tim x
\(-12x\left(x-5\right)+7\left(3-x\right)=15\)
3, tim x, biet ;
a,\(3x\left[12x-4\right]-9x\left[4x-3\right]=30\)
b,\(x\left[5-2x\right]+2x\left[x-1\right]=15\)
a) \(36x^2-12x-36x^2+27x=30\)
\(15x=30\)
\(x=2\)
b) \(5x-2x^2+2x^2-2x=15\)
\(3x=15\)
\(x=5\)
Phân tích thành nhân tử
a. \(\left(x^2+8x+7\right)\left(x+3\right)\left(x+5\right)+15\)
b. \(\left(4x+1\right)\left(12x-1\right)\left(3x+2\right)\left(x+1\right)-4\)
c. \(\left(x+5\right)\left(x+6\right)\left(x+10\right)\left(x+12\right)-3x^2\)
a) \(\left(x^2+8x+7\right)\left(x+3\right)\left(x+5\right)+15\)
\(= \left(x^2+8x+7\right)\left(x^2+5x+3x+15\right)+15\)
\(=\left(x^2+8x+7\right)\left(x^2+8x+15\right)+15\)
Đặt \(x^2+8x+7=t\), ta đc:
⇒ \(t\left(t+8\right)+15\) = \(t^2+8t+15=\left(t+5\right)\left(t+3\right)\)
b)
\(=\left(12x^2+11x+2\right)\left(12x^2+11x-1\right)-4\)
Đặt \(12x^2+11x+2=t\)
⇒\(t\left(t-3\right)-4\)=\(\left(t-4\right)\left(t+1\right)\)
c) tương tự nha
tim x
a) 2.\(3^x\) =162
b) \(\left(7\times x-11\right)^3=2^5\times5^2+200\)
c) \(\left(2\times x-15\right)^5=\left(2\times x-15\right)^3\)
a) 2.3x =162
3x =162:2
3x=81
3x=34
vậy x bằng 4
Phân tích thành nhân tử:
a) \(B=\left(4x+1\right)\left(12x-1\right)\left(12x-1\right)\left(x+1\right)-4\)
b) \(C=\left(x^2+x\right)^2-2\left(x^2+x\right)-15\)
c) \(D=\left(x^2+2x\right)^2+9x^2+18x+20\)
d) \(E=\left(x^2+3x+1\right)\left(x^2+3x+2\right)-6\)
e) \(F=\left(x^2+8x+7\right)\left(x+3\right)\left(x+5\right)+15\)
vào câu hỏi tương tự mà lm tương tự như thế nha
Phân tích đa thức thành nhân tử:
a) \(A=\left(4x+1\right)\left(12x-1\right)\left(12x-1\right)\left(x+1\right)-4\)
b) \(B=\left(x^2+x\right)^2-2\left(x^2+x\right)-15\)
c) \(C=\left(x^2+2x\right)^2+9x^2+18x+20\)
d) \(D=\left(x^2+3x+1\right)\left(x^2+3x+2\right)-6\)
e) \(E=\left(x^2+8x+7\right)\left(x+3\right)\left(x+5\right)+15\)
phân tích đa thức thành nhân tử:
a. \(ax^2-a^2x-x+a\)
b. \(18x^3-12x^2+2x\)
c. \(x^3-5x^2-4x+20\)
d. \(\left(x+7\right)\left(x+15\right)+15\)
\(a.\) \(ax^2-a^2x-x+a\)
\(=\left(ax^2-a^2x\right)-\left(x-a\right)\)
\(=ax\left(x-a\right)-\left(x-a\right)\)
\(=\left(ax-1\right)\left(x-a\right)\)
\(b.\) \(18x^3-12x^2+2x\)
\(=2x\left(9x^2-6x+1\right)\)
\(=2x\left(3x-1\right)^2\)
\(c.\) \(x^3-5x^2-4x+20\)
\(=\left(x^3-5x^2\right)-\left(4x-20\right)\)
\(=x^2\left(x-5\right)-4\left(x-5\right)\)
\(=\left(x^2-4\right)\left(x-5\right)\)
\(=\left(x-2\right)\left(x+2\right)\left(x-5\right)\)
\(d.\) \(\left(x+7\right)\left(x+15\right)+15\)
\(=x^2+15x+7x+105+15\)
\(=x^2+22x+120\)
\(=\left(x+10\right)\left(x+12\right)\)
giải pt:
a,\(\left(13-4x\right)\sqrt{2x-3}+\left(4x-3\right)\sqrt{5-2x}=2+8\sqrt{-4x^2+16x-15}\)
b,\(\left(9x-2\right)\sqrt{3x-1}+\left(10-9x\right)\sqrt{3-3x}-4\sqrt{-9x^2+12x-3}=4\)
c, \(\left(6x-5\right)\sqrt{x+1}-\left(6x+2\right)\sqrt{x-1}+4\sqrt{x^2-1}=4x-3\)
Giaỉ các PT:
a) \(\left(x^2+1\right)^2=4\left(2x-1\right)\)
b) x(x+1)(x+2)(x+3)=24
c)\(\left(12x+7\right)^2\left(3x+2\right)\left(2x+1\right)=3\)
d)\(\left(x^2-9\right)^2=12x+1\)
e)\(\left(x-1\right)^5+\left(x+3\right)^5=242\left(x+1\right)\)
Giup mk vs mn
b) x(x+1)(x+2)(x+3)=24
(x2+3x)(x2+3x+2)=24 (1)
Đặt x2+3x+1=a
Khi đó(1)<=>(a-1)(a+1)=24
a2-1=24 <=>a2=25<=>a=5;-5
a=5=>x2+3x+1=5=>x2+3x-4=0=>(x-1)(x+4)=0=>x=1,-4
a=-5=>x^2+3x+1=-5=>x2+3x+6=0=>(x+\(\frac{3}{2}\))2+\(\frac{15}{4}\)=0
=>pt vô nghiệm
\(\left|x\right|-5\frac{3}{7}\left|x\right|-\frac{3}{4}=2\left|x\right|+\left(-\frac{8}{7}\right)\)
Tim x
khi x>0, ta có
x - 38/7*x - 3/4 = 2*x + (-8/7)
-45/7*x=-11/28
x=-11/180( ko thoả )
khi x<0 có
-x -38/7x - 3/4 = -2x -8/7
bạn tự giải nhé rồi ktra dđiều kiện nhé !