Tính bằng cách thuận tiện:
11 x (X - 5) = 5 x X + 11
Tính bằng cách thuận tiện 5/6 x 4/11 + 5/6 x 7/11
tính bằng cách thuận tiện nhất
a, 20,23 x 21 + 20,23 x 80 - 20,23
b, 5/13 x 7/11 + 5/13 x 2/11 + 8/13 x 9/11
\(\dfrac{5}{13}\times\dfrac{7}{11}+\dfrac{5}{13}\times\dfrac{2}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\left(\dfrac{7}{11}+\dfrac{2}{11}\right)+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\dfrac{9}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{9}{11}\times\left(\dfrac{5}{13}+\dfrac{8}{13}\right)\)
\(=\dfrac{9}{11}\times1\)
\(=\dfrac{9}{11}\)
a) \(20,23\times21+20,23\times80-20,23\)
\(=20,23\times\left(21+80-1\right)\)
\(=20,23\times100\)
\(=2023\)
\(\dfrac{5}{13}\) \(\times\) \(\dfrac{7}{11}\) + \(\dfrac{5}{13}\) \(\times\) \(\dfrac{2}{11}\) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\left(\dfrac{5}{13}\times\dfrac{7}{11}+\dfrac{5}{13}\times\dfrac{2}{11}\right)\)+ \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{5}{13}\)\(\times\) (\(\dfrac{7}{11}\) + \(\dfrac{2}{11}\)) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{5}{13}\) \(\times\) \(\dfrac{9}{11}\) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{9}{11}\) \(\times\)( \(\dfrac{5}{13}\) +\(\dfrac{8}{13}\))
= \(\dfrac{9}{11}\) \(\times\) 1
= \(\dfrac{9}{11}\)
Tính bằng cách thuận tiện nhât:
7/5 x 11/24 x 5/7 x 24/55
\(\dfrac{7}{5}\times\dfrac{11}{24}\times\dfrac{5}{7}\times\dfrac{24}{55}\\ =\left(\dfrac{7}{5}\times\dfrac{5}{7}\right)\times\left(\dfrac{11}{24}\times\dfrac{24}{55}\right)\\ =1\times\dfrac{1}{5}\\ =\dfrac{1}{5}\)
\(\dfrac{7x11x5x24}{5x24x7x55}\)=\(\dfrac{11}{55}\)=\(\dfrac{1}{5}\)
= (7/5 x 5/7) x (11/24 x 24/55)
= 1 x 1/5
= 1/5
1.Tính bằng cách thuận tiện nhất :
(6/7 - 2/7) : 4/9 x 3 =
7/11 x 5/6 + 4/11 x 5/6 =
1,
a,=4/7:4/9.3
=9/7.3
=27/7
b,=(7/11+4/11).5/6
=1.5/6
=5/6
`(6/7-2/7):4/9xx3=4/7xx9/4xx3=[4xx9xx3]/[7xx4]=27/7`
`7/11xx5/6+4/11xx5/6=(7/11+4/11)xx5/6=11/11xx5/6=5/6`
Bài 6: Tính bằng cách thuận tiện nhất.
3 x 6/11 + 6/11 x 5 + 2 x 6/11
\(3\times\frac{6}{11}+\frac{6}{11}\times5+2\times\frac{6}{11}\text{ }\)
\(=\frac{6}{11}\times\left(3+5+2\right)\)
\(=\frac{6}{11}\times10\)
\(=\frac{60}{11}\)
các bạn giúp mik làm các bài này với mai mik nộp rồi huhu :
1) tính bằng cách thuận tiện nhất:
3/5 x 6/11 + 2/5 x 6/11
2) tính bằng cách thuận tiện nhất:
17/25 x 11/19 + 17/25 x 6/19 + 17/25 x 2/19
1) \(=\left(\frac{3}{5}+\frac{2}{5}\right).\frac{6}{11}\)
\(=1.\frac{6}{11}\)
\(=\frac{6}{11}\)
2)\(\frac{17}{25}.\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\)
\(=\frac{17}{25}.1\)
\(=\frac{17}{25}\)
2.\(\frac{17}{25}.\frac{11}{19}+\frac{17}{25}.\frac{6}{19}+\frac{17}{25}.\frac{2}{19}=\frac{17}{25}\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\\ =\frac{17}{25}.1\\ =\frac{17}{25}\)
Tính bằng cách thuận tiện
a) 5 x 11 x 15 x 18/6 x 15 x 22 x 10
b) 7/12 x 3/5 + 3/5 x 5/12
a, \(\dfrac{5\times11\times15\times18}{6\times15\times22\times10}\)
= \(\dfrac{5\times11\times15\times6\times3}{6\times15\times11\times2\times2\times5}\)
= \(\dfrac{5\times11\times15\times6}{5\times11\times15\times6}\) \(\times\) \(\dfrac{3}{2\times2}\)
= 1 \(\times\) \(\dfrac{3}{4}\)
= \(\dfrac{3}{4}\)
b, \(\dfrac{7}{12}\) \(\times\) \(\dfrac{3}{5}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{5}{12}\)
= \(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{7}{12}+\dfrac{5}{12}\))
= \(\dfrac{3}{5}\) \(\times\) \(\dfrac{12}{12}\)
= \(\dfrac{3}{5}\) \(\times\) 1
= \(\dfrac{3}{5}\)
tính bằng cách thuận tiện nhất :
a, 5/11 x 7/25 + 15/11 x 1/5
b, 3/7 x 25/19 - 1/7 x 18/19
giải giúp mình câu này với .
Tính bằng cách thuận tiện:
9/5 + 4/7 + 6/5 + 3/7 = .........................................................
1/2 x 45/33 x 1/9 x 11/6 = ....................................................
9/5 + 4/7 + 6/5 + 3/7
= ( 9/5 + 6/5 ) + ( 4/7 + 3/7)
= 3 + 1
= 4
9/5 + 4/7 + 6/5 + 3/7 = (9/5 + 6/5) + (4/7 + 3/7)
= 15/5 + 7/7
= 3 + 1
= 4
1/2 x 45/33 x 1/9 x 11/6 = (1/2 x 1/9) x (45/33 x 11/6)
= 1/18 x 45/18
= 5/2
1/2 x 45/33 x 1/9 x 11/6
= (1/2 x 1/9) x (45/33 x 11/6)
= 1/18 x 45/18
= 5/2