Làm hộ bài 6🤡
🤡 🤡 🤡
Cứu mình với
Tìm x thuộc N
a) 2x chia hết cho 4x+82
b) x+30 là bội của x+4
Hứa ai làm nhanh mà đầy đủ sẽ tíck
Con gái đã nói là sẽ làm 🤡🤡
làm hộ em bài 6
Bài 6:
\(34,075;34,175;34,257;37,303\)
Làm hộ em bài 6
`21 km //h = 21 000 m // 60 phút `
`= 350m // phút `
Làm hộ mình bài 6 ạ
1 She failed to do everything she was supposed to do
2 There is no likelihood that anyone will apply for this post
3 He succeeded in finishing the English test in time
4 There is no likelihood that the situation will improve in the near future
5 There is a chance that you will get what you want there
6 Don't check your answers before answering all the questions
7 I won't give an opinion before thinking this through
8 The judge will decide after hearing all the evidence
9 I won't be able to have a holiday until I save enough money
10 There is little likelihood that my sister will win the first prize in the singing contest
11 He made no reference of his new job when I last spoke to him
1 She failed to do everything she was supposed to do
2 There is no likelihood that anyone will apply for this post
3 He succeeded in finishing the English test in time
4 There is no likelihood that the situation will improve in the near future
5 There is a chance that you will get what you want there
6 Don't check your answers before answering all the questions
7 I won't give an opinion before thinking this through
8 The judge will decide after hearing all the evidence
9 I won't be able to have a holiday until I save enough money
10 There is little likelihood that my sister will win the first prize in the singing contest
11 He made no reference of his new job when I last spoke to him
làm câu d bài 6 hộ
\(2x^3+5x^2-3x=0\Leftrightarrow x\left(2x^2+5x-3\right)=0\Leftrightarrow x\left(2x-1\right)\left(x+3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\\x=-3\end{matrix}\right.\)
làm hộ bài 6 câu c
b: \(\Leftrightarrow8\left(1-3x\right)-2\left(3x+2\right)=140-15\left(2x+1\right)\)
=>8-24x-6x-4=140-30x-15
=>-30x+30x=115-4=111
=>0x=111(vô lý)
Ai làm hộ mình bài 6 với
làm bài 6 hộ mik với SoS
a)
f(x) + h(x) = g(x)
\( \Rightarrow x^4 - 3x^2 + x-1 \) + h(x) = \(x^4 - x^3 + x^2 +5\)
\(\Rightarrow \) h(x) = \(( x^4 - x^3 + x^2 + 5 ) - ( x^4 - 3x^2 + x-1 )\)
\(\Rightarrow \) h(x) = \(x^4 - x^3 + x^2 + 5 - x^4 + 3x^2 - x +1\)
\(\Rightarrow\) h(x) = \(( x^4-x^4 ) + ( -x^3 ) + ( x^2 + 3x^2 ) + ( 5+1)\)
\(\Rightarrow\) h(x) = \(4x^2 - x^3 +6\)
Vậy h(x) = \(4x^2 - x^3 +6\)
b) f(x) - h(x) = g(x)
\(\Rightarrow \) \(x^4 - 3x^2 +x-1\) - h(x) = \(x^4 - x^3 + x^2-1\)
\(\Rightarrow\) h(x) = \((x^4 - 3x^2 +x-1)\) - \((x^4 - x^3 + x^2 +5 )\)
\(\Rightarrow\) h(x) = \(x^4 - 3x^2 + x-1 - x^4 + x^3 - x^2 - 5\)
\(\Rightarrow\) h(x) = \(( x^4-x^4 ) + x^3 + ( -3x^2 - x^2 ) + ( -1-5 )\)
\(\Rightarrow\) h(x) = \(x^3 - 4x^2 -6\)
Vậy h(x) = \(x^3 - 4x^2 -6\)