Question

làm bài 6 hộ mik với SoS

Answer 1

a)

f(x) + h(x) = g(x) 

\( \Rightarrow x^4 - 3x^2 + x-1 \) + h(x) = \(x^4 - x^3 + x^2 +5\)

\(\Rightarrow \) h(x) = \(( x^4 - x^3 + x^2 + 5 ) - ( x^4 - 3x^2 + x-1 )\)

\(\Rightarrow \) h(x) = \(x^4 - x^3 + x^2 + 5 - x^4 + 3x^2 - x +1\)

\(\Rightarrow\) h(x) = \(( x^4-x^4 ) + ( -x^3 ) + ( x^2 + 3x^2 ) + ( 5+1)\)

\(\Rightarrow\) h(x) = \(4x^2 - x^3 +6\)

Vậy h(x) = \(4x^2 - x^3 +6\)

Answer 2

b) f(x) - h(x) = g(x)

\(\Rightarrow \) \(x^4 - 3x^2 +x-1\) - h(x) = \(x^4 - x^3 + x^2-1\)

\(\Rightarrow\) h(x) = \((x^4 - 3x^2 +x-1)\) - \((x^4 - x^3 + x^2 +5 )\)

\(\Rightarrow\) h(x) = \(x^4 - 3x^2 + x-1 - x^4 + x^3 - x^2 - 5\)

\(\Rightarrow\) h(x) = \(( x^4-x^4 ) + x^3 + ( -3x^2 - x^2 ) + ( -1-5 )\)

\(\Rightarrow\) h(x) = \(x^3 - 4x^2 -6\)

Vậy h(x) = \(x^3 - 4x^2 -6\)