

\(S=\left(1+2-3-4\right)+\left(5+6-7-8\right)+...+\left(2017+2018-2019-2020\right)+2021\\ S=\left(-4\right)+\left(-4\right)+...+\left(-4\right)+2021\)

Ta có từ 1 đến 2020 có 2020 số nên khi nhóm 4 số 1 cặp thì có \(2020:5=404\left(cặp\right)\)

Vậy \(S=404\left(-4\right)+2021=-1616+2021=405\)

S=1+(2-3)+(-4+5)+(6-7)+(-8+9)+...+(-2020+2021)
S=1-1+1-1+1+...+1
S=1+0+0+...+0
S=1

S=1+2-3-4+5+6-7-8+9+10-...+2018-2019-2020+2021

=1+(2-3-4+5)+(6-7-8+9)+...+(2018-2019-2020+2021)

=1+0+0+...+0

=1

Vậy S=1

$S=1+2-3-4+5+6-7-8+9+10-...+2018-2019-2020+2021$

$S=0+1-1+1-1+...-1-+1=0$

1

\(S=1+2-3-4+5+6-7-8+9+10-...+2018-2019-2020+2021\)

\(S=0+1-1+1-1+...-1-+1=0\)

S = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ... + 2018 – 2019 - 2020 + 2021 + 2022

S = (1 + 2 - 3 - 4) + ... + (2017 + 2018 – 2019 - 2020) + 2021 + 2022

S = (-4) + ... + (-4) + 2021 + 2022

2020 : 4 = 505

S = (-4) . 505 + 2021 + 2022

S = (-2020) + 2021 + 2022

S = 2023

1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ... + 2018 – 2019 - 2020 + 2021 

=(1 + 2 - 3 - 4) + ... + (2017 + 2018 – 2019 - 2020) + 2021 

= (-4) + ... + (-4) + 2021 + 2020 : 4 = 505 

= (-4) . 505 + 2021  

= (-2020) + 2021  

= 1

I'm come back:Đ

=(-1)+(-1)+...+(-1)+2021

=2021-1010

=1011