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Trần Thị Như
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TV Cuber
11 tháng 5 2022 lúc 20:59

a)\(-\dfrac{2}{3}x^6y^3\)ư

hệ số -2/3 

biến \(x^6y^3\)

b) \(\dfrac{5}{8}x^4y^2\)

hệ số 5/8

biến\(x^4y^2\)

c)\(2x^7y^3\)

hệ số : 2

 biến \(x^7y^3\)

Nguyễn Thụy Mi
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Nguyễn Phương Uyên
8 tháng 7 2019 lúc 17:36

a) 2x - 3 = x + 1/2

<=> 2x - 3 = 1/2x + 1/2

<=> 2x - 3 - 1/2x = 1/2

<=> 3/2x - 3 = 1/2

<=> 3/2x = 1/2 + 3

<=> 3/2x = 7/2

<=> x = 7/2 : 3/2

<=> x = 7/3

=> x = 7/3

\(a,2x-3=x+\frac{1}{2}\)

\(2x-3=\frac{1}{2}x+\frac{1}{2}\)

\(2x-3-\frac{1}{2}x=\frac{1}{2}\)

\(\frac{3}{2}x-3=\frac{1}{2}\)

\(\frac{3}{2}x=\frac{1}{2}+3\)

\(\frac{3}{2}x=\frac{7}{2}\)

\(x=\frac{7}{2}:\frac{3}{2}\)

\(x=\frac{14}{6}=\frac{7}{3}\)

\(\)B làm tương tự 

Ha
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Đoàn Quỳnh Vy
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Dang Tung
13 tháng 12 2023 lúc 13:46

Đặt x/6 = y/3 = k

=> x=6k và y = 3k

Ta có : xy = 3

=> 18k^2 = 3

=> k^2 = 1/6

=> k = ±√1/6 = ±√6 / 6

Vậy (x;y) = (√6;√6 /2);(-√6;-√6 /2)

Matt De Gea
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Nguyễn Ngọc Huy Toàn
9 tháng 5 2022 lúc 20:38

a.

\(A=B\)

\(\Leftrightarrow\dfrac{x+2}{x-2}-\dfrac{x-2}{x+2}=\dfrac{-16}{x^2-4}\);ĐK:\(x\ne\pm2\)

\(\Leftrightarrow\dfrac{\left(x+2\right)^2-\left(x-2\right)^2}{\left(x-2\right)\left(x+2\right)}=\dfrac{-16}{\left(x-2\right)\left(x+2\right)}\)

\(\Leftrightarrow\left(x+2\right)^2-\left(x-2\right)^2=-16\)

\(\Leftrightarrow x^2+4x+4-x^2+4x-4+16=0\)

\(\Leftrightarrow8x+16=0\)

\(\Leftrightarrow8\left(x+2\right)=0\)

\(\Leftrightarrow x=-2\left(ktm\right)\)

Vậy không có giá trị x thỏa mãn A=B

b.

\(A:B=\dfrac{\left(x+2\right)^2-\left(x-2\right)^2}{\left(x-2\right)\left(x+2\right)}:\dfrac{-16}{\left(x-2\right)\left(x+2\right)}< 0\)

\(\Leftrightarrow\dfrac{x^2+4x+4-x^2+4x-4}{-16}< 0\)

\(\Leftrightarrow\dfrac{8x}{-16}< 0\)

\(\Leftrightarrow\dfrac{8x}{16}>0\)

\(\Leftrightarrow\dfrac{x}{2}>0\)

\(\Leftrightarrow x>0\)

 

 

BÙI BẢO KHÁNH
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Kiều Vũ Linh
14 tháng 10 2023 lúc 14:35

a) 16 = 2⁴

42 = 2.3.7

ƯCLN(16; 42) = 2

ƯC(16; 42) = Ư(2) = {1; 2}

b) 16 = 2⁴

42 = 2.3.7

86 = 2.43

ƯCLN(16; 42; 86) = 2

ƯC(16; 42; 86) = Ư(2) = {1; 2}

c) 25 = 5²

75 = 3.5²

ƯCLN(25; 75) = 5² = 25

ƯC(25; 75) = Ư(25) = {1; 5; 25}

d) 25 = 5²

55 = 5.11

75 = 3.5²

ƯCLN(25; 55; 75) = 5

ƯC(25; 55; 75) = Ư(5) = {1; 5}

6a01dd_nguyenphuonghoa.
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Nguyễn Xuân Thành
9 tháng 8 2023 lúc 20:47

\(\dfrac{x}{9}< \dfrac{4}{7}< \dfrac{x+1}{9}\)

=>\(\dfrac{7x}{63}< \dfrac{36}{63}< \dfrac{7x+7}{63}\)

\(\Rightarrow7x< 36< 7x+7\)

\(\Rightarrow x< \dfrac{36}{7}< x+1\)

\(\Rightarrow x< 5\dfrac{1}{7}< x+1\)

\(\Rightarrow x=5\)

 

Nguyễn Xuân Thành
9 tháng 8 2023 lúc 20:48

tik cho mình nhé

Bùi Linh Chi
10 tháng 8 2023 lúc 5:44

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6a01dd_nguyenphuonghoa.
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\(\dfrac{x}{9}\) < \(\dfrac{4}{7}\) < \(x\) + \(\dfrac{1}{9}\)

\(\dfrac{7x}{63}\) < \(\dfrac{36}{63}\) < \(\dfrac{63x}{63}\) + \(\dfrac{7}{63}\)

7\(x\) < 36 < 63\(x\) + 7

\(\left\{{}\begin{matrix}7x< 36\\63x+7>36\end{matrix}\right.\)\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\63x>36-7\end{matrix}\right.\)\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\63x>29\end{matrix}\right.\)\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\x>\dfrac{29}{63}\end{matrix}\right.\)

\(\dfrac{29}{63}\)<  \(x\) < \(\dfrac{36}{7}\) vì \(x\in\) Z nên \(x\in\) { 1; 2; 3; 4; 5}

⇒ \(\dfrac{x}{9}\) = \(\dfrac{1}{9}\)\(\dfrac{2}{9}\)\(\dfrac{3}{9}\)\(\dfrac{4}{9}\);\(\dfrac{5}{9}\)

 

 

Trần Phương Linh
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