10.3/4+3.4/5
`(3^{4}.4-3^{6})/(3^{5}.5+10.3^{4}`
tính hợp lý ( nếu có thể )
( đang lừi tính :") , giải ra nha)
\(=\dfrac{3^4.\left(4-9\right)}{3^4\left(15+10\right)}=-\dfrac{5}{25}=-\dfrac{1}{5}\)
\(=\dfrac{3^4\left(4-9\right)}{3^4\left(5.3+10\right)}=-\dfrac{5}{25}=-\dfrac{1}{5}\)
tính:M=5^4.9^4-2.6^9/2^10.3^8+6^8.20
Tìm x biết :
4/x=8/6
3/x-5=-4/x+2
X/-2=-8/x
Rút gọn các phân số
2^4.5^2.11^2.7/2^3.5^3.7^2.11
2^10.3^10-2^10.3^9/2^9.3^10
5^11.7^12+5^12.7^11/5^12.7^12+9.5^11.7^11
1. Tìm x, biết:
a) \(\frac{4}{x}=\frac{8}{6}\). Ta có: \(\frac{8}{6}=\frac{8:2}{6:2}=\frac{4}{3}\Rightarrow x=3\)
b) \(\frac{3}{x-5}=\frac{4}{x+2}\). Ta có: \(5-2=3\)
\(\Rightarrow x=\left(3.5\right)+\left(4.2\right)+3=15+8+3=26\)
c) \(\frac{x}{-2}=\frac{-8}{x}\Rightarrow x=\left(-8\right):\left(-2\right)=4\)
2. Rút gọn
a) \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}\Leftrightarrow\frac{2^3.2^1.5^2.11.11.7}{2^3.5^2.5^1.7.7.11}\Leftrightarrow\frac{2^1.11}{5^1.7}=\frac{22}{35}\)
b) Tương tự
c) Tương tự
\(\frac{4}{x}=\frac{8}{6}\Rightarrow x=\frac{4.6}{8}=3\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\Rightarrow3\left(x+2\right)=-4\left(x-5\right)\)
\(\Rightarrow3x+6=-4x+20\)
\(\Rightarrow3x+4x=20-6\)
\(\Rightarrow7x=14\)
\(\Rightarrow x=2\)
\(\frac{x}{-2}=\frac{-8}{x}\Rightarrow x^2=\left(-8\right)\left(-2\right)=16\Rightarrow x=\pm4\)
\(\frac{4}{x}=\frac{8}{6}\)
\(\Rightarrow4\cdot6=x\cdot8\)
\(\Rightarrow x=\frac{4\cdot6}{8}\)
\(\Rightarrow x=3\)
A=2^10.3^10-2^10.3^9/2^9.3^10
B=5^11.7^12+7^11.5^11/5^12.7^12+9.5^11.7^11
a)2^10.3^10:2^10.3^9/2^9.3^10.
b)5^11.7^12+5^11.7^11/5^12.7^12+9.5^11.7^11
Tính
a) A= 1+5+5^2+5^3+.....+5^100
b)B= 1/2+(1/2)^2+(1/2)^3+(1/2)^4+....+(1/2)^99
c)C= (4^5.9^4-2.6^9)/2^10.3^8+6^8.20
a)
\(5A=5+5^2+.....+5^{101}\)
\(\Rightarrow5A-A=\left(5+5^2+.....+5^{101}\right)-\left(1+5+.....+5^{100}\right)\)
\(\Rightarrow4A=5^{101}-1\)
\(\Rightarrow A=\frac{5^{101}-1}{4}\)
b)
\(2B=1+\left(\frac{1}{2}\right)^2+....+\left(\frac{1}{2}\right)^{100}\)
\(\Rightarrow2B-B=\left(1+\frac{1}{2^2}+.....+\frac{1}{2^{100}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+......+\frac{1}{2^{99}}\right)\)
\(\Rightarrow B=1-\frac{1}{2^{100}}\)
Bài 3 (2 điểm): Tìm x
a) 25 – 3.(6 – x) = 22
b) [(2x – 11):3 + 1].5 = 20
c) (25 - 2x) mũ 3 : 5 - 3 mũ 2 = 4 mũ 2
d) 2.3x = 10.3 mũ12 + 8.27 mũ4
Bài 1: tìm x
a) 2^2x.2^4=1024
b) 2.3^x=10.3^12+8.27^4
c) 5^8.25^x+1=5^17
d) 3^x-1+3^x-4=28.243
e) (2x-4)^5=(2x-4)^3
a) \(2^{2x}.2^4=1024\)
\(2^{2x}=1024:2^4\)
\(2^{2x}=1024:16\)
\(2^{2x}=64\)
\(2^{2x}=2^6\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
vay \(x=3\)
b) \(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=2.5.3^{12}+2^3.\left(3^3\right)^4\)
\(2.3^x=2.5.3^{12}+2^3.3^{12}\)
\(2.3^x=2.3^{12}.\left(5+2^2\right)\)
\(2.3^x=2.3^{12}.9\)
\(2.3^x=2.3^{12}.3^2\)
\(2.3^x=2.3^{14}\)
\(\Rightarrow x=14\)
vay \(x=14\)
c) \(5^8.25^x+1=5^{17}\)
\(5^8.\left(5^2\right)^x+1=5^{17}\)
\(5^8.5^{2x}+1=5^{17}\)
\(5^{8+2x}=5^{17}-1\)
e) \(\left(2x-4\right)^5=\left(2x-4\right)^3\)
\(\left(2x-4\right)^5-\left(2x-4\right)^3=0\)
\(\left(2x-4\right)\left[\left(2x-4\right)^2-1\right]=0\)
\(\left(2x-4\right)\left(2x-4-1\right)\left(2x-4+1\right)=0\)
\(\left(2x-4\right)\left(2x-5\right)\left(2x-3\right)=0\)
\(\Rightarrow2x-4=0\)hoac \(\orbr{\begin{cases}2x-5=0\\2x-3=0\end{cases}}\)
\(\Rightarrow2x=4\)hoac \(\orbr{\begin{cases}2x=5\\2x=3\end{cases}}\)
\(\Rightarrow x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
vay \(x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
2.6^9-4^5.9^4
------------------
2^10.3^7+6^7.40
\(=\dfrac{2.3^9.2^9-\left(2^2\right)^5.\left(3^2\right)^4}{2^{10}.3^7+3^7.2^7.2^3.5}\\ =\dfrac{2^{10}.3^9-2^{10}.3^8}{2^{10}.3^7+3^7.2^{10}.5}\\ =\dfrac{2^{10}.3^8\left(3-1\right)}{2^{10}.3^7\left(1+5\right)}\\ =\dfrac{3.2}{6}=\dfrac{6}{6}=1\)