a)

 \(\left(2x-15\right)^5=\left(2x-15\right)^3\\ \Leftrightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\\ \Leftrightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15-1\right).\left(2d-15+1\right)=0\end{matrix}\right.\\\Leftrightarrow\left[{}\begin{matrix}2x-15=0\\2x-16=0\\2x-14=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=7\end{matrix}\right. \)

b) \(\left(7x-11\right)^3=\left(-3\right)^2.15+208\\ \Leftrightarrow\left(7x-11\right)^3=343=7^3\\ \Leftrightarrow7x-11=7\\ \Leftrightarrow x=\dfrac{18}{7}\)

\(\Leftrightarrow3y\left(x+5\right)+2\left(x+5\right)=-25\)

\(\Leftrightarrow\left(3y+2\right)\left(x+5\right)=-25\)

cái này phải thêm x,y thuộc Z nữa chứ k thuộc thì t làm k làm nổi đâu :))

Ta có : \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)

\(\Rightarrow\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)

\(\Leftrightarrow\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x-15=0\\\left(2x-15\right)^2=1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=15\\2x-15=1;-1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{15}{2}\\2x=16;14\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{15}{2}\\x=8;7\end{cases}}\)

\(\Rightarrow\left(2x-15\right)^5=\left(2x-15\right)^3=0\)

\(\Rightarrow\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)

\(\Leftrightarrow\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x-15=0\\\left(2x-15\right)^2=1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=15\\2x-15=1;-1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=7,5\\x=8;7\end{cases}}\)

a) \(4x+4=16\)

\(4x=12\)

\(x=3\)

b) \(34\left(2x-6\right)=0\)

\(2x=6\)

\(x=3\)

c) \(15:x=5\)

\(x=15:5=3\)

d) \(20-\left(x+14\right)=5\)

\(x+14=20-5=15\)

\(x=15-14=1\)

a) \(4x+4=16\)

\(\Rightarrow4x=16-4\)

\(\Rightarrow4x=12\)

\(\Rightarrow x=\dfrac{12}{4}\)

\(\Rightarrow x=3\)

b) \(34\cdot\left(2x-6\right)=0\)

\(\Rightarrow2x-6=\dfrac{0}{36}\)

\(\Rightarrow2x-6=0\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=\dfrac{6}{2}\)

\(\Rightarrow x=3\)

c) \(15:x=5\)

\(\Rightarrow x=15:5\)

\(\Rightarrow x=3\)

d) \(20-\left(x+14\right)=5\)

\(\Rightarrow x+14=20-5\)

\(\Rightarrow x+14=15\)

\(\Rightarrow x=15-14\)

\(\Rightarrow x=1\)

Vì 15:5=3 mà X:5<15:5=3 nên:

X:5=0;1;2<3

=>X=0(Loại) vì (15-0).79>(15-2).79

=>X=5 hoặc X=10 thỏa mãn đ k đề bài đã cho.

Đ s :X=5 và X=10

cảm ơn nhung cau lam sai roi

k minh minh giai cho

Ggh

Nếu x > 0

\(\Rightarrow\hept{\begin{cases}|2x-5|=2x-5\\|2x-15|=2x-15\end{cases}}\)

\(\Leftrightarrow2x-5+2x-15=10\)

\(\Leftrightarrow4x=30\)

\(\Leftrightarrow x=\frac{15}{2}\)

Nếu x < 0

\(\Rightarrow\hept{\begin{cases}|2x-5|=-2x+5\\|2x-15|=-2x+15\end{cases}}\)

\(\Leftrightarrow-2x+5-2x+15=10\)

\(\Leftrightarrow-4x=-10\)

\(\Leftrightarrow x=\frac{5}{2}\)

Vậy...

\(\Rightarrow20-4x=10\) với x\(\ge\)\(\frac{5}{2}\)

\(\Rightarrow4x=10\)

\(\Rightarrow x=\frac{5}{2}\)(t/m)

\(\Rightarrow-10=10\) (loại) với \(\frac{5}{2}< x< \frac{15}{2}\)

\(\Rightarrow4x-10=10\)với x\(\le\frac{15}{2}\)

\(\Rightarrow4x=20\Rightarrow x=5\)

Vậy x=...........

Hok tốt

a. 2^x - 15 = 17

2^x =17+15

2^x =32

x=8

b,{7x . 11}³ = 2⁵ .5² +200

=>{7x . 11}³= 32.25+200

=>{7x . 11}³= 800+200

=>{7x . 11}³=1000

VÌ 10³ =1000=> 7x.11=10

\(7x=\frac{10}{11}\)

=> x=\(\frac{10}{77}\)  

c, x¹⁰ =1^x

=> x=1

d,x¹⁰=1

=>x=1

e,2x-15=1

=>2x=1+15

2x=16

=>x=8

a. 2^x - 15 = 17

    2^x         = 17 + 15

    2^x         =     32

=> x = ⁵

Vậy : 2⁵ - 15 = 17

ai giúp minh đi cần quá gấp