\(3^4\)

\(9^2\)

\(2^6\)

\(10^8\)

3⁴

9²

2⁶

10⁸

a) 3⁴

b) 9²

c) 2⁶

d) 10⁸

^{k mik nha}

^{học tốt !}

`@` `\text {Ans}`

`\downarrow`

`a)`

`16^3 = (4^2)^3 = 4^6` 

`b)`

`25^6 = (5^2)^6 = 5^12`

`c)`

`81^5 = (9^2)^5 = 9^10`

`d)`

`27^5 = (3^3)^5 = 3^15`

`e)`

`64^3*16^3`

`= (4^3)^3*(4^2)^3`

`= 4^9*4^6`

`= 4^15`

_____

`@` Nâng lên lũy thừa

CT: `(a^m)^n=a^m*a^n = a^(m*n)`

\(a.\) \(81=3\cdot3\cdot3\cdot3=3^4\)

\(b.\) \(81=9\cdot9=9^2\)

\(c.\) \(64=2\cdot2\cdot2\cdot2\cdot2\cdot2=2^6\)

\(d.\) \(100000000=10\cdot10\cdot10\cdot10\cdot10\cdot10\cdot10\cdot10=10^8\)

a) 81=3.3.3.3 ta đc 3⁴

b) 81=9.9 ta đc 9²

c) 64=2.2.2.2.2.2 ta đc 2⁶

d)100 000 000=10.10.10.10.10.10.10.10=10⁸

a,81=3^4

b,81=9^2

c,64=2^6

d,100000000=10^8

9=3²

27=3³

81=3⁴

729=3⁶

3*9*27*81*729=3*3²*3³*3⁴*3⁶=3^1+2+3+4+6=3¹⁶

Phần còn lại làm tương tự kết quả là 5¹⁰*57

3.9.27.81.729 = 3.3.3.3.3.3.3.3.3.3.3.3.3.3.3.3 = 3¹⁶

5.25.125.625.57 = 5.5.5.5.5.5.5.5.5.5.57 = 5¹⁰.57

64=2^6

128=2^7

125=5^3

625=5^4

81=3^4

243=3^5

1024=2^10

64=2⁴

128=2⁷

125=5³

625=5⁴

81=3⁴

243=3⁵

1024=2¹⁰

2^6 => 64

2^7 => 128

5^3=>125

5^4 => 625

3^4 => 81

3^5 => 243

2^10 => 1024

K NHA

Bài 6: 

a: \(2^{27}=8^9\)

\(3^{18}=9^9\)

b: Vì \(8^9< 9^9\)

nên \(2^{27}< 3^{18}\)

Ta có: +) \({({2^2})^3} = {2^2}{.2^2}{.2^2} = {2^{2 + 2 + 2}} = {2^6}\)

+) \({\left[ {{{( - 3)}^2}} \right]^2} = {( - 3)^2}.{( - 3)^2} = {( - 3)^{2 + 2}} = {( - 3)^4}\)

a) 8 = 2³

42⁵ = 2⁵.3⁵.7⁵

16 = 2⁴

b) (0,09)³ = (3/10)⁶

(3/10)⁸ = (3/10)⁸

0,027 = (3/10)³

`@` `\text {Ans}`

`\downarrow`

`a)`

`8 = 2^3`

`32^5` chứ ạ?

`32^5 = (2^5)^5 = 2^10`

`16 = 2^4`

`b)`

`(0,09)^3 = (0,3^2)^3 = 0,3^6` hay `(3/10)^6`

`(3/10)^8 = (3/10)^8`

`(0,027) = (0,3)^3` hay `(3/10)^3`

`@` `\text {Kaizuu lv uuu}`

a) 2.2.2.2 = \({2^4}\). Cơ số 2, số mũ 4

b) 5.5.5 = \({5^3}\). Cơ số 5, số mũ 3