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Bài 1

a) 3 2/5 - 1/2

= 17/5 - 1/2

= 34/10 - 5/10

= 29/10

b) 4/5 + 1/5 × 3/4

= 4/5 + 3/20

= 16/20 + 3/20

= 19/20

c) 3 1/2 × 1 1/7

= 7/2 × 8/7

= 4

d) 4 1/6 : 2 1/3

= 25/6 : 7/3

= 25/14

Bài 2

a) 3 × 1/2 + 1/4 × 1/3

= 3/2 + 1/12

= 18/12 + 1/12

= 19/12

b) 1 4/5 - 2/3 : 2 1/3

= 9/5 - 2/3 : 7/3

= 9/5 - 2/7

= 63/35 - 10/35

= 53/35

Bài 1

a) 3 2/5 - 1/2

= 17/5 - 1/2

= 34/10 - 5/10

= 29/10

b) 4/5 + 1/5 × 3/4

= 4/5 + 3/20

= 16/20 + 3/20

= 19/20

c) 3 1/2 × 1 1/7

= 7/2 × 8/7

= 4

d) 4 1/6 : 2 1/3

= 25/6 : 7/3

= 25/14

bủh

a )\(A=\frac{x^2+4x+4}{x^2-4}=\frac{\left(x+2\right)^2}{x^2-2^2}=\frac{\left(x+2\right)^2}{\left(x+2\right)\left(x-2\right)}=\frac{x+2}{x-2}=\frac{5}{3}\)

<=> (x + 2).3 = (x - 2).5

<=> 3x + 6 = 5x - 10

<=> 3x - 5x = - 10 - 6

<=> - 2x = - 16

=> x = 8

b ) \(\frac{x+2}{x-2}=\frac{\left(x-2\right)+4}{x-2}=1+\frac{4}{x-2}\)

đến đây tự tìm đc 

Bài 2 lớp 8 ko làm đc thì đi chết đi

\(a,x+\dfrac{1}{4}\times\dfrac{1}{5}=\dfrac{4}{5}\)

\(x+\dfrac{1}{20}=\dfrac{4}{5}\)

\(x=\dfrac{4}{5}-\dfrac{1}{20}\)

\(x=\dfrac{16}{20}-\dfrac{1}{20}\)

\(x=\dfrac{15}{20}=\dfrac{3}{4}\)

\(b,3\dfrac{2}{3}:x=2\dfrac{2}{3}-1\dfrac{1}{2}\)

\(\dfrac{11}{3}:x=\dfrac{8}{3}-\dfrac{3}{2}\)

\(\dfrac{11}{3}:x=\dfrac{7}{6}\)

\(x=\dfrac{11}{3}:\dfrac{7}{6}=\dfrac{22}{7}\)

a: =>x+1/20=4/5

=>x=4/5-1/20=16/20-1/20=15/20=3/4

b: =>11/3:x=8/3-3/2=16/6-9/6=7/6

=>x=11/3:7/6=11/3*6/7=66/21=22/7

a)

`x+1/4xx1/5=4/5`

`x+1/20=4/5`

`x=4/5-1/20`

`x=16/20-1/20`

`x=15/20=3/4`

b)

`3 2/3:x=2 2/3-1 1/2`

`11/3:x=8/3-3/2`

`11/3:x=16/6-9/6`

`11/3:x=7/6`

`x=11/3:7/6`

`x=11/3xx6/7`

`x=22/7`

\(a,x+\dfrac{1}{4}.\dfrac{1}{5}=\dfrac{4}{5}\)

\(\Rightarrow\)\(x+\dfrac{1}{20}=\dfrac{4}{5}\)

\(\Rightarrow x=\dfrac{4}{5}-\dfrac{1}{20}=\dfrac{16}{20}-\dfrac{1}{20}=\dfrac{3}{4}\)

\(b,3\dfrac{2}{3}:x=2\dfrac{2}{3}-1\dfrac{1}{2}\)

\(\Rightarrow\dfrac{11}{3}:x=\dfrac{7}{6}\)

\(\Rightarrow x=\dfrac{11}{3}:\dfrac{7}{6}=\dfrac{22}{7}\)

Ko chép đề

\(2)x-17+x=x-7\)

\(x+x-x=-7+17\)

\(x=-10\)

Vậy ....

âm 10 , nhỉ ?

a) x - 3/2 = 4/3 

    x = 4/3 + 3/2

    x = 8/6 + 9/6 = 17/6

b) 2/5 * x = 1/3

    x = 1/3 : 2/5

    x = 1/3 x 5/2 = 5/6

c) x - 4/9 = 3/7 : 9/14

    x - 4/9 = 2/3

    x = 2/3 + 4/9

    x = 6/9 + 4/9 = 10/9

d) 3/5 * x - 1/2 = 1/5

    3/5 * x = 1/5 + 1/2 = 7/10

    x = 7/10 : 3/5

    x = 7/10 * 5/3 = 7/6

a/\(x-\dfrac{3}{2}=\dfrac{4}{3}\)
\(x=\dfrac{4}{3}+\dfrac{3}{2}\)
\(x=\dfrac{17}{6}\)
b/\(\dfrac{2}{5}\times x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{2}{5}\)
\(x=\dfrac{5}{6}\)
c/\(x-\dfrac{4}{9}=\dfrac{3}{7}:\dfrac{9}{14}\)
\(x-\dfrac{4}{9}=\dfrac{2}{3}\)
\(x=\dfrac{2}{3}+\dfrac{4}{9}\)
\(x=\dfrac{10}{9}\)
d/\(\dfrac{3}{5}\times x-\dfrac{1}{2}=\dfrac{1}{5}\)
\(\dfrac{3}{5}\times x=\dfrac{1}{5}+\dfrac{1}{2}\)
\(\dfrac{3}{5}\times x=\dfrac{7}{10}\)
\(x=\dfrac{7}{10}:\dfrac{3}{5}\)
\(x=\dfrac{7}{6}\)

a,x=\(\dfrac{17}{6}\)b,x=\(\dfrac{5}{6}\)c,x=\(\dfrac{10}{9}\)d,x=\(\dfrac{7}{6}\)

k mk đi

ai k mk

mk k lại

thanks

a; (\(x\) - 2)².(\(x+1\)).(\(x\) - 4) < 0

    (\(x-2\))² ≥ 0 ∀\(x\); \(x+1\) = 0 ⇒ \(x=-1\); \(x-4\) = 0 ⇒ \(x=4\)

Lập bảng ta có:

Theo bảng trên ta có: -1 < \(x\) < 4

Vậy \(-1< x< 4\)

b; [\(x^2\).(\(x-3\)):(\(x-9\))] < 0

    \(x-3=0\)⇒ \(x=3\); \(x-9\) = 0 ⇒ \(x=9\)

    Lập bảng ta có:

Theo bảng trên ta có:     3 < \(x\) < 9

Vậy 3 < \(x\) < 9

Câu 6: Khôg có cau nào đúng

Câu 7: C

Câu 8: B

Câu 9: B

Câu 10: D

6Không có đáp án nào đúng x=11/4

7C

8B

9B

10D