(x+1) + (x+2) + ... + (x+211) = 23632

(x+x+x+...+x+x) + (1+2+3+...+211) = 23632  (211 số x)

x x 211 + 22366 = 23632

x x 211 = 23632 - 22366 =1266

x = 1266:211

x = 6

(\(x\) + 1) + (\(x\) + 2) + ... + (\(x\) + 211) = 23632

Xét dãy số: 1; 2;...; 211

Dãy số trên là dãy số cách đều với khoảng cách là:

2 - 1 = 1

Số số hạng của dãy số trên là:

(211 - 1) : 1 + 1 = 211

Vậy ta có:

211 \(\times\) \(x\) + (211 + 1) \(\times\) 211 : 2 = 23632

211 \(\times\) \(x\) + 22366   = 23632

211 \(\times\) \(x\)               = 23632 - 22366

211 \(\times\) \(x\)               = 1266

           \(x\)               =  6 

( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 210 ) + ( x + 211 ) = 23632

x + 1 + x + 2 + x +3 + .... + x + 210 + x + 211 = 23632

( x + x + x + .... + x ) + ( 1 + 2 + 3 + ... + 210 + 211 ) = 23632

211x + 22366 = 23632

             211x  = 23632 - 22366

             211x  = 1266

=> x = 1266 : 211 = 6

Vậy x = 6

ta có (x+1) + (x+2) + (x+3) + ... + (x+210) + (x+211) = 23632

     = X + ( 1 + 2 +3 + 4 + .... + 210 + 211 ) = 23632

     = X + ( 1 + 211 ) + ( 2 + 210 ) + .... =23632

     = X + 212 x 105 =23632

     = X + 22260 = 23632

     = X          = 23632 - 22260

     = X          = 1372

Thiếu đề hả bạn

Trả lời:

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+211\right)=0\)

\(\Leftrightarrow\left(x+x+...+x\right)+\left(1+2+...+211\right)=0\)

\(\Leftrightarrow211x+\left(211+1\right)\times\left[\left(211-1\right)\div1+1\right]\div2=0\)

\(\Leftrightarrow211x+212\times211\div2=0\)

\(\Leftrightarrow211x+22366=0\)

\(\Leftrightarrow211x=-22366\)

\(\Leftrightarrow x=-106\)

Vậy \(x=-106\)

lớp 5 nha bạn 

e) (x + 1) + (x + 2) + .... + (x + 211) = 23632 

   (x + x + .... + x) + (1 + 2 + ... + 211) = 23632 

  211x + 22366 = 23632 

  211x = 23632 - 22366 

  211x = 1266

=> x= 6 

f) (1 + 3 + 5 + 7 + .... + 2009) + x = 1010026 

Số số hạng của 1 + 3 + 5 + 7 + .... + 2009 là: (2009 - 1) : 2 + 1 = 1005

Tổng của 1 + 3 + 5 +... + 2009 là: (1 + 2009) x 1005 : 2 = 1010025

Ta được : 1010025 + x = 1010026 

             => x = 1010026 - 1010025 = 1 

các bạn giúp mình làm bài 8 đi

Bài 8:

( 752248-752248) : ( 2+4+6+...+200)

0 : ( 2+4+6+200)=0

Chúc bạn hok tốt nha!

a)

(x*211)+(1+2+...+211)=23632

(x*211)+22366=23632

x*211=23632-22366

x*211=1266

x=1266:211

x=6

Vậy x=6

( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 210 ) + ( x + 211 ) = 23632

x + 1 + x + 2 + x +3 + .... + x + 210 + x + 211 = 23632

( x + x + x + .... + x ) + ( 1 + 2 + 3 + ... + 210 + 211 ) = 23632

211x + 22366 = 23632

             211x  = 23632 - 22366

             211x  = 1266

=> x = 1266 : 211 = 6

Vậy x = 6

\(1,\frac{1212}{1515}+\frac{1212}{3535}+\frac{1212}{6363}+\frac{1212}{9999}=\frac{12}{15}+\frac{12}{35}+\frac{12}{63}+\frac{12}{99}=6\left(\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}\right)=6\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right).Tacocongthuc:\frac{1}{n}-\frac{1}{n+k}=\frac{k}{n\left(n+k\right)}\Rightarrow\frac{1212}{1515}+\frac{1212}{3535}+\frac{1212}{6363}+\frac{1212}{9999}=6\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-.....-\frac{1}{11}\right)=6\left(\frac{1}{3}-\frac{1}{11}\right)=\frac{48}{33}=\frac{16}{11}\)

\(2,\left(x+1\right)+\left(x+2\right)+.....+\left(x+211\right)=211x+\left(1+2+....+211\right)=211x+\frac{212.211}{2}=211x+22366=23632\Leftrightarrow211x=23632-22366=1266\Leftrightarrow x=6\)

a, \(14:\left(4\frac{2}{3}:1\frac{5}{9}\right)+14:\left(\frac{2}{3}+\frac{8}{9}\right)\)

=> \(14:\frac{28}{9}+14:\frac{14}{9}=>14.\frac{9}{28}+14.\frac{9}{14}\)

=> 14. ( \(\frac{9}{28}+\frac{9}{14}\) )

=> \(14.\frac{27}{28}=\frac{419}{28}\)

b, \(\frac{1212}{1515}+\frac{1212}{3535}+\frac{1212}{6363}+\frac{1212}{9999}\)

=> \(\frac{4}{5}+\frac{12}{35}+\frac{4}{21}+\frac{4}{33}\)

=> \(\frac{8}{7}+\frac{24}{77}=\frac{16}{11}\)

bài 2 :

( x + 1 ) + ( x + 2 ) + ... + ( x + 211 ) = 23632

=> ( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 211 ) = 23632

=> 211x + 22366 = 23632

=> 211x = 23632 - 22366

=> 211x = 1266

=> x = 1266 : 211

x = 6

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+214\right)=23632\)

\(\Rightarrow\left(x+x+.....+x\right)+\left(1+2+....+214\right)=23632\)

\(\Rightarrow214x+23005=23632\)

\(\Rightarrow214x=627\)

\(\Rightarrow x=\frac{627}{214}\)

a) \(\dfrac{5}{8}-\left(x+\dfrac{3}{4}\right)=\dfrac{7}{6}\)

     \(-x-\dfrac{3}{4}=\dfrac{13}{24}\)

    \(-x=\dfrac{31}{24}\)

\(\Rightarrow x=\dfrac{-31}{24}\)

b) \(\left(x-\dfrac{3}{4}\right)+\dfrac{3}{2}=\dfrac{11}{3}\)

    \(x-\dfrac{3}{4}=\dfrac{13}{6}\)

    \(x=\dfrac{35}{12}\)

c) \(\left(x+\dfrac{1}{2}\right)-\dfrac{5}{8}=2\)

    \(x+\dfrac{1}{2}=\dfrac{21}{8}\)

    \(x=\dfrac{17}{8}\)

d) \(\dfrac{11}{2}-\left(\dfrac{4}{5}+x\right)=2-\dfrac{1}{3}\)

    \(\dfrac{11}{2}-\left(\dfrac{4}{5}+x\right)=\dfrac{5}{3}\)

    \(-\dfrac{4}{5}-x=\dfrac{-23}{6}\)

    \(-x=\dfrac{-91}{30}\)

\(\Rightarrow x=\dfrac{91}{30}\)