\(2^x:4=32\\ \Rightarrow2^x=128\\ \Rightarrow2^x=2^7\\ \Rightarrow x=7\)

\(3^{x-2}:3=243\\ \Rightarrow3^{x-2}=729\\ \Rightarrow3^{x-2}=3^6\\ \Rightarrow x-2=6\\ \Rightarrow x=8\)

\(256:4^{x+1}=4^2\\ \Rightarrow4^{x+1}=4^2\\ \Rightarrow x+1=2\\ \Rightarrow x=1\)

\(4^{2x-1}:4=4^4\\ \Rightarrow4^{2x-1}=4^5\\ \Rightarrow2x-1=5\\ \Rightarrow x=3\)

\(5^{x-1}:5=5^3\\ \Rightarrow5^{x-1}=5^4\\ \Rightarrow x-1=4\\ \Rightarrow x=5\)

\(3^{2x+1}:3=3^4\\ \Rightarrow3^{2x+1}=3^5\\ \Rightarrow2x+1=5\\ \Rightarrow x=3\)

1: =>\(5^{x-2}-9=2^4-\left(6^2-6^2\right)\)

=>\(5^{x-2}=16+9=25\)

=>x-2=2

=>x=4

2: \(\Leftrightarrow3^x+16=19^6:19^5-3=19-3=16\)

=>3^x=0

=>x=0

3: \(\Leftrightarrow2^x+2^x\cdot16=272\)

=>2^x*17=272

=>2^x=16

=>x=4

4: \(\Leftrightarrow2^{x-1}+3=24-\left(4^2-2^2+1\right)=24-\left(16-4+1\right)\)

=>\(2^{x-1}+3=24-16+4-1=8+4-1=12-1=11\)

=>2^x-1=8

=>x-1=3

=>x=4

1: \(=6x^2+2x-15x-5-x^2+6x-9+4x^2+20x+25-27x^3-27x^2-9x-1\)

=-27x^3-18x^2+4x+10

2: =4x^2-1-6x^2-9x+4x+6-x^3+3x^2-3x+1+8x^3+36x^2+54x+27

=7x^3+37x^2+46x+33

5:

\(=25x^2-1-x^3-27-4x^2-16x-16-9x^2+24x-16+\left(2x-5\right)^3\)

\(=8x^3-60x^2+150-125+12x^2-x^3+8x-60\)

=7x^3-48x^2+8x-35

1) 2x – (3 – 5x) = 4( x +3)

<=>2x-3+5x=4x+12

<=>2x-3+5x-4x-12=0

<=>3x-15=0

<=>x=5

2) 5(2x-3) - 4(5x-7) =19 - 2(x+11)

<=>10x-15-20x+28=19-2x-22

<=>10x-15-20x+28-19+2x+22=0

<=>-8x+16=0

<=>x=2

tham khảo

1) 2x – (3 – 5x) = 4( x +3)

<=>2x-3+5x=4x+12

<=>2x-3+5x-4x-12=0

<=>3x-15=0

<=>x=5

2) 5(2x-3) - 4(5x-7) =19 - 2(x+11)

<=>10x-15-20x+28=19-2x-22

<=>10x-15-20x+28-19+2x+22=0

<=>-8x+16=0

<=>x=2

`1/3 : (2x - 1) = (-4/24)`

`2x - 1 = 1/3 : (-4/24)`

`2x - 1 = -2`

`2x = (-2) + 1`

`2x = (-1)`

`x = 2 : (-1)`

`x = -2`

\(\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-4}{24}\)

        \(2x-1=\dfrac{1}{3}:\left(\dfrac{-4}{24}\right)\)

        \(2x-1=-2\)

        \(2x=\left(-2\right)+1\)

         \(2x=-1\)

           \(x=2:\left(-1\right)\)

           \(x=-2\)

vậy x =...

1) \(-6x^4+4x^3-2x^2\)

2) \(=x^2+4x-21-x^2-4x+5=-16\)

3) \(=6x^2-4x-x^2-4x-4=5x^2-8x-4\)

4) \(=2x^3-4x^2-8x-3x^2+6x+12=2x^3-7x^2-2x+12\)

giúp mình với

\(3.\left(2x-3\right).\left(1+x\right)-2.\left(3x-1\right).\left(x+4\right)=24\)

\(\Leftrightarrow6x+6x^2-9-9x-6x^2-24x+2x+8=24\)

\(\Leftrightarrow-25x-1=24\)

\(\Leftrightarrow-25x=25\)

\(\Leftrightarrow x=-1\)

Vậy \(x=-1\) ( làm hơi tắt xíu nha !! )

\(\dfrac{3}{4}\left(2x-5\right)+\dfrac{1}{6}=\dfrac{5}{24}\\ \Rightarrow\dfrac{3}{4}\left(2x-5\right)=\dfrac{1}{24}\\ \Rightarrow2x-5=\dfrac{1}{18}\\ \Rightarrow2x=\dfrac{91}{18}\\ \Rightarrow x=\dfrac{91}{36}\)

15/16 . -7/13 + 15/16 . -6/13 -1/16