a) (1 + x)/(1 - x) + 3 = (3 - x)/(1 - x) b) 1/(2x - 3) - 3/(x(2x - 3)) = 5/x
Những câu hỏi liên quan
Tìm x
a) (2x-5) mũ 2 - (2x+3).(2x-3) = 10
b) (4x-1).(x+2) - (2x+3) mũ 2 - 5.(x-1) = 9
c) (x+1) mũ 3 - (x-1) mũ 3 - 2 = 6
d) (x+2).(x mũ 2 - 2x+4 ) - (x+1).(x mũ 2 - x+1) - 3.(-x-2) = 5
a) \(\left(2x-5\right)^2-\left(2x+3\right)\left(2x-3\right)=10\Leftrightarrow\left(4x^2-20x+25\right)-\left(4x^2-9\right)-10=0\)
\(\Leftrightarrow-20x+24=0\Leftrightarrow x=\frac{6}{5}\)
b) \(\left(4x-1\right)\left(x+2\right)-\left(2x+3\right)^2-5\left(x-1\right)=9\Leftrightarrow-10x-15=0\)
\(\Leftrightarrow x=\frac{-3}{2}\)
c) \(\left(x+1\right)^3-\left(x-1\right)^3-2=6\Leftrightarrow\left(x^3+3x^2+3x+1\right)-\left(x^3-3x^2+3x-1\right)-8=0\)
\(\Leftrightarrow6x^2-6=0\Leftrightarrow x=\pm1\)
d) \(\left(x+2\right)\left(x^2-2x+4\right)-\left(x+1\right)\left(x^2-x+1\right)-3\left(-x-2\right)=5\)
\(\Leftrightarrow\left(x^3+8\right)-\left(x^3+1\right)+3x+6=5\Leftrightarrow3x+8=0\Leftrightarrow x=\frac{-8}{3}\)
giúp mik vs mai mik kiểm tra rùi
a) $\frac{x-1}{x}$ - $\frac{1}{x+1}$ = $\frac{2x-1}{x2+x}$
b) (x+2).(5-3x)=0
c)$\frac{5(1-2x)}{3}$ + $\frac{x}{2}$ = $\frac{3(x-5)}{4}$ - 2
d)$(x+2)^{2}$ - (x-1).(x+3) = (2x-4).(x+4)-3
e)$(2x-3)^{2}$ = (2x-3).(x+1)
a:=>x^2-1-x=2x-1
=>x^2-x-1=2x-1
=>x^2-3x=0
=>x=0(loại) hoặc x=3(nhận)
b:=>x+2=0 hoặc 5-3x=0
=>x=-2 hoặc x=5/3
c:=>20(1-2x)+6x=9(x-5)-24
=>20-40x+6x=9x-45-24
=>-34x+20=9x-69
=>-43x=-89
=>x=89/43
d: =>x^2+4x+4-x^2-2x+3=2x^2+8x-4x-16-3
=>2x^2+4x-19=-2x+7
=>2x^2+6x-26=0
=>x^2+3x-13=0
=>\(x=\dfrac{-3\pm\sqrt{61}}{2}\)
e: =>(2x-3)(2x-3-x-1)=0
=>(2x-3)(x-4)=0
=>x=4 hoặc x=3/2
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Mọi người giúp tới gấp nhé:1. Tìm x, biết:a/ 3(2x - 3) + 2(2 - x) -3b/ 2x(x2 - 2) + x2(1 - 2x) - x2 -122. Tìm x, biết:a/ 3x(2x + 3) - (2x + 5)(3x - 2) 8b/ 4x(x - 1) - 3(x2 - 5) - x2 (x - 3) - (x + 4)c/ 2(3x - 1)(2x + 5) - 6(2x - 1)(x + 2) -6d/ 3(2x - 1)(3x - 1) - (2x - 3)(9x -1) - 3 -3e/ (3x - 1)(2x + 7) - (x + 1)(6x - 5) (x + 2) - (x - 5)f/ 3xy(x + y) - (x + y)(x2 + y2 + 2xy) + y3 273. Chứng minh rằng giá trị của các biểu thức sau không phụ thuộc vào x:a/ A 2x(x - 1) - x(2x + 1) - (3 -...
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Mọi người giúp tới gấp nhé:
1. Tìm x, biết:
a/ 3(2x - 3) + 2(2 - x) = -3
b/ 2x(x2 - 2) + x2(1 - 2x) - x2 = -12
2. Tìm x, biết:
a/ 3x(2x + 3) - (2x + 5)(3x - 2) = 8
b/ 4x(x - 1) - 3(x2 - 5) - x2 = (x - 3) - (x + 4)
c/ 2(3x - 1)(2x + 5) - 6(2x - 1)(x + 2) = -6
d/ 3(2x - 1)(3x - 1) - (2x - 3)(9x -1) - 3 = -3
e/ (3x - 1)(2x + 7) - (x + 1)(6x - 5) = (x + 2) - (x - 5)
f/ 3xy(x + y) - (x + y)(x2 + y2 + 2xy) + y3 = 27
3. Chứng minh rằng giá trị của các biểu thức sau không phụ thuộc vào x:
a/ A = 2x(x - 1) - x(2x + 1) - (3 - 3x)
b/ B = 2x(x - 3) - (2x - 2)(x - 2)
c/ C = (3x - 5)(2x + 11) - (2x + 3)(3x + 7)
d/ D = (2x + 11)(3x - 5) - (2x + 3)(3x + 7)
f/ \(3xy\left(x+y\right)-\left(x+y\right)\left(x^2+y^2+2xy\right)+y^3=27\)
\(3x^2y+3xy^2-\left(x+y\right)\left(x+y\right)^2+y^3=27\)
\(3x^2y+3xy^3-\left(x+y\right)^3+y^3=27\)
\(3x^2y+3xy^3-\left(x^3+3x^2y+3xy^2+b^3\right)+y^3=27\)
\(-x^3=27\)
\(x=-3\)
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Bài 1:
a/ \(3\left(2x-3\right)+2\left(2-x\right)=-3\)
\(6x-9+4-2x=-3\)
\(4x=-2\)
\(x=-\frac{1}{2}\)
b/ \(2x\left(x^2-2\right)+x^2\left(1-2x\right)-x^2=-12\)
\(2x^3-4x+x^2-2x^3-x^2=-12\)
\(-4x=-12\)
\(x=\frac{1}{3}\)
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Bài 2:
a/ \(3x\left(2x+3\right)-\left(2x+5\right)\left(3x-2\right)=8\)
\(6x^2+9x-6x^2-15x+4x+10=8\)
\(-2x=8\)
\(x=-4\)
b/ \(4x\left(x-1\right)-3\left(x^2-5\right)-x^2=\left(x-3\right)-\left(x+4\right)\)
\(4x^2-4x-3x^2+15-x^2=-7\)
\(-4x=-22\)
\(x=\frac{11}{2}\)
c/ \(2\left(3x-1\right)\left(2x+5\right)-6\left(2x-1\right)\left(x+2\right)=-6\)
\(6x-2\left(2x+5\right)-12x+6\left(x+2\right)=-6\)
\(6x-4x-10-12x+6x+12=-6\)
\(-4x=-8\)
\(x=2\)
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Xem thêm câu trả lời
Tìm x
a)(2x-1)^3-(2x-1)^3=-8
b)x(x-2)(x+2)-3(2x-1)^2-2x-5=-6x(x+1) c)(x+1)^3-(x-1)^3-6(x-1)^2=-10
b: \(\Leftrightarrow x^3-4x-3\left(4x^2-4x+1\right)-2x-5=-6x^2-6x\)
\(\Leftrightarrow x^3-4x-12x^2+12x-3-2x-5=-6x^2-6x\)
\(\Leftrightarrow x^3-12x^2+6x-8+6x^2+6x=0\)
\(\Leftrightarrow x^3-6x^2+12x-8=0\)
=>x-2=0
hay x=2
c: \(\Leftrightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6\left(x-1\right)^2=-10\)
\(\Leftrightarrow6x^2+2-6x^2+12x-6=-10\)
=>12x-4=-10
=>12x=-6
hay x=-1/2
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Phân tích các đa thức sau thành nhân tử
a, (x-3)(x-1)-3(x-3)
b, (x-1)(2x+1)+3(x-1)(x+2)(2x+1)
c, (6x+3)-(2x-5)(2x+1)
d, (x-5)^2+(x+5)(x-5)-(5-x)(2x+1)
e, (3x-2)(4x-3)-(2-3x)(x-1)-2(3x-2)(x+1)
\(\left(x-3\right)\left(x-1\right)-3\left(x-3\right)\)
\(=\left(x-3\right)\left(x-1-3\right)\)
\(=\left(x-3\right)\left(x-4\right)\)
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\(\left(x-1\right)\left(2x+1\right)+3\left(x-1\right)\left(x+2\right)\left(2x+1\right)\)
\(=\left(x-1\right)\left(2x+1\right)\left(1+3x+6\right)\)
\(=\left(x-1\right)\left(2x+1\right)\left(3x+7\right)\)
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\(\left(x-5\right)^2+\left(5+x\right)\left(x-5\right)-\left(5-x\right)\left(2x+1\right)\)
\(=\left(x-5\right)^2+\left(5+x\right)\left(x-5\right)+\left(x-5\right)\left(2x+1\right)\)
\(=\left(x-5\right)(x-5+5+x+2x+1)\)
\(=\left(x-5\right)\left(4x+1\right)\)
Còn lại bạn tự làm nhá
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Xem thêm câu trả lời
Tìm x
a) (12x-5)(3x-1)-(18x-1)(2x+3)=5
b) (x+2)(x-3)-(x-2)(x+5)=2(x+3)
c) (2x+3)(2x-1)-(2x+5)-(2x-3)=12
Phân tích đa thức thành nhân tử:
1). (x - 3)(x - 1) - 3(x - 3)
2). (6x + 3) - (2x - 5)(2x + 1)
3). (x - 1)(2x + 1) + 3(x - 1)(x + 2)(2x + 1)
4). (3x - 2)(4x - 3) - (2 - 3x)(x - 1) - 2(3x - 2)(x + 1)
5). \(\left(x-5\right)^2+\left(x+5\right)\left(x-5\right)-\left(5-x\right)\left(2x+1\right)\)
6). (a - b)(a + 2ab) - (b - a)(2a - b) - (a - b)(a + 3b)
\(1,\left(x-3\right)\left(x-1\right)-3\left(x-3\right)\)
\(=\left(x-3\right)\left(x-1-3\right)\)
\(=\left(x-3\right)\left(x-4\right)\)
\(2,6x+3-\left(2x-5\right)\left(2x+1\right)\)
\(=3\left(2x+1\right)-\left(2x-5\right)\left(2x+1\right)\)
\(=\left(2x+1\right)\left(3-2x+5\right)\)
\(=\left(2x+1\right)\left(-2-2x\right)\)
\(3,\left(x-1\right)\left(2x+1\right)+3\left(x-1\right)\left(x+2\right)\left(2x+1\right)\)\(=\left(x-1\right)\left(2x+1\right)\left(1+3x+6\right)\)
\(=\left(x-1\right)\left(2x+1\right)\left(3x+7\right)\)
\(4,\left(3x-2\right)\left(4x-3\right)-\left(2-3x\right)\left(x-1\right)-2\left(3x-2\right)\left(x+1\right)\)\(=\left(3x-2\right)\left(4x-3\right)+\left(3x-2\right)\left(x-1\right)-2\left(3x-2\right)\left(x+1\right)\)\(=\left(3x-2\right)\left(4x-3+x-1-2x-2\right)\)
\(=\left(3x-2\right)\left(3x-6\right)\)
\(5,\left(x-5\right)^2+\left(x+5\right)\left(x-5\right)-\left(5-x\right)\left(2x+1\right)\)\(=\left(x-5\right)^2+\left(x+5\right)\left(x-5\right)+\left(x-5\right)\left(2x+1\right)\)\(=\left(x-5\right)\left(x-5+x+5+2x+1\right)\)
\(=\left(x-5\right)\left(4x+1\right)\)
6, Tương tự
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Bài 1.Tìm x biết
a, 4|3x - 1| + |x| - 2|x-5| + 7|x-3| 12 b, 3|x + 4| - |2x + 1| - 5|x + 3| + |x - 9| 5
c, |x + 5| - |1 - 2x| x d, |x| - |2x + 3| x - 1
e, |x| + |1 - x| x + |x-3| g, |x-2| + |x-5| 3
f, |2x - 1| + |2x - 5| 4 m, |x-3| + |x + 5| 8
n, |x-3| + |3x + 4| |2x + 1|
Các bạn giúp mình nhanh với ạ...
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Bài 1.Tìm x biết
a, 4|3x - 1| + |x| - 2|x-5| + 7|x-3| = 12 b, 3|x + 4| - |2x + 1| - 5|x + 3| + |x - 9| = 5
c, |x + 5| - |1 - 2x| = x d, |x| - |2x + 3| = x - 1
e, |x| + |1 - x| = x + |x-3| g, |x-2| + |x-5| = 3
f, |2x - 1| + |2x - 5| = 4 m, |x-3| + |x + 5| = 8
n, |x-3| + |3x + 4| = |2x + 1|
Các bạn giúp mình nhanh với ạ mình đang cần gấp
Bài 1 : Tìm x, biết
a) 3x(x2 - 2) + x2(1-2x) - x2 = -12
b) 3x(2x +3) - (2x +5)(3x -2) = 8
c)3(3x -1)(2x+5) - 6(2x -1)(x+2) = -6
d) 3(2x -1)(3x - 1)- (2x -3)(9x -1) - 3 = -3
e) 4x(x-1)- 3(x2 -5)- x2 = (x-3)(x+4)
f) (3x-1)(2x+7)-(x+1)(6x-5)= (x+2)-(x-5)
tck đầu tiên chọn câu trả lời của mình đi