7.(x+9)-3.(5-x)=98
7.(x+9)-3.(5-x)=98
Lời giải:
$7(x+9)-3(5-x)=98$
$\Leftrightarrow 7x+63-15+3x=98$
$\Leftrightarrow 10x+48=98$
$\Leftrightarrow 10x=50$
$\Leftrightarrow x=5$
\(7\times\left(x+9\right)-3\times\left(5-x\right)=98\)
\(7x+63-15+3x=98\)
\(10x+48=98\)
\(10x=98-48\)
\(10x=50\)
\(x=5\)
Vậy: \(x=5\)
Tính giá trị biểu thức :
C = 1 / 3 - 3 / 5 + 5/7 - 7/ 9 + 9 /11 - 11 / 13 + 13 / 15 + 11/ 13 - 9 /11 + 7 / 9
D = 1/99 - 1 /99 x 98 - 1 / 98 x 97 - 1 /97 x 96 - ........ - 1 / 3x 2 - 1/ 2 x 1
Tính giá trị biểu thức :
A = ( 3 - 1 / 4 + 2 /3 ) - ( 5 1/3 - 6/5 ) - ( 6 - 7/4 + 3 /2 )
B = 1 / 3 - 3 / 4 - ( -3/ 5 ) + 1 /64 - 2 / 9 - 1 /36 + 1 / 15
C = 1 / 3 - 3 / 5 + 5/7 - 7/ 9 + 9 /11 - 11 / 13 + 13 / 15 + 11/ 13 - 9 /11 + 7 / 9
D = 1/99 - 1 /99 x 98 - 1 / 98 x 97 - 1 /97 x 96 - ........ - 1 / 3x 2 - 1/ 2 x 1
hơi bị khó... chờ mình ghi lại để hỏi cô!!!
Tính giá trị biểu thức :
A = ( 3 - 1 / 4 + 2 /3 ) - ( 5 1/3 - 6/5 ) - ( 6 - 7/4 + 3 /2 )
B = 1 / 3 - 3 / 4 - ( -3/ 5 ) + 1 /64 - 2 / 9 - 1 /36 + 1 / 15
C = 1 / 3 - 3 / 5 + 5/7 - 7/ 9 + 9 /11 - 11 / 13 + 13 / 15 + 11/ 13 - 9 /11 + 7 / 9
D = 1/99 - 1 /99 x 98 - 1 / 98 x 97 - 1 /97 x 96 - ........ - 1 / 3x 2 - 1/ 2 x 1
A = ( 4/4 + 2/3 ) - ( 51/3 - 6/5 ) - ( 6 - 7/4 + 3/2 )
Sau đó quy đồng rồi trừ cả là đc
B tương tự
C=13/15
D cx thế . Bạn tự vận dụng đi . Xl vì ko giải đc . Mik đang gấp
Tính giá trị biểu thức :
A = ( 3 - 1 / 4 + 2 /3 ) - ( 5 1/3 - 6/5 ) - ( 6 - 7/4 + 3 /2 )
B = 1 / 3 - 3 / 4 - ( -3/ 5 ) + 1 /64 - 2 / 9 - 1 /36 + 1 / 15
C = 1 / 3 - 3 / 5 + 5/7 - 7/ 9 + 9 /11 - 11 / 13 + 13 / 15 + 11/ 13 - 9 /11 + 7 / 9
D = 1/99 - 1 /99 x 98 - 1 / 98 x 97 - 1 /97 x 96 - ........ - 1 / 3x 2 - 1/ 2 x 1
Giải đc câu nào thì giải hộ mình nhé ! ko nhất thiết phải giải hết
Tìm x:
a, (12/25)^x = (5/3)^2 - (-3/5)^4
b, 172^2 x - 7^9 : 98^3= 2^-3
1. x - 8 +32= 68
2. x +8+32=68
3. 98-x +34=43
4. 98+x-34=43
5. x :5:4=800
6. 18+x=384:8
7. (84,6-2 x x):3,02= 5,1
8. x x5= 120:6
9. (15x 24-x) :0,25= 100:0,25
1. \(x-8+32=68\)
\(x-8=68-32\)
\(x-8=36\)
\(x=36+8\)
\(x=44\)
_____
2. \(x+8+32=68\)
\(x+8=68-32\)
\(x+8=36\)
\(x=36-8\)
\(x=28\)
_____
3. \(98-x+34=43\)
\(98-x=43-34\)
\(98-x=9\)
\(x=98-9\)
\(x=89\)
_____
4. \(98+x-34=43\)
\(98+x=43+34\)
\(98+x=77\)
\(x=77-98\)
\(x=-21\)
_____
5. \(x:5:4=800\)
\(x:5=800.4\)
\(x:5=3200\)
\(x=3200.5\)
\(x=16000\)
_____
6. \(18+x=384:8\)
\(18+x=48\)
\(x=48-18\)
\(x=30\)
_____
7. \(\left(84,6-2\times x\right):3,02=5,1\)
\(84,6-2.x=5,1.3,02\)
\(84,6-2.x=15,402\)
\(2.x=84,6-15,402\)
\(2.x=69,198\)
\(x=69,198:2\)
\(x=34,599\)
_____
8. \(x\times5=120:6\)
\(x.5=20\)
\(x=20:5\)
\(x=4\)
_____
9. \(\left(15\times24-x\right):0,25=100:0,25\)
\(\left(15.24-x\right):0,25=400\)
\(15.24-x=400.0,25\)
\(15.24-x=100\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
1,x-8+32=68
=>x-8=68-32=36
=>x=36+8=42
2,x+8+32=68
=>x+8=68-32=36
=>x=36-8=28
3,98-x+34=43
=>98-x=43-34=9
=>x=98-9=89
4,98+x-34=43
=>98+x=43+34=77
=>x=77-98=-21
5,x:5:4=800
=>x:20=800
=>x=800x20=16000
6,18+x=384:8=48
=>x=48-18=30
7,(84,6-2x):3,02=5,1
=>84,6-2x=5,1x3,02=15,402
=>2x=84,6-15,402=69,198
=>x=69,198:2=34,599
8,5x=120:6=20
=>x=20:5=4
9,(15x24-x):0,25=100:0,25=400
=>360-x=400x0,25=100
=>x=360-100=260.
1. \(...\Rightarrow x+24=68\Rightarrow x=68-24=44\)
2. \(...\Rightarrow x+40=68\Rightarrow x=68-40=28\)
3. \(...\Rightarrow3^{2\left(8+x\right)}=9=3^2\Rightarrow2\left(8+x\right)=2\Rightarrow8+x=1\Rightarrow x=-7\)
4. \(...\Rightarrow3^{2\left(8+x\right)}=77\) (bạn xem lại đề)
5. \(...\Rightarrow x:5=800.4\Rightarrow x:5=3200\Rightarrow x=3200.5=16000\)
6. \(...\Rightarrow18+x=48\Rightarrow x=48-18=30\)
7. \(...\Rightarrow84,6-2x=5,1.3,02=15,402\Rightarrow2x=84,6-15,402\Rightarrow2x=69,198\Rightarrow x=34,599\)
8. \(...\Rightarrow5.x=20\Rightarrow x=20:5=4\)
9. \(\left(360-x\right):0,25=400\Rightarrow360-x=400.0,25=100\Rightarrow x=400-100=300\)
2 TÌM X BIẾT
a, (5x+1)^2 = 36/49
b, (12/25)^x =(5/3)^2 -(-3/5)^4
c, (-3/4)^ 3x-1 = 256/81
d, 172 .x ^2 -7^9 :98^3 =2^3
e,5^x .(5^3)^2 =625
f, (x-2/9)^3 =(2/3)^6
a)\(\left(5x+1\right)^2=\frac{36}{49}\\ \left(5x+1\right)^2=\left(\frac{6}{7}\right)^2\\ \Rightarrow\left[{}\begin{matrix}5x+1=\frac{6}{7}\\5x+1=\frac{-6}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{-1}{35}\\x=\frac{-13}{35}\end{matrix}\right.\)
vậy...
2.
a) \(\left(5x+1\right)^2=\frac{36}{49}\)
⇒ \(5x+1=\pm\frac{6}{7}\)
⇒ \(\left[{}\begin{matrix}5x+1=\frac{6}{7}\\5x+1=-\frac{6}{7}\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}5x=\frac{6}{7}-1=-\frac{1}{7}\\5x=\left(-\frac{6}{7}\right)-1=-\frac{13}{7}\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}x=\left(-\frac{1}{7}\right):5\\x=\left(-\frac{13}{7}\right):5\end{matrix}\right.\)
⇒ \(\left[{}\begin{matrix}x=-\frac{1}{35}\\x=-\frac{13}{35}\end{matrix}\right.\)
Vậy \(x\in\left\{-\frac{1}{35};-\frac{13}{35}\right\}.\)
Chúc bạn học tốt!
tinh : 1+2-3+4+5+6+7+8+9+...+97+98-99
tim x: 1-|x+1|=-7