2x - 2³. 3³ = 138

2x - 8 . 27  = 138

2x - 216     = 138

2x              = 138 + 216

2x              = 354

2x              = 354 : 2

 x               = 177

vậy x = 177

( 6x - 3⁴ ) . 7³    = 3 . 7⁴

( 6x - 81 ) . 343  = 3 . 2401

( 6x - 81 ) . 343  = 7203

  6x - 81            = 7203 : 343

  6x - 81            = 21

  6x                   = 21 + 81

  6x                   = 102

    x                   = 102 : 6

    x                   = 17

vậy x = 17

\(2x-2^3.3^2=138\)

\(2x-8.9=138\)

\(2x-72=138\)

\(2x=138+72\)

\(2x=210\)

\(x=210:2\)

\(x=105\)

\(\left(6x-3^4\right).7^3=3.7^4\)

\(\left(6x-3^4\right)=3.7^4:7^3\)

\(\left(6x-3^4\right)=3.7\)

\(6x-81=21\)

\(6x=21+81\)

\(6x=102\)

\(x=102:6\)

\(x=17\)

\(27+\left(220-6x\right).3=615\)

\(\rightarrow\left(220-6x\right).3=615-27=588\)

\(\rightarrow220-6x=588:3=196\)

\(\rightarrow6x=220-196=24\)

\(\rightarrow x=24:6=4\)

\(315-\left(x-3\right).7=210\)

\(\Rightarrow\left(x-3\right).7=315-210=105\)

\(\Rightarrow x-3=105:7=15\)

\(\Rightarrow x=15+3=18\)

Trả lời

a)27+(220-6x)3=615

         (220-6x)3=615-27

         (220-6x)3=588

          220-6x   =588:3

          220-6x   =196

                  6x  =220-196

                  6x  =24

                =>x  =24:6

                =>x  =4

b)315-(x-3)7=210

          (x-3)7=315-210

          (x-3)7 =105

           x-3    =105:7

          x-3    =15

           x      =15+3

           x      =18

c)1302-(2x+421)=503

              2x+421 =1302-503

              2x+421 =799

              2x         =799-421

              2x         =378

                x         =378:2

                x         =189

d)609(5x)=12

          5x =609:12

          5x =50,75

            x =10,15

Ta có :

\(\dfrac{5\left(3.7^{15}-19.7^{14}\right)}{7^6+3.7^{15}}\)

\(=\dfrac{5.7^6\left(3.7^9-19.7^8\right)}{7^6\left(1+3.7^9\right)}\)

\(=\dfrac{5.7^8\left(3.7-19\right)}{1+3.7^9}\)

\(=\dfrac{5.7^8.2}{1+3.7^9}\)

\(=\dfrac{10.7^8}{1+3.7^8.7}\)

\(=\dfrac{10.7^8}{1+7^8.21}\)

\(\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}=\frac{5.2.7^{14}}{10.7^{15}}=\frac{1}{7}\)

Đặt P= \(\dfrac{2.5^{22}-9.5^{21}}{25^{10}}\) : \(\dfrac{5.\left(3.7^{15}-19.7^{14}\right)}{\left(7^{16}+3.7^{15}\right)}\)

Có : \(\dfrac{2.5^{22}-9.5^{21}}{25^{10}}\)

= \(\dfrac{\left(2.5-9\right).5^{21}}{\left(5^2\right)^{10}}\)= \(\dfrac{\left(10-9\right).5^{21}}{5^{20}}\)=\(\dfrac{5^{21}}{5^{20}}\)= 5 (1)

Có: \(\dfrac{5.\left(3.7^{15}-19.7^{14}\right)}{\left(7^{16}+3.7^{15}\right)}\)

= \(\dfrac{5.\left[7^{14}.\left(3.7-19\right)\right]}{\left[7^{15}.\left(3+7\right)\right]}\)=\(\dfrac{5.7^{14}.2}{7^{15}.10}\)=\(\dfrac{10.7^{14}}{7^{15}.10}\)=\(\dfrac{1}{7}\) (2)

Từ (1) và (2) suy ra:

A= 5:\(\dfrac{1}{7}\)=5.7=35

Vậy A=35 hay \(\dfrac{2.5^{22}-9.5^{21}}{25^{10}}\):\(\dfrac{5.\left(3.7^{15}-19.7^{14}\right)}{\left(7^{16}+3.7^{15}\right)}\)= 35

\(P=\dfrac{2.5^{22}-9.5^{20}}{25^{10}}:\dfrac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)

\(=\dfrac{5^{20}\left(2.5^2-9\right)}{5^{20}}:\dfrac{5.7^{14}\left(3.7-19\right)}{7^{15}\left(7+3\right)}\)

\(=\left(2.5^2-9\right):\dfrac{5\left(3.7-19\right)}{7.10}\)

\(=\dfrac{7.10\left(2.5^2-9\right)}{5\left(3.7-19\right)}\)

\(=\dfrac{7.2\left(2.5^2-9\right)}{3.7-19}\)

\(=\dfrac{14.41}{21-19}\)

\(=\dfrac{14}{2}\cdot41=7.41=287\)

a)4.(x+3)-(2x-12)=x-(-11+4)

4x+12-2x+12=x+11-4

2x+24=x+7

2x-x=-24+7

x=-17

b)-(4x-13)+(5x-4)=-3-(-15+7)

-4x+13+5x-4=-3+15-7

(-4x+5x)+13-4=12-7

x+9=5

x=-4

c)(5x-3)-(-2x+4)=6x-12

5x-3+2x-4=6x-12

5x+2x-6x=3+4-12

x=-5

d)(15x+20)-(9x-3)=5x-(-12)

15x+20-9x+3=5x+12

15x-9x-5x=-20-3+12

x=-11

e,(7x+14)+(3x-8)=-(-9x+3)

7x+14+3x-8=9x-3

7x+3x-9x=-14+8-3

x=-9

điêu thế 2 không thể bằng 3

2 ko bao giờ bằng 3 đc nha bạn!