Ta có \(\frac{9}{25}x+\frac{3}{5}.\frac{9}{25}x+\frac{3}{5}.18+\frac{9}{25}x+18=x\)

=> \(\frac{9}{25}x\left(1+\frac{3}{5}+1\right)+18\left(\frac{3}{5}+1\right)=x\)

=> \(\frac{117}{125}x+28,8=x\)

=> \(x-\frac{117}{125}x=28,8\)

=> \(\frac{8}{125}x=28,8\)

=> x = 450

Vậy x = 450

\(\frac{9}{25}x+\frac{3}{5}.\frac{9}{25}x+\frac{3}{5}.18+\frac{9}{25}x+18=x\)

\(x\left(\frac{9}{25}+\frac{9}{25}+\frac{9}{25}\right).\frac{3}{5}+\frac{3}{5}.18+18=x\)

\(x.\frac{3}{5}\left(\frac{27}{25}+18\right)+18=x\)

\(x.\frac{3}{5}\left(\frac{27}{25}+\frac{450}{25}\right)+18=x\)

\(x.\frac{3}{5}.\frac{477}{25}+18=x\)

\(x.\frac{1431}{125}+\frac{2250}{125}=x\)

\(x.\frac{3681}{125}=x\)

vậy chac tui làm sai rồi

= 2/5

= 1/15

\(\dfrac{1}{9}\times\dfrac{18}{5}=\dfrac{2}{5}\)

\(\dfrac{3}{25}:\dfrac{9}{5}=\dfrac{3}{25}\times\dfrac{5}{9}=\dfrac{1}{15}\)

a, = 18/45 = 2/5

b, = 3/25 x 5/9 = 15/225 = 1/15

Thay \(x=-4\) vào pt elip ta được:

\(\frac{y^2}{9}=1-\frac{16}{25}=\frac{9}{25}\Rightarrow\left[{}\begin{matrix}y=\frac{9}{5}\\y=-\frac{9}{5}\end{matrix}\right.\)

\(\Rightarrow MN=2.\frac{9}{5}=\frac{18}{5}\)

a: \(=\dfrac{18}{51}\cdot\dfrac{34}{9}\cdot\dfrac{17}{18}=\dfrac{17}{51}\cdot\dfrac{34}{9}=\dfrac{1}{3}\cdot\dfrac{34}{9}=\dfrac{34}{27}\)

b: \(=\dfrac{21}{32}\cdot\dfrac{4}{7}\cdot25\cdot\dfrac{4}{5}=\dfrac{21}{7}\cdot\dfrac{4}{32}\cdot20=60\cdot\dfrac{1}{8}=\dfrac{15}{2}\)

\(\Leftrightarrow3^x\cdot82=3^{50}+3^{54}\)

hay x=50

9x9+25x9+33+18
=3x27+75x3+3x11+3x6
=3x﴾27+75+11+6﴿
=3x139
=417

ủng hộ nha e nguyen hai Yen

đáp án: 357 ( tính máy tính )

k nha

bạn xem lại đề 

\(a,\left(-12\right).1125.\left(-9\right).\left(-5\right).3=-1822500< 0\)

\(b,21.\left(-25\right).\left(-6\right).\left(-3\right).18.\left(-2022\right)=343942200>0\)

a: 9-25=7-x-(25+7)

=>7-x-25-7=-16

=>-x-25=-16

=>x+25=16

hay x=-9

b: \(10+2\left|x\right|=2\cdot\left(3^2-1\right)\)

\(\Leftrightarrow2\left|x\right|=2\cdot8-10=6\)

=>x=3 hoặc x=-3

c: -6x=18

nên x=18:(-6)=-3

\(b)\frac{9}{5}.x=\frac{18}{25}\)

\(\Rightarrow x=\frac{18}{25}\div\frac{9}{5}=\frac{18}{25}.\frac{5}{9}\)

\(\Rightarrow x=\frac{2}{5}\)

\(e)x-20\%.x=2,5\)

\(\Rightarrow x.\left(1-\frac{1}{5}\right)=\frac{5}{2}\)

\(\Rightarrow x.\frac{4}{5}=\frac{5}{2}\)

\(\Rightarrow x=\frac{5}{2}\div\frac{4}{5}=\frac{25}{8}\)

b) \(\frac{9}{5}\). x = \(\frac{18}{25}\)

               x = \(\frac{18}{25}\): \(\frac{9}{5}\)

               x = \(\frac{2}{5}\)

e) x - 20% . x = 2,5

1 . x - \(\frac{1}{5}\). x = \(\frac{5}{2}\)

x . ( 1- \(\frac{1}{5}\)) = \(\frac{5}{2}\)

x . \(\frac{4}{5}\)= \(\frac{5}{2}\)

x = \(\frac{5}{2}\): \(\frac{4}{5}\)

x = \(\frac{25}{8}\)

=^_^=

h mình nha