a) 9x⁴+16y⁶-24x²y³

=(3x²)²-2.3x².4y³+(4y³)²

=(3x²-4y³)²

b) 16x²-24xy+9y²

=(4x)²-2.4x.3y+(3y)²

=(4x-3y)²

c) 36x²-(3x-2)²

=(36x-3x+2)(36x+3x-2)

=(33x+2)(39x-2)

d) 27x³+54x²y+36xy²+8y³

=(3x)³+3.(3x)².2y+3.3x.(2y)²+(2y)³

=(3x+2y)³

e) y⁹-9x²y⁶+27x⁴y³-27x⁶

=(y³)³-3.(y³)².3x²+3.y³.(3x²)²-(3x²)³

=(y³-3x²)³

f) 64x³+1

= (4x)³+1³

=(4x+1)[(4x)²-4x.1+1²]

=(4x+1)(16x²-4x+1)

e) 27x⁶-8x³  *sửa đề*

=(3x²)³-(2x)³

=(3x²-2x)[(3x)²+3x².2x+(2x)²]

=(3x²-2x)(9x²+6x³+4x²)

~~~

d) \(2x^2+5x-7=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{7}{2}\end{matrix}\right.\) \(\left(a+b+c=1\right)\)

\(\left(3-2x\right)^2=\left(x-2\right)\left(2x-3\right)\)

\(\Leftrightarrow\left(3x-2\right)^2-\left(x-2\right)\left(2x-3\right)=0\)

\(\Leftrightarrow9x^2-12x+4-\left(2x^2-7x+6\right)=0\)

\(\Leftrightarrow9x^2-12x+4-2x^2+7x-6=0\)

\(\Leftrightarrow7x^2-5x-2=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{2}{7}\end{matrix}\right.\)

Vậy \(S=\left\{1;-\dfrac{2}{7}\right\}\)

`(3-2x)^2=(x-2)(2x-3)`

`<=>(2x-3)^2 -(x-2)(2x-3)=0`

`<=> (2x-3)(2x-3-x+2)=0`

`<=> (2x-3)(x-1)=0`

\(< =>\left[{}\begin{matrix}2x-3=0\\x-1=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=1\end{matrix}\right.\)

\(i)4^8:x=4^6\\ x=4^8:4^6\\ x=4^2\\ k)12x-33=3^5\\ 12x-33=243\\ 12x=243+3\\ 12x=276\\ x=276:12\\ x=23\\ l)\left(5x+335\right):2=20^2\\ \left(5x+335\right):2=400\\ 5x+335=400.2\\ 5x+335=800\\ 5x=800-335\\ 5x=465\\ x=465:5\\ x=93\) 

\(m)\left(x^2-10\right):5=3\\ x^2-10=3.5\\ x^2-10=15\\ x^2=15+10\\ x^2=25\\ x^2=5^2\\ 740:\left(x+10\right)=10^2-2.13\\ 740:\left(x+10\right)=100-26\\ 740:\left(x+10\right)=74\\ x+10=740:74\\ x+10=10\\ x=10-10\\ x=0.\)

i) 4⁸:x=4⁶

<=> x = 4⁸ : 4⁶ = 4² = 16

k)12x-33=3⁵

<=> x = (3⁵ + 33) : 12 = 23

l)(5x+335):2=20²

<=> x = (20² x 2 - 335) : 5 = 93

m)(x²-10):5=3

<=> x² = 3 x 5 + 10 = 25

<=> x = 5 hoặc x = -5

740:(x+10)=10²-2.13

<=> x = 740 : (10² - 2.13) - 10 = 0

chiu

`a)`

`A(x) + B(x) = 2x - 4x^2 + 1 + x^3 - 4x^2 + 5 - 2x`

                  `= x^3 - ( 4x^2 + 4x^2 ) + ( 2x - 2x ) + ( 1+ 5 )`

                  `= x^3 - 8x^2 + 6`

__________________________________________________________

`b)`

    `P(x) + B(x) = A(x)`

`=>P(x) = A(x) - B(x)`

`=>P(x) = 2x - 4x^2 + 1 + x^3 + 4x^2 - 5 + 2x`

`=>P(x) = x^3 + ( -4x^2 + 4x^2 ) + ( 2x + 2x ) + ( 1 - 5 )`

`=>P(x) = x^3 + 4x - 4`

a: \(=a\left(y^2-2yz+z^2\right)\)

\(=a\left(y-z\right)^2\)

b: \(=\left(x^2+6xy+9y^2\right)-16\)

=(x+3y)^2-16

=(x+3y+4)(x+3y-4)

c: \(=7\left(a-b\right)+\left(a-b\right)\left(a+b\right)\)

=(a-b)(7+a+b)

d: \(36x^4-13x^2\)

=x^2*36x^2-x^2*13

=x^2(36x^2-13)

f: x^2-2xy+y^2-49

=(x-y)^2-49

=(x-y-7)(x-y+7)

e: 2x^3-18x

=2x(x^2-9)

=2x(x-3)(x+3)

g: 2x+2y-x^2-xy

=2(x+y)-x(x+y)

=(x+y)(2-x)

h: (x^2+3)^2+16

=x^4+6x^2+25

=x^4+10x^2+25-4x^2

=(x^2+5)^2-4x^2

=(x^2-2x+5)(x^2+2x+5)

\(=\dfrac{x^2\left(x-2\right)+5\left(x-2\right)}{x-2}=x^2+5\)