4.(5-x)-23=24.3
4(x-5)-23=24.3
\(4\left(x-5\right)-2^3=2^4.3\)
\(\Rightarrow4x-20-8=48\)
\(\Rightarrow4x=76\Rightarrow x=19\)
4(x-5) - 2^3 =2^4.3
4(x-5)-2^3=16.3
4(x-5)-2^3=48
4(x-5)=48+2^3
4(x-5)=56
x-5=56:4
x-5=14
x=14+5
x=19
sai mong mn thông cảm nha
4.( 5 - x ) - 23 = 24.3
\(4\cdot\left(5-x\right)-2^3=2^4\cdot3\)
\(\Rightarrow4\cdot\left(5-x\right)-2^3=16\cdot3\)
\(\Rightarrow4\cdot\left(5-x\right)-2^3=48\)
\(\Rightarrow4\cdot\left(5-x\right)=48+8\)
\(\Rightarrow4\cdot\left(5-x\right)=56\)
\(\Rightarrow5-x=56:4\)
\(\Rightarrow5-x=14\)
\(\Rightarrow x=5-14\)
\(\Rightarrow x=-9\)
4(x–5)–23=24.3
\(4\left(x-5\right)-23=24\cdot3\)
\(4\left(x-5\right)-23=72\)
\(4\left(x-5\right)=72+23\)
\(4\left(x-5\right)=95\)
\(x-5=\dfrac{95}{4}\)
\(x=\dfrac{95}{4}+5\)
\(x=\dfrac{115}{4}\)
\(4(x–5)-23=24.3\)
\(4(x–5)-23=72\)
\(4(x–5)=72+23\)
\(4(x-5)=95\)
\(x-5=95:4\)
\(x-5=23,75\)
\(x=23,75+5\)
\(x=28,75\)
4 ( x - 5 ) - 23 = 24 . 3
=> 4(x-5)-23=72
=> 4(x-5)=72+23
=> 4(x-5)=95
=> x-5=95/4
=> x-5 = 23,75
=> x = 23,75 + 5
=>x = 28,75
a.x - 8 : 4 - (46 - 23 .2 + 6 . 3) = 0
b. 240 - (23 + (13+24.3-x)) = 132
Có bao nhiêu giá trị của x thỏa mãn 240−[23+(13+24.3−x)]=132?
A. 3
B. 2
C. 1
D. 4
4(x-5)-16=24.3
\(4\left(x-5\right)-16=24\cdot3\)
\(\Rightarrow4\left(x-5\right)-16=72\)
\(\Rightarrow4\left(x-5\right)=72+16\)
\(\Rightarrow4\left(x-5\right)=88\)
\(\Rightarrow x-5=\dfrac{88}{4}\)
\(\Rightarrow x-5=22\)
\(\Rightarrow x=22+5\)
\(\Rightarrow x=27\)
\(4.\left(x-5\right)-16=24.3\)
\(4.\left(x-5\right)-16=72\)
\(4.\left(x-5\right)=72+16\)
\(4.x-5=88\)
\(x-5=88:4\)
\(x-5=22\)
\(x=22+5\)
\(x=27\)
tìm x
x-8:4-(46-23.2+6.3)=0
240-[23+(13+24.3-x)]=132
(19x+2.5^2):14=(13-8)^2-4^2
(x+3)+3(x+1)=39
240-[23+(13+24.3-x)]=132
240-[23+(13+168-x)]=132
240-[23+(181-x)]=132
|
x-8:4-(46-23.2+6.3)=0
\(x-8:4-\left(46-23.2+6.3\right)=0\)
\(x-2-\left(46-46+18\right)=0\)
\(x-2-18=0\)
\(x-2=0+18\)
\(x-2=18\)
\(x=18+2\)
\(x=20\)
\(240-\left[23+\left(13+24.3-x\right)\right]=132\)
\(240\left[23+\left(13+82-x\right)\right]=132\)
\(23+\left(95-x\right)=132:240\)
\(23+\left(95-x\right)=\frac{132}{240}=\frac{11}{30}\)
\(23+\left(95-x\right)=\frac{11}{30}\)
\(95-x=\frac{11}{30}-23\)
\(95-x=\frac{11}{30}-\frac{690}{30}\)
\(95-x=-\frac{679}{30}\)
\(x=95+\frac{679}{30}\)
\(x=\frac{2850}{30}+\frac{679}{30}\)
\(x=\frac{3529}{30}=\)tự rút gọn ( nếu có thể )
giúp mình với mình cần gấp
(3^6+24.3^5):3^4
= [3^6.(3+24)]:3^4
= (3^6.27) : 3^4
= 3^9 : 3^4
= 3^5
= 243
em lá bin si ghss
24.3 + X : 16 - 3.4 = 30.34
Tim X
[-3/2]^3+-49/24.3/14-[5/8-27/8]
Ta có: \(\left(-\dfrac{3}{2}\right)^3+\dfrac{-49}{24}\cdot\dfrac{3}{14}-\left(\dfrac{5}{8}-\dfrac{27}{8}\right)\)
\(=\dfrac{-27}{8}+\dfrac{-7}{2}\cdot\dfrac{1}{8}-\dfrac{-22}{8}\)
\(=\dfrac{-27+22}{8}+\dfrac{-7}{16}\)
\(=\dfrac{-5}{8}+\dfrac{-7}{16}\)
\(=\dfrac{-10}{16}+\dfrac{-7}{16}\)
\(=\dfrac{-17}{16}\)