B. 1800

Chon B

-18.43+18.143=0

(92-1332+45)-(45+92)=-1.195-137=-135,805‬

#hungb

\(-18\cdot43+18\cdot143\)

\(=18\cdot\left(-43\right)+18\cdot143\)

\(=18\cdot\left[\left(-43\right)+143\right]\)

\(=18\cdot100=1800\)

\(\left(92-1332+45\right)-\left(45+92\right)\)

\(=92-1332+45-45-92\)

\(=\left(92-92\right)+\left(45-45\right)-1332\)

\(=0+0-1332=0-1332\)

\(=-1332\)

Gọi công thức thủy tinh là: \(aK_2O.bCaO.cSiO_2\)

\(a:b:c=\dfrac{18,43}{94}:\dfrac{10,98}{56}:\dfrac{70,59}{60}=1:1:6\)

Loại thủy tính đã cho có dạng \(K_2O.CaO.6SiO_2\)

Sửa đề:

13².181 - 5².181 + 144.19

= 169.181 - 25.181 + 144.19

= 181.(169 - 25) + 144.19

= 181.144 + 144.19

= 144.(181 + 19)

= 144.200

= 28800

\(13^2\cdot181-5^2:181+144\cdot19\)

\(=169\cdot181-25:181+144\cdot19\)

\(=30589-\dfrac{25}{181}+2736\)

\(=30588,86188+2736\)

\(=33324,86188\)

   $-(181 + 72 - 5) + (95 - 181 + 72)$

$=-181 - 72 + 5 + 95 - 181 + 72$

$= (-181 -181) + (72 - 72) + (5 + 95)$

$= -362 + 100 = -262$.

\(\left(2017-\dfrac{5}{181}+\dfrac{1}{50}\right)-\left(4+\dfrac{3}{181}-\dfrac{2}{50}\right)+\left(1-\dfrac{8}{181}+\dfrac{3}{50}\right)\)

\(=2017-\dfrac{5}{181}+\dfrac{1}{50}-4-\dfrac{3}{181}+\dfrac{2}{50}+1-\dfrac{8}{181}+\dfrac{3}{50}\)

\(=2014+\dfrac{143}{4525}\)

\(=\dfrac{9113493}{4525}\)

\(181+111=292\)

tong la 292 k nheđào ngọc minh

181 + 111 = 292

x=2

181 + (26 - 3x) : 5 = 185

(26 - 3x) : 5 = 185 - 181

(26 - 3x) : 5 = 4

(26 - 3x) = 5 x 4

(26 - 3x) = 20

3x = 26 - 20

3x = 6

x = 6 : 3

x = 2

=> (26-3x):5=4

=> 26-3x=20

=> 3x=6

=>x=2

Đáp án C

\(-359+181+(-123)+350+(-172)\\=(-359+350)+[181+(-172)] +(-123)\\=-9+9-123\\=-123\)

359+181+(−123)+350+(−172)

=(−359+350)+[181+(−172)]+(−123)

=−9+9−123

=−123