(9x^3-12x+3x):3x
giup mik voi
mấy bạn ơi giúp mik câu này vs
3x(12x-4)-(4x-3)(9x+4)=9
3x(12x-4)-(4x-3)(9x+4) = 9
36x2 -12x-(36x2 -16x-27x-12) = 9
36x2 -12x-36x2 -16x+27x+12 = 9
-x = 9-12
-x = -3
x= -3 : -1
x= 3
vậy x= 3
Tìm thương của phép chia: [9x^3 (x^2 - 1) − 6x^2 (x^2 - 1)^2 + 12x(x^2 -1)]: 3x(x^2 - 1). Giúp mik vs, mik cần gấp!!
[9x³(x² - 1) - 6x²(x² - 1) + 12x(x² - 1)] : 3x(x² - 1)
= [9x³(x² - 1) : 3x(x² - 1)] - [6x²(x² - 1) : 3x(x² - 1) + [12x(x² - 1) : 3x(x² - 1)]
= 3x² - 2x + 4
\(12x^3-9x^2+3x\\ x^2-y^2+6x+9x\)
Giúp mình ới
6) \(\sqrt{x^2+12x+36}=-x-6\)
7) \(\sqrt{9x^2-12x+4}=3x-2\)
8) \(\sqrt{16-24x+9x^2}=2x-10\)
9) \(\sqrt{x^2-6x+9}==2x-3\)
10) \(\sqrt{x^2-3x+\dfrac{9}{4}}=\dfrac{3}{x}x-4\)
6) ĐKXĐ: \(x\le-6\)
\(\sqrt{\left(x+6\right)^2}=-x-6\Leftrightarrow\left|x+6\right|=-x-6\)
\(\Leftrightarrow x+6=x+6\left(đúng\forall x\right)\)
Vậy \(x\le-6\)
7) ĐKXĐ: \(x\ge\dfrac{2}{3}\)
\(pt\Leftrightarrow\sqrt{\left(3x-2\right)^2}=3x-2\Leftrightarrow\left|3x-2\right|=3x-2\)
\(\Leftrightarrow3x-2=3x-2\left(đúng\forall x\right)\)
Vậy \(x\ge\dfrac{2}{3}\)
8) ĐKXĐ: \(x\ge5\)
\(pt\Leftrightarrow\sqrt{\left(4-3x\right)^2}=2x-10\)\(\Leftrightarrow\left|4-3x\right|=2x-10\)
\(\Leftrightarrow4-3x=10-2x\Leftrightarrow x=-6\left(ktm\right)\Leftrightarrow S=\varnothing\)
9) ĐKXĐ: \(x\ge\dfrac{3}{2}\)
\(pt\Leftrightarrow\sqrt{\left(x-3\right)^2}=2x-3\Leftrightarrow\left|x-3\right|=2x-3\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=2x-3\left(x\ge3\right)\\x-3=3-2x\left(\dfrac{3}{2}\le x< 3\right)\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(ktm\right)\\x=2\left(tm\right)\end{matrix}\right.\)
3x.(12x-4)-9x.(4x-3)=30
3x.(12x-4)-9x.(4x-3)=30
=> 36x2-12x-36x2+27x=30
=> 15x=30
=> x=30:15
=> x=2
3x.(12x-4)-9x(4x-3)=30
3x(12x-4)-9x(4x-3)=30
<=>36x2-12x-36x2+27x=30
<=>15x=30
<=>x=2
3x.(12x-4)-9x.(4x-3)=30
\(3x.\left(12x-4\right)-9x.\left(4x-3\right)=30\)
\(36x^2-12x-36x^2=27x=30\)
\(15x=30\)
\(x=2\)
\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
\(\Rightarrow36x^2-12x-36x^2+27x=30\)
\(\Rightarrow\left(36x^2-36x^2\right)+\left(27x-12x\right)=30\)
\(\Rightarrow15x=30\)
\(\Rightarrow x=2\)
\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
\(\Rightarrow36x^2-12x-36x^2+27x=30\)
\(\Rightarrow15x=30\Rightarrow x=2\)
Vậy...............
Chúc bạn học tốt!!!
3x(12x-4)-9x(4x-3)=30
\(\Rightarrow36x^2-12x-36x^2+27x=30\)
\(\Rightarrow15x=30\Rightarrow x=30:15=2\)
a)6x^3+3x^2+4x+1/3x^2+2
b) 12x^4+4x^3+9x+3/3x-2
Tìm x;
(12x^4-6x^3-9x^2):(-3x^2)-(2-3x)(2+3x)=-(3x+1)
Có ai làm dc câu này ko thầy mk cho đề hack não quá
\(\frac{12x^4-6x^3-9x^2}{-3x^2}-\left(2-3x\right)\left(2+3x\right)=-\left(3x+1\right)\)\(Dk:-3x^2\ne0\)\(< =>x\ne0\)
<=> \(-4x^2+2x+3-\left(2-3x\right).\left(2+3x\right)=-\left(3x+1\right)\)
<=> \(-4x^2+2x+3-4-6x+6x+9x^2=-3x-1\)
<=>\(5x^2+5x=0\)
<=> \(\orbr{\begin{cases}x=-1\left(n\right)\\x=0\left(l\right)\end{cases}}\)