\(\dfrac{7}{2}\) : \(\dfrac{2}{5}\) = x : \(\dfrac{8}{7}\)

x : \(\dfrac{8}{7}\) = \(\dfrac{7}{2}\) : \(\dfrac{2}{5}\)

x : \(\dfrac{8}{7}\) = \(\dfrac{35}{4}\)

x       = \(\dfrac{35}{4}\) . \(\dfrac{8}{7}\)

x = 10

10

\(\dfrac{7}{2}\)\(:\dfrac{2}{5}\)\(=x:\dfrac{8}{7}\)

\(\dfrac{35}{4}=x:\dfrac{8}{7}\)

\(x=\dfrac{35}{4}:\dfrac{8}{7}=\dfrac{245}{32}\)

Vậy \(x=\dfrac{245}{32}\)
 

 a) \(1\frac{2}{7} = 1 + \frac{2}{7} = \frac{9}{2}\)

\(\begin{array}{l}x:1\frac{2}{7} =  - 3,5\\x:\frac{9}{7} =  - \frac{7}{2}\\x =  - \frac{7}{2}.\frac{9}{7}\\x =  - \frac{9}{2}\end{array}\)

b) \(0,4.x - \frac{1}{5}.x = \frac{3}{4}\)

\(\begin{array}{l}\frac{2}{5}.x - \frac{1}{5}.x = \frac{3}{4}\\\left( {\frac{2}{5} - \frac{1}{5}} \right).x = \frac{3}{4}\\\frac{1}{5}.x = \frac{3}{4}\\x = \frac{3}{4}:\frac{1}{5}\\x = \frac{3}{4}.5\\x = \frac{{15}}{4}\end{array}\)

a) \(x=-\dfrac{3}{5}\times\dfrac{9}{7}=-\dfrac{27}{35}\)

b) \(x\left(0,4-\dfrac{1}{5}\right)=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)

a, \(x=-3,5.\dfrac{9}{7}=-\dfrac{9}{2}\)

b, \(\dfrac{2}{5}x-\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)

x=\(\dfrac{9}{7}x-3.5\)

x=\(\dfrac{-9}{5}\)

a, \(\dfrac{3}{7}\)\(x\) - 0,4 = - \(\dfrac{17}{35}\)

    \(\dfrac{3}{7}\)\(x\)         = - \(\dfrac{17}{35}\) + 0,4

     \(\dfrac{3}{7}\)\(x\)       = - \(\dfrac{3}{35}\)

        \(x\)       = - \(\dfrac{3}{35}\): \(\dfrac{3}{7}\)

        \(x\)       = - \(\dfrac{1}{5}\)

b, 0,2.(\(x\) - 3) +2,4 = 10

    0,2.(\(x\) - 3)          = 10 - 2,4

    0,2.(\(x\) - 3)          = 7,6

           \(x\) - 3            = 7,6:0,2

           \(x\) - 3            = 38

            \(x\)                = 38 + 3

             \(x\)                = 41

\(\dfrac{3}{7}x-0,4=\dfrac{-17}{35}\)

\(\dfrac{3}{7}x=\dfrac{-17}{35}+0,4=\dfrac{-34}{70}+\dfrac{28}{70}\)

\(\dfrac{3}{7}x=\dfrac{-6}{70}=\dfrac{-3}{35}\)

\(x=\dfrac{-3}{35}:\dfrac{3}{7}=\dfrac{-3}{35}\cdot\dfrac{7}{3}\)

\(x=\dfrac{3\cdot\left(-1\right)\cdot7}{5\cdot7\cdot3}=-\dfrac{1}{5}\)

b) \(0,2\left(x-3\right)+2,4=10\)

\(0,2\left(x-3\right)=10-2,4=7,6\)

\(x-3=7,6:0,2=38\)

\(x=38+3=41\)

c) \(\left(x:2,2\right)\cdot\dfrac{1}{6}=\dfrac{-3}{8}\cdot\left(0,5-1\dfrac{3}{5}\right)\)

\(\left(x:2,2\right)\cdot\dfrac{1}{6}=\dfrac{-3}{8}\cdot\dfrac{-11}{10}\)

\(x:2,2=\dfrac{-3}{8}\cdot\dfrac{-11}{10}\cdot\dfrac{6}{1}\)

\(x:2,2=\dfrac{-3\cdot\left(-11\right)\cdot2\cdot3}{2\cdot4\cdot10\cdot1}=\dfrac{99}{40}\)

\(x=\dfrac{99}{40}\cdot2,2=\dfrac{99}{40}\cdot\dfrac{22}{10}\)

\(x=\dfrac{99\cdot2\cdot11}{40\cdot2\cdot5}=\dfrac{1089}{200}\)

B)\(\frac{11}{2}+x=\frac{3}{2}-7\)

\(\frac{11}{2}+x=\frac{3}{2}-\frac{14}{2}\)

\(\frac{11}{2}+x=\frac{-11}{2}\)

\(x=\frac{-11}{2}-\frac{11}{2}\)

\(x=\frac{-22}{2}\)

\(x=-11\)

A)\(\frac{1}{3}x+\frac{2}{5}\left(x+1\right)=0\)

\(\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\)

\(x\cdot\left(\frac{1}{3}+\frac{2}{5}\right)=0-\frac{2}{5}\)

\(x\cdot\left(\frac{5}{15}+\frac{6}{15}\right)=-\frac{2}{5}\)

\(x\cdot\frac{11}{15}=\frac{-2}{5}\)

\(x=\frac{-2}{5}:\frac{11}{5}\)

\(x=\frac{-2}{11}\)

nhớ k cho mình nha

a) 1/3 x + 0,4 ( x + 1 ) = 0

<=>  1/3 x + 0,4 . x + 0,4 . 1 = 0

<=> 1/3 x + 0,4 x + 0,4 = 0

<=> x. ( 1/3 + 0,4 ) + 0,4 = 0 

<=> x. 11/15 + 0.4 = 0

<=> x. 11/15 = -2/5

<=> x = -2/5 : 11/15 = - 6/11

b) 1 1/2 + x = 3/2 -7

<=> 3/2 + x = -11/2

<=> x =  -11/2 - 3/2

<=> x = -7  < GOOD LUCK >

0,4+0,16:x=14:7

0,4+0,16:x=2

0,16:x=2-0,4

0,16:x=1,6

x=0,1

14:(0,4+0,16:x)=7

=> (0,4+0,16:x)=14:7

=>(0,4+0,16:x)=2

=>0,16:x=2-0,4

=> 0,16:x =1,6

=>x= 0,16:1,6

=>x=0,1

14 : ( 0,4 + 0,16 : x) = 7

         0,4 + 0,16 : x = 14 : 7

         0,4 + 0,16 : x = 2

                 0,16 : x = 2 - 0,4

                 0,16 : x = 1,6

                          x =0,16 : 1,6

                          x =0,1

a) Ta có: \(6x\left(x-5\right)+3x\left(7-2x\right)=18\)

\(\Leftrightarrow6x^2-30x+21x-6x^2=18\)

\(\Leftrightarrow-9x=18\)

hay x=-2

Vậy: S={-2}

b) Ta có: \(2x\left(3x+1\right)+\left(4-2x\right)\cdot3x=7\)

\(\Leftrightarrow6x^2+2x+12x-6x^2=7\)

\(\Leftrightarrow14x=7\)

hay \(x=\dfrac{1}{2}\)

Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)

c) Ta có: \(0.5x\left(0.4-4x\right)+\left(2x+5\right)\cdot x=-6.5\)

\(\Leftrightarrow0.2x-2x^2+2x^2+5x=-6.5\)

\(\Leftrightarrow5.2x=-6.5\)

hay \(x=-\dfrac{5}{4}\)

Vậy: \(S=\left\{-\dfrac{5}{4}\right\}\)

d) Ta có: \(\left(x+3\right)\left(x+2\right)-\left(x-2\right)\left(x+5\right)=6\)

\(\Leftrightarrow x^2+5x+6-\left(x^2+3x-10\right)=6\)

\(\Leftrightarrow x^2+5x+6-x^2-3x+10=6\)

\(\Leftrightarrow2x+16=6\)

\(\Leftrightarrow2x=-10\)

hay x=-5

Vậy: S={-5}

e) Ta có: \(3\left(2x-1\right)\left(3x-1\right)-\left(2x-3\right)\left(9x-1\right)=0\)

\(\Leftrightarrow3\left(6x^2-5x+1\right)-\left(18x^2-29x+3\right)=0\)

\(\Leftrightarrow18x^2-15x+3-18x^2+29x-3=0\)

\(\Leftrightarrow14x=0\)

hay x=0

Vậy: S={0}

Tìm y:

\(\frac{Y}{15}=\frac{2}{5}\) => y = 15 x 2/ 5 = 6 

Vậy y = 6 

tk ủng hộ giúp mk nha!!!!!!!!!

y/15=2/5

=>5y=30

y=30:5 

y=6

1/ \(\frac{y}{15}=\frac{2}{5}\Leftrightarrow y=\frac{15\times2}{5}=6\)

2/ \(\frac{3}{y-7}=\frac{27}{135}\)

\(\Leftrightarrow\frac{3}{y-7}=\frac{1}{5}\)

\(\Leftrightarrow y-7=3\times5\)

\(\Leftrightarrow y-7=15\)

\(\Leftrightarrow y=22\)

3/ \(\Leftrightarrow y\times\left(20\%+0,4\right)=12\)

\(\Leftrightarrow y\times\left(\frac{2}{5}+0,2\right)=12\)

\(\Leftrightarrow y\times\frac{3}{5}=12\)

\(\Leftrightarrow y=20\)

PS: Dấu " <=> " mình viết cho đầy đủ thôi chứ bạn không có hiểu. Với cả chỗ tính mình ra kết quả luôn, bạn tự quy đồng nhá