a,3/4 . (-5/12)+3/4.(-7/12)

` 3/4 . [ - ( 5/12 + 7/12  ) ] `

`3/4 . (-1) = -3/4 `

`2/3 . x - 0,5 = 3/4 `

`        x - 0,5 = 3/4 - 2/3 `

`        x-0,5 = 1/12 `

`        x =       1/12 + 0,5 `

`        x= 7/12 `

a, 3/4 . (-5/12)+3/4.(-7/12) 

= 3/4 . [(-5/12) + (-7/12)]

= 3/4 . (-1)

= -3/4

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a, 2/3 .x-0,5=3/4

2/3 . x = 3/2 + 0,5

2/3 . x = 2 

x = 2 : 2/3

x = 3 

vậy x = 3

Bài 2:

a: =>2/3x=3/4+1/2=3/4+2/4=5/4

=>x=5/4:2/3=5/4*3/2=15/8

b:=>-2x+4=3x-12

=>-5x=-16

=>x=16/5

Bài 1: 

a) Ta có: \(\dfrac{17}{6}-x\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)

\(\Leftrightarrow\dfrac{17}{6}-x^2+\dfrac{7}{6}x-\dfrac{7}{4}=0\)

\(\Leftrightarrow-x^2+\dfrac{7}{6}x+\dfrac{13}{12}=0\)

\(\Leftrightarrow-12x^2+14x+13=0\)

\(\Delta=14^2-4\cdot\left(-12\right)\cdot13=196+624=820\)

Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:

\(\left\{{}\begin{matrix}x_1=\dfrac{14-2\sqrt{205}}{-24}=\dfrac{-7+\sqrt{205}}{12}\\x_2=\dfrac{14+2\sqrt{2015}}{-24}=\dfrac{-7-\sqrt{205}}{12}\end{matrix}\right.\)

b) Ta có: \(\dfrac{3}{35}-\left(\dfrac{3}{5}-x\right)=\dfrac{2}{7}\)

\(\Leftrightarrow\dfrac{3}{5}-x=\dfrac{3}{35}-\dfrac{10}{35}=\dfrac{-7}{35}=\dfrac{-1}{5}\)

hay \(x=\dfrac{3}{5}-\dfrac{-1}{5}=\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)

ai giúp mik vs

Bài 3: 

a) Ta có: \(2x-3=x+\dfrac{1}{2}\)

\(\Leftrightarrow2x-x=\dfrac{1}{2}+3\)

\(\Leftrightarrow x=\dfrac{7}{2}\)

b) Ta có: \(4x-\left(x+\dfrac{1}{2}\right)=2x-\left(\dfrac{1}{2}-5\right)\)

\(\Leftrightarrow3x-\dfrac{1}{2}-2x+\dfrac{1}{2}-5=0\)

\(\Leftrightarrow x=5\)

a) y : 4/11 x 3/5 = 27/4

y : 4/11 = 27/4 : 3/5

y : 4/11 = 45/4

y = 45/4 x 4/11

y = 45/11

b) y + 7/2 - 5/9 = 14/3

y + 7/2 = 14/3 + 5/9

y + 7/2 = 47/9

y = 47/9 - 7/2

y = 31/18

a) y : 4/11 x 3/5 = 27/4

y : 4/11 = 27/4 : 3/5

y : 4/11 = 45/4

y = 45/4 x 4/11

y = 45/11
b) y + 7/2 - 5/9 = 14/3

y + 7/2 = 14/3 + 5/9

y + 7/2 = 47/9

y = 47/9 - 7/2

y = 31/18

\(\)a) \(y\) : \(\dfrac{4}{11}\) x \(\dfrac{3}{5}\) \(=\) \(\dfrac{27}{4}\)                   b) \(y\) \(+\) \(\dfrac{7}{2}\) \(-\) \(\dfrac{5}{9}\) \(=\) \(\dfrac{14}{3}\)

    \(y\) : \(\dfrac{4}{11}\)        \(=\) \(\dfrac{27}{4}:\dfrac{3}{5}\)                 \(y\) \(+\) \(\dfrac{7}{2}\)          \(=\) \(\dfrac{14}{3}\) \(+\) \(\dfrac{5}{9}\) 

    \(y\) : \(\dfrac{4}{11}\)        \(=\) \(\dfrac{45}{4}\)                       \(y\) \(+\) \(\dfrac{7}{2}\)           \(=\) \(\dfrac{47}{9}\)

    \(y\)                \(=\) \(\dfrac{45}{4}\) x \(\dfrac{4}{11}\)              \(y\)                    \(=\) \(\dfrac{47}{9}-\dfrac{7}{2}\)

    \(y\)                \(=\) \(\dfrac{45}{11}\)                      \(y\)                     \(=\) \(\dfrac{31}{18}\)

`c)1/4x+2/5=7/5`

`=>1/4x=7/5-1/5=1`

`=>x=1:1/4=4`

Vậy `x=4` 

`a)2x-2/3=-3/4`

`=>2x=-3/4+2/3=-1/12`

`=>x=-1/24`

Vậy `x=-1/24`

`b)x:3/4+1/4=-2/3`

`=>x:3/4=-2/3-1/4=-11/4`

`=>x=-11/4 xx 3/4=-33/16`

Vậy `x=-33/16`

a.1/8+3/8=1/2

b.2/5-1/8=11/40

a, `1/2`

b, `11/40`

1/2

11/40

A nhé

Chọn A

Bài 4:

a) \(\dfrac{x}{2}=\dfrac{2}{4}\)

\(\Rightarrow\dfrac{x}{2}=\dfrac{1}{2}\)

\(\Rightarrow x=2\)

Vậy: \(x=2\)

b) \(-\dfrac{1}{5}=\dfrac{2}{x}\)

\(\Rightarrow x=\dfrac{-5.2}{1}=-10\)

Vậy: \(x=-10\)

c) \(\dfrac{x}{5}=\dfrac{5}{x}\)

\(\Rightarrow x^2=25\)

\(\Rightarrow\left[{}\begin{matrix}x=5\\x=-5\end{matrix}\right.\)

Vậy: \(x\in\left\{5;-5\right\}\)

\(\dfrac{x}{2}=\dfrac{2}{4}\\ =>x=\dfrac{2.2}{4}=1\)

\(\dfrac{-1}{5}=\dfrac{2}{x}\\ =>x=\dfrac{2.5}{-1}=-10\)

\(\dfrac{x}{5}=\dfrac{5}{x}\\ =>x^2=25\\ x=5;x=-5\)

a) 2

b) 5,-5

a: Ta có: \(P=\dfrac{\sqrt{x}+1}{\sqrt{x}-2}+\dfrac{2\sqrt{x}}{\sqrt{x}+2}+\dfrac{5\sqrt{x}+2}{4-x}\)

\(=\dfrac{x+3\sqrt{x}+2+2x-4\sqrt{x}-5\sqrt{x}-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)

\(=\dfrac{3x-6\sqrt{x}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)

\(=\dfrac{3\sqrt{x}}{\sqrt{x}+2}\)

b: Để P=2 thì \(3\sqrt{x}=2\sqrt{x}+4\)

hay x=16