a) $4P + 5O_2 \xrightarrow{t^o} 2P_2O_5$

b) $Mg + Cl_2 \xrightarrow{t^o} MgCl_2$

c) $2Na + 2H_2O \to 2NaOH + H_2$

d) $C + O_2 \xrightarrow{t^o} CO_2$

e) $C_xH_y + (x + \dfrac{y}{4})O_2 \xrightarrow{t^o} xCO_2 + \dfrac{y}{2}H_2O$

f) $2Al + Fe_2O_3 \xrightarrow{t^o} Al_2O_3 + 2Fe$
g) $2Al + 3H_2SO_4 \to Al_2(SO_4)_3 + 3H_2$

i) $Fe_xO_y + yCO \xrightarrow{t^o} xFe + yCO_2$

k) $Fe_2O_3 + 6HCl \to 2FeCl_3 +3 H_2O$

l) $3Fe + 2O_2 \xrightarrow{t^o} Fe_3O_4$

\(6KOH+Fe_2\left(SO_4\right)_3\rightarrow3K_2SO_4+2Fe\left(OH\right)_3\left(6:1:3:2\right)\)

\(2KNO_3\rightarrow2KNO_2+O_2\left(2:2:1\right)\)

\(2Al+3CuCl_2\rightarrow2AlCl_3+3Cu\left(2:3:2:3\right)\)

\(P_2O_5+3H_2O\rightarrow2H_3PO_4\left(1:3:2\right)\)

a: \(2Ca+O_2->2CaO\)

b: \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

a) 2Ca + O₂  -> 2CaO

b) 2Al + 3H₂SO₄ -> Al₂(SO₄)₃ + 3H₂

c) Fe₃O₄ + 4H₂ -> 3Fe + 4H₂O

a, 2Al+3H₂SO₄\(\rightarrow\)Al₂SO₄+3H₂

c. 2Fe+3Cl₂\(\rightarrow\)2FeCl₃

b. 2NaOH+ZnCl₂\(\rightarrow\).Zn(OH)₂+2NaCl

d. 3Fe+2O₂\(\rightarrow\)Fe₃O₄

\(\cdot2Al+3H_2SO_4\xrightarrow[]{}Al_2\left(SO_4\right)_3+3H_2\)

\(\cdot2NaOH+ZnCl_2\xrightarrow[]{}Zn\left(OH\right)_2+2NaCl\)

\(\cdot2Fe+3CL_2\xrightarrow[]{}2FeCl_3\)

\(\cdot3Fe+2O_2\xrightarrow[]{}Fe_3O_4\)

\(a,3Fe+O_2\rightarrow Fe_3O_4\)

\(b,Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(c,Al_2\left(SO_4\right)_3+6NaOH\rightarrow2Al\left(OH\right)_3+3Na_2SO_4\)

\(d,CaCO_3+2HCl\rightarrow CaCl_2+CO_2+H_2O\)

\(a,2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ 2:3:1:3\\ b,2Na+2H_2O\to 2NaOH+H_2\\ 2:2:2:1\\ c,4NH_3+5O_2\buildrel{{t^o,xt}}\over\to 4NO+6H_2O\\ 4:5:4:6\\ d,2KMnO_4+16HCl\to 2KCl+2MnCl_2+5Cl_2+8H_2O\\ 2:16:2:2:5:8\)

\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\) (phản ứng thế) 
\(2KClO_3\underrightarrow{t^o,xtMnO_2}2KCl+3O_2\) (phản ứng phân hủy ) 
\(4P+5O_2\underrightarrow{t^o}2P_2O_5\)(phản ứng hóa hợp)

a, `2Al + 3H_2SO_4 -> Al_2(SO_4)_3 + 3H_2`.

`=>` Phản ứng thế.

b, `2KClO_3 -> 2KCl + 3O_2`

`=>` Phản ứng phân hủy,

c, `4P + 5O_2 -> 2P_2O_5`.

`=>` Phản ứng hóa hợp.

Cân bằng các phương trình hóa học theo các sơ đồ phản ứng sau:

a)10 Al + 36HNO₃  ---> 10Al(NO₃) + 3N₂ + 18H₂O

b) 2AL + 2Ba(OH)₂ + H_2O  ---> Ba(AlO₂)₂ + 3H₂

c) 3Fe(OH)₂ + 10HNO₃ ---> 3Fe(NO₃)₃ + NO + 8H₂O

d) MnO₂ + 2FeSO₄ + 2H₂SO₄  ---> Fe₂(SO₄)₃ + MnSO₄ + 2H₂O