Phần trong ngoặc.........phân tích cơ số ra thừa số nguyên tố:

\(125^3\cdot7^5-175^5:5=\left(5^3\right)^3\cdot7^5-\left(5^2\cdot7\right)^5:5=5^9\cdot7^5-5^9\cdot7^5=0\)

1) ( 125³ . 7⁵ - 175⁵ : 5 ) : 2016²⁰¹⁷ = 0: 2016^2017 = 0 

2)

a)5* 3^x = 8*3^9 + 8* 27^3 

3^x = 59049

x=10

1) = 0

2) a = 10

b) khó qá bn ạk

mk chẳng hiểu đề lắm

nha bn

5.\(3^x\) = 8.3⁹ + 7.27³

5.\(3^x\) = 8.3⁹ + 7.(3³)³

5.\(3^x\) = 8.3⁹   + 7.3⁹

5.\(3^x\)  = 3⁹.( 8 + 7)

5.\(3^x\)  = 3⁹. 15

    \(3^x\) = 3⁹.15:5

     \(3^x\) = 3⁹.3

       \(3^x\)= 3¹⁰

        \(x\) = 10

Vậy \(x\) = 10 

Câu b

\(5\cdot3^x=8\cdot3^9+7\cdot27^3\)

\(\Leftrightarrow5\cdot3^x=8\cdot3^9+7\cdot\left(3^3\right)^3\)

\(\Leftrightarrow5\cdot3^x=8\cdot3^9+7\cdot^9\)

\(\Leftrightarrow5\cdot3^x=15\cdot3^9\)

\(\Leftrightarrow3^x=3\cdot3^9=3^{10}\)

Vậy \(x=10\)

#kido

a. 37-7.(x+1)=40-8.3

37 - 7(x+1) = 16 

7(x+1) = 21

x+1 = 3

x=2

b. (x+5).3=11=10+(3+4).4

(sao có 2 dấu bằng, dấu nào là dấu cộng do viết nhầm ???)

c. 25-5.3+4.10=100-5.x

50 = 100 - 5x 

5x = 50

x=10

d. 36+2.(x-7)=12+8.(3+5)-36

36 + 2(x-7) = 40

2(x-7) = 4

x-7 =2

x=9

e. 3.(x+7)-9=11.5-5-8

3(x+7) - 9 = 42 

3(x+7) = 51

x+7 = 17 

x=10

5.3x = 8.310 - 3.310 

<=> 5.3x = ( 8-3 ) . 310

<=> 5.3x = 5 .310 

<=>    x = 10 

a. 5x3^x= 8x19683+7x19683

    5x3^x=(8+7)x19683

   5x3^x=15x19683

   5x3^x= 295245

   3^x=295245:5

       =59049

3^x= 3^10

vậy x=10

d.x-32=0:45

  x-32=0

  x=0+32

  x=32

sắp hết giờ rồi.............huhuhu

*** \(\dfrac{15-x}{8}=\dfrac{x-23}{10}\)

\(\Rightarrow10\left(15-x\right)=8\left(x-23\right)\)

\(\Rightarrow150-10x=8x-184\)

\(\Rightarrow150+184=10x+8x\)

\(\Rightarrow18x=334\)

\(\Rightarrow x=\dfrac{167}{9}\)

*** \(\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(-\dfrac{1}{2}\right).\left(2015\right)^0\)

\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(-\dfrac{1}{2}\right).1\)

\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(-\dfrac{1}{2}\right)\)

\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(-\dfrac{1}{2}\right)\)

\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|=\left(-\dfrac{1}{2}\right)+3\dfrac{2}{5}\)

\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|=\dfrac{29}{10}\)

\(\Rightarrow\left|2x-1\right|=\dfrac{29}{10}:\dfrac{1}{2}\)

\(\Rightarrow\left|2x-1\right|=\dfrac{29}{5}\)

\(\Rightarrow\left[{}\begin{matrix}2x-1=\dfrac{29}{5}\\2x-1=-\dfrac{29}{5}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{34}{5}\\2x=-\dfrac{24}{5}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{17}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)