cho x^2 - x = 3 tinh A = x^4 - 2x^3 + 3x^2 -2x +2 GIUP MINH VOI ///??
Những câu hỏi liên quan
a,|x-3| - | 2x-4| = 0
b, |3x-2| = x-1
c, |4-3x| = 2x+1
d, |4-2x| +|x+1| =6
giup minh voi
tinh so huu ti x
2/3x-3/12=4/5-(7/x-2)
2x-3/3+-3/2=5-3x/6-1/3
tim x
(x-1).(x-2)>0
2x-3<0
(2x-4).(9-3x)<0
moi nguoi giup minh nhe cam on nhieu
ai giup mink ba cau nay voi a,|x-5|=|-3x+2| b,|x-5|+|x^2-25|=0 c,|2x-3|+|2x+4|=7
Tinh x
a)3.(2x-1)-x.(3x-2)=3x.(1-x)+2
b)2x3.(2x-3)-x2.(4x2-6x+2)=0
thuc hien phep nhan
(x2+x+1).(x3-x2+1)
giup minh nha thu bay minh nop cho thay roi cam on
a) \(3\left(2x-1\right)-x\left(3x-2\right)=3x\left(1-x\right)+2\)
\(6x-3-3x^2+2x=3x-3x^2+2\)
\(6x-3x^2+2x-3x+3x^2=2+3\)
\(5x=5\)
\(x=1\)
b) \(2x^3\left(2x-3\right)-x^2\left(4x^2-6x+2\right)=0\)
\(4x^4-6x^3-4x^4+6x^2-2x^2=0\)
\(-2x^2=0\)
\(x^2=0\)
\(x=0\)
\(\left(x^2+x+1\right)\left(x^3-x^2+1\right)\)
\(=x^5+x^4+x^3-x^4-x^3-x^2+x^2+x+1\)
\(=x^5+x+1\)
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Phan tich da thuc thanh nhan tu :
a, -x^3 * ( 2x + 1 )^2 + 49x
b, 125x^2 + 20y - 5y^2 - 20
c, ( 1+ 2x )*(1 - 2x ) - x*(x + 2 )*( x - 2 )
d, ( x - z )*(x + z) - y*(2x - y )
e, x^2 - 3x - 54
Giup minh voi nhe cac ban. Minh se tick cho.
a: \(=x\left[49-x^2\left(2x+1\right)^2\right]\)
\(=x\left[49-\left(2x^2+x\right)^2\right]\)
\(=x\left[\left(7-2x^2-x\right)\left(7+2x^2+x\right)\right]\)
b: \(=5\left[25x^2-\left(y^2-4y+4\right)\right]\)
\(=5\left[\left(5x-y+2\right)\left(5x+y-2\right)\right]\)
c: \(=1-4x^2-x\left(x^2-4\right)\)
\(=1-4x^2-x^3+4x\)
\(=\left(1-x\right)\left(1+x+x^2\right)-4x\left(x-1\right)\)
\(=\left(1-x\right)\left(1+x+x^2+4x\right)\)
\(=\left(1-x\right)\left(x^2+5x+1\right)\)
e: =(x-9)(x+6)
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giup mik voi tim x biet
1, 5-(3x+6)>-2x+1
2, -7.(x+2)-3x<6-11x
3, (x+1).(x+2)-x.(x+3)<4-x
4, 6-2x>17+(4-x)
cho P=(2+x/2-x+4x^2/x^2-4-2-x/2+x):x^2-3x/2x^2-x^3
a) tim dieu kien cua x de gia tri cua P xac dinh
b) rut gon P
mn giup minh voi
1 tháng 5 2022 lúc 9:23
cho 2 da thuc :f(x)=3x^3 - 2x^2 + x + 5
g(x)=3x^2 + ax + b
tim a,b sao cho f(x)=(x-1)*g(x)
moi nguoi giai giup em voi
\(f\left(x\right)=\left(x-1\right).g\left(x\right)\)
\(\Rightarrow3x^3-2x^2+x+5=\left(x-1\right)\left(3x^2+ax+b\right)\)
\(\Rightarrow3x^3-2x^2+x+5=3x^3+ax^2+bx-3x^2-ax-b\)
\(\Rightarrow-2x^2+x+5=x^2\left(a-3\right)+x\left(b-a\right)-b\)
-Bạn kiểm tra lại đề.
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cho x,y la so thuc thoa man x3 - y3 = -3xy(y - x)
tinh bieu thuc A= (2x - y)(y - 2x )(x - y)2
moi nguoi giai giup minh voi +_+ huhu
Có: \(x^3-y^3=-3xy\left(y-x\right)\)
\(\Leftrightarrow x^3-y^3=-3xy^2+3x^2y\)
\(\Leftrightarrow x^3-3x^2y+3xy^2-y^3=0\)
\(\Leftrightarrow\left(x-y\right)^3=0\)
\(\Leftrightarrow x-y=0\Leftrightarrow x=y\)
Khi đó bt A trở thành:
\(A=\left(2x-y\right)\left(y-2x\right)\left(y-y\right)^2=\left(2x-y\right)\left(y-2x\right)\cdot0=0\)
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giup minh voi cac ban oi !!!!!!!!!!!!!!!!1
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1, (x+1)2-3(x+1)
2, 2x(x-2) - (x-2)2
3, 4x2-20xy+ 25y2
4, x2+3x-x-3
5, x2-xy+x-y
6, 2y(x+2)-3x-6 giai giup em voi ạ
\(\left(x+1\right)^2-3\left(x+1\right)=\left(x+1\right)\left(x+1-3\right)=\left(x+1\right)\left(x-2\right)\)
\(2x\left(x-2\right)-\left(x-2\right)^2=\left(x-2\right)\left[2x-\left(x-2\right)\right]=\left(x-2\right)\left(2x-x+2\right)=\left(x-2\right)\left(x+2\right)\)
\(4x^2-20xy+25y^2=\left(2x\right)^2-2.2x.5y+\left(5y\right)^2=\left(2x-5y\right)^2\)
\(x^2+3x-x-3=x\left(x+3\right)-\left(x+3\right)=\left(x-1\right)\left(x+3\right)\)
\(x^2-xy+x-y=x\left(x-y\right)+\left(x-y\right)=\left(x-y\right)\left(x+1\right)\)
\(2y\left(x+2\right)-3x-6=2y\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(2y-3\right)\)
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