a)  2x-3=-x+6

2x - 3 + x - 6 =0

3x -9 = 0

3x = 9

x = 9 : 3

x= 3

c/ \(\left(-12x-4^3\right).8^3=4.8^4\)

\(\left(-12x-64\right).512=16384\)

\(-12x-64=\dfrac{16384}{512}=32\)

\(-12x=32+64=96\)

\(x=\dfrac{96}{\left(-12\right)}=-8\)

a,   2x-3=-x+6

\(\Leftrightarrow\)2x-3+x-6=0

\(\Leftrightarrow\)3x-9=0

\(\Leftrightarrow\)3x=9

\(\Leftrightarrow\)x=3

a) Ta có: \(2x-3=-x+6\)

\(\Leftrightarrow2x+x=6+3\)

\(\Leftrightarrow3x=9\)

hay x=3

Vậy: x=3

b) Ta có: \(\left|2x-7\right|+2=13\)

\(\Leftrightarrow\left|2x-7\right|=11\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-7=11\\2x-7=-11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=18\\2x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\\x=-2\end{matrix}\right.\)

Vậy: \(x\in\left\{9;-2\right\}\)

c) Ta có: \(\left(-12x-4^3\right)\cdot8^3=4\cdot8^4\)

\(\Leftrightarrow\left(-12x-64\right)=\dfrac{4\cdot8^4}{8^3}=32\)

\(\Leftrightarrow-12x=96\)

hay x=-8

Vậy: x=-8

đơn giản

bn ơi nếu muốn ân smux

thì bn ấn vào chữ X² 

ạ bn viết thế này

mình ko có hiểu

\(a,128-3.\left(x+4\right)=23\\ \Rightarrow3.\left(x+4\right)=105\\ \Rightarrow x+4=35\\ \Rightarrow x=31\\ b,\left[\left(4x+28\right).3+55\right]:5=35\\ \Rightarrow\left(4x+28\right).3+55=175\\ \Rightarrow4x+28.3=120\\ \Rightarrow4x+28=60\\ \Rightarrow4x=32\\ \Rightarrow x=8.\)

c) \(\left(12x-4^3\right).8^3=4.8^4\)

\(12x-64=4.8^4:8^3\)

\(12x-64=32\)

\(12x=32+64\)

\(12x=96\)

\(x=\dfrac{96}{12}\)

\(x=8\)

d) \(720:\left[41-\left(2x-5\right)\right]:5=35\)

\(720:\left(41-2x+5\right):5=35\)

\(720:\left(46-2x\right)=35.5\)

\(720:\left(46-2x\right)=175\)

\(46-2x=720:175\)

\(46-2x=\dfrac{144}{35}\)

\(2x=46-\dfrac{144}{35}\)

\(2x=\dfrac{1466}{35}\)

\(x=\dfrac{1466}{35}:2\)

\(x=\dfrac{733}{35}\)

lm nốt hộ mik 2 ý cuối vs ạ

a  <=>12x-4^3=32

     <=>12x=96

<=>x=8

b,    <=>3x-6=27

       <=>3x=33

       <=>x=11

c,    <=>119-(x-6)=102

       <=>x-6=17

       <=>x=23

hok tot

a) ( 12x - 4³ ) . 8³ = 4.8⁴

=> ( 12x - 4³ ) : 4 = 8⁴ : 8³

=> ( 12x - 4³ ) : 4 = 8

=> 12x - 4³ = 8 . 4

=> 12x - 64 = 32

=> 12x = 96

=> x = 8

b) ( 3x - 6 ) . 3 = 3⁴

=> ( 3x - 6 ) = 3⁴ : 3¹

=> 3x - 6 = 3³

=> 3x - 6 = 27

=> 3x = 33

=> x = 11

c) 2448 : [ 119 - ( x - 6 ) ] = 24

=> 119 - ( x - 6 ) = 102

=> x - 6 = 7

=> x = 13

a,

128-3x-12=23

3x=128-12-23

3x=93

x=93:3

= 31

b,

(12x+84+55):5=35

12x+84+55=35.5

12x+84+55=175

12x=175-55-84

12x=36

x=36:12

x=3

(12x-4³).8³=4.8⁴

=> 12x-4³=4.8⁴:8³

=> 12x-64=4.8

=> 12x-64=32

=> 12x=32+64

=> 12x=96

=> x=96:12

=> x=8

(3x-2⁴).7³=2.7⁴

=> 3x-2⁴=2.7⁴:7³

=> 3x-16=2.7

=> 3x-16=14

=> 3x=14+16

=> 3x=30

=> x=10

2^x+2^x+4=272

=> 2^x.(1+2⁴)=272

=> 2^x.(1+16)=272

=> 2^x.17=272

=> 2^x=16

=> 2^x=2⁴

=> x=4

a/ 5^2x-3- 2. 5²= 5². 3

    5^2x-3- 2. 25= 25. 3

    5^2x-3- 50= 75

    5^2x-3= 75+ 50

    5^2x-3= 125= 5³

    2x- 3= 3

    2x= 3+ 3

    2x= 6

      x= 6: 2

      x= 3

b/ (12x- 4³). 8³= 4. 8⁴

    12x- 64= (4. 8⁴): 8³

    12x- 64= 4. 8= 32

            12x= 32+ 64

            12x= 96

            x= 96: 12

            x= 8

128-3.(x+4) =23                 

        3.(x+4) =128-23

        3.(x+4) = 105

            x+4 =105:3

            x+4 =35

               x = 35-4

               x=31

4.x + 5.x -x =128

\(4^2x+4^2.10=160\)

\(4^2\left(x+10\right)=160\)

\(16\left(x+10\right)=160\)

\(x+10=10\)

\(x=0\)

vay \(x=0\)

\(\left(12x-4^3\right).8^3=4.8^4\)

\(\left(12x-4^3\right).8^3-4.8^4=0\)

\(\left(12x-64\right).8^3-4.8^4=0\)

\(8^3\left(12x-64-32\right)=0\)

\(12x-96=0\)

\(12x=96\)

\(x=8\)

vay \(x=8\)