`2/5 + 9/15= 2/5 + 3/5=5/5=1`

`15/45 + 25/30= 1/3 + 5/6= 2/6+5/6=7/6`

`28/32 + 45/72=7/8+ 5/8=12/8=3/2`

`8/28 + 5/30= 2/7 + 1/6= 12/42 + 7/42= 19/42`

5+ 5 + 5 + 5+ 5 + 5 +5+ 5 + 5 +5=5x10=50

25 + 25 + 25 + 25 + 25 + 25 +25 + 25=25x8=200

45 + 45 + 45 + 45 + 15 + 15 + 15 + 15=(45x4)+(15x4)=180+60=240

5+ 5 + 5 + 5+ 5 + 5 +5+ 5 + 5 +5
= 5 x 10
= 50

25 + 25 + 25 + 25 + 25 + 25 +25 + 25
= 25 x 8
= 200

45 + 45 + 45 + 45 + 15 + 15 + 15 + 15
= 45 x 4 + 15 x 4
= 180 + 60
= 240

2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18
= (2 + 18) + (4 + 16) + (8 + 12) + (6 + 14) + 10
= 20 + 20 + 20 + 20 + 10 
= 20 x 4 + 10
= 80 + 10
= 90 

125 + 125 + 125 + 125 - 25 - 25 - 25 - 25 
= 4 x (125 - 25) 
= 4 x 100 
= 400
(Tick cho mk pls ^^)

a)5.(-8).2.(-3)

=[5.(-2)].[(-8).(-3)]

=-10.24

=-240

b)(45-135+72)-(45+72)

=45-135+72-45-72

=(45-45)+(72-72)-135

=0+0-135

=-135

c)3.(-5)².2+2.(-5)-20

=3.25.2+2(-5)-20

=75.2+(-10)-20

=150+(-30)

=120

d)86.(-46)+46.27-46.41

=86.(-1).46+46.27-46.41

=-86.46+46.27-46.41

=46(-86+27-41)

=46(-100)

-4600

e)34(15-10)-15(34-10)

=34.15-34.10-15.34+15.10

=(34.15-15.34)+(15.10-34.10)

=[34(15-15)]+[10(15-34)]

=34.0+10(-9)

=0+(-90)

=-90

a: \(-\dfrac{4}{7}-\dfrac{5}{13}\cdot\dfrac{-39}{25}+\dfrac{-1}{42}:\dfrac{-5}{6}\)

\(=\dfrac{-4}{7}+\dfrac{3}{5}+\dfrac{1}{35}\)

\(=\dfrac{-20}{35}+\dfrac{21}{35}+\dfrac{1}{35}\)

\(=\dfrac{2}{35}\)

11.9.2=11.18

45.3.5=15.45

6.3.11=11.18

9.5.15=15.45

vậy(1) 11.8=11.9.2=6.3.11

(2)15.45=45.3.5=9.5.15

=>A=6/5-(19/7+26/5).

=>A=6/5-26/5-19/7.

=>A=-20/5-19/7.

=>A=-4+(-19/7)=-4 19/7 (đay là hỗn số).

B=47*45-47*15-47*45+47*15.

=>B=(47*45-47*45)+(47*15-47*15).

=>B=0+0.

=>B=0.

tk nha.

-5 + ( -37 - 45 + 51 ) - ( -37 + 51 ) 

=-5+ -37 - 45 + 51- -37 + 51 

=(37+(-37) +(51-(-51) + (45 - (-5)

=0+0+50

=50

MIK MỚI LÀM ĐC PHẦN A)

=\(\left[\dfrac{\left(0,4.2\right)^5}{\left(0,4\right)^6}+\dfrac{2^9.2^6.3^8}{\left(3.2\right)^6.2^9}\right]=\left[\dfrac{\left(0,4\right)^5.2^5}{\left(0,4\right)^6}+\dfrac{2^6.3^8}{3^6.2^6}\right]\)

=\(\left[\dfrac{2^5}{0,4}+3^2\right]\)

=\(\left[80+9\right]=89\)

\(\left[\dfrac{\left(2.0,4\right)^5}{0,4,0,4^5}+\dfrac{2^{15}.3^8}{3^6.2^6.2^9}\right]\div\dfrac{3^{20}.5^{30}}{3^{15}.5^{30}}\)

\(=\left[\dfrac{2^5.0.4^5}{0,4.0,4^5}+\dfrac{2^{15}.3^8}{3^6.2^{15}}\right]\div3^5\)

\(=\left[\dfrac{2^5}{0,4}+3^2\right]\div243\)

\(=80+\left(3^5\div3^2\right)\)

\(=80+3^3\)

\(=80+27\)

\(=107\)

Phương pháp giải:

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