Tìm x biết:
a, (x - 32) ÷ 7 = 64
b, 24 ÷ (x - 12) = 4
Tìm x, biết:
a) 230 + 2 4 + ( x - 5 ) = 315 . 2018 0 ;
b) 707 : 2 x - 5 + 74 = 4 2 - 3 2 ;
c) [(6x - 12): 3].32 = 64;
d) (x:7 + 15).23 = 391
Tìm x biet:
a,93/17:x+(-21/17):x+22/7:22/3=5/14
b,-32/27-(3x-7/9)^3=-24/27
c,[(3,75:1/4)+12/5.125%)-(7/2.0,8-1,2:3/2)]:(3/2+0,75)x=64
a; \(\dfrac{93}{17}\): \(x\) + (- \(\dfrac{21}{17}\)) : \(x\) + \(\dfrac{22}{7}\): \(\dfrac{22}{3}\) = \(\dfrac{5}{14}\)
\(\dfrac{94}{17}\) \(\times\) \(\dfrac{1}{x}\) - \(\dfrac{21}{17}\) \(\times\) \(\dfrac{1}{x}\) + \(\dfrac{3}{7}\) = \(\dfrac{5}{14}\)
\(\dfrac{72}{17}\) \(\times\) \(\dfrac{1}{x}\) + \(\dfrac{3}{7}\) = \(\dfrac{5}{14}\)
\(\dfrac{72}{17x}\) = \(\dfrac{5}{14}\) - \(\dfrac{3}{7}\)
\(\dfrac{72}{17x}\) = - \(\dfrac{1}{14}\)
17\(x\) = 72.(-14)
17\(x\) = - 1008
\(x\) = - 1008 : 17
\(x\) = - \(\dfrac{1008}{17}\)
Vậy \(x\) \(=-\dfrac{1008}{17}\)
b; - \(\dfrac{32}{27}\) - (3\(x\) - \(\dfrac{7}{9}\))3 = - \(\dfrac{24}{27}\)
- \(\dfrac{32}{27}\) + \(\dfrac{24}{27}\) = (3\(x\) - \(\dfrac{7}{9}\))3
(3\(x-\dfrac{7}{9}\))3 = - \(\dfrac{8}{27}\)
(3\(x-\dfrac{7}{9}\))3 = (- \(\dfrac{2}{3}\))3
3\(x-\dfrac{7}{9}\) = - \(\dfrac{2}{3}\)
3\(x\) = - \(\dfrac{2}{3}\) + \(\dfrac{7}{9}\)
3\(x\) = \(\dfrac{1}{9}\)
\(x\) = \(\dfrac{1}{9}\) : 3
\(x\) = \(\dfrac{1}{27}\)
Vậy \(x=\dfrac{1}{27}\)
Tìm số nguyên x biết
a, 7x + 4 = 3212
b, 2x = 325 . 646
Có ai on ko giúp với
b) \(2^x=32^5\cdot64^6\)
\(2^x=32^5\cdot\left(2\cdot32\right)^6\)
\(2^x=32^5\cdot2^6\cdot32^6\)
\(2^x=32^{11}\cdot2^6\)
\(2^x=32^{11}\cdot32\cdot2\)
\(2^x=32^{12}\cdot2\)
\(2^x=\left(2^5\right)^{12}\)
\(2^x=2^{60}\)
\(=>x=60\)
Bài 1:Tìm x, biết:
a, (x-15):50+22=24
b, 42-(2x+32)+12:2=6
c,134-2{156-6.[54-2.(9+6)]}.x=86
bài 2:tìm x, biết
a,120:[21-(4x-4)]=23.3
b,3.[205-(x-9)]-486=0
c,204-2{200-5.[64-2.(11+6)]}.x=4
a,\(\left(x-15\right):50+22=24\)
\(< =>\frac{\left(x-15\right)}{50}=2< =>x-15=100\)
\(< =>x=100+15=115\)
b,\(42-\left(2x+32\right)+12:2=6\)
\(< =>42-2x-32=0\)
\(< =>10-2x=0< =>x=\frac{10}{2}=5\)
Làm nốt :
c) \(134-2\left\{156-6\cdot\left[54-2\cdot\left(9+6\right)\right]\right\}\cdot x=86\)
=> 134 - 2{156 - 6 . [54 - 2 . 15]} . x = 86
=> 134 - 2{156 - 6 . [54 - 30]} . x = 86
=> 134 - 2{156 - 6. 24} . x = 86
=> 134 - 2{156 - 144} . x = 86
=> 134 - 2.12 . x = 86
=> 134 - 24 . x = 86
=> 24.x = 48
=> x = 2
Bài 2 : a) 120 : [21 - (4x - 4)] = 23.3
=> 120 : [21 - (4x - 4)] = 8.3
=> 120 : [21 - (4x - 4)] = 24
=> 21 - (4x - 4) = 5
=> 4x - 4 = 16
=> 4x = 20
=> x = 5
b) 3.[205 - (x - 9)] - 486 = 0
=> 3.[205 - (x - 9)] = 486
=> 205 - (x - 9) = 162
=> x - 9 = 205 - 162 = 43
=> x = 43 + 9 = 52
c) 204 - 2{200 - 5.[64 - 2.(11 + 6)]} . x = 4
=> 204 - 2{200 - 5.[64 - 2.17]} . x = 4
=> 204 - 2{200 - 5 .[64 - 34]}.x = 4
=> 204 - 2{200 - 5.30} . x = 4
=> 204 - 2{200 - 150}.x = 4
=> 204 - 2.50 . x = 4
=> 2.50.x = 200
=> 100.x = 200
=> x = 2
Tìm số nguyên x biết
a, 7x + 4 = 3212
b, 2x = 325 . 646
Có ai on ko giúp với
Mình chỉ biết làm câu b thôi. Xl nhé!
b/ \(2^x=32^5.64^6\)
\(\Rightarrow2^x=\left(2^5\right)^5.\left(2^6\right)^6\)
\(\Rightarrow2^x=2^{25}.2^{36}\)
\(\Rightarrow2^x=2^{25+36}\)
\(\Rightarrow2^x=2^{61}\)
\(\Rightarrow x=61\)
Vậy \(x=61\)
Tìm x :
a)\(\dfrac{49}{81}\)=\(\dfrac{7^x}{9}\) b)\(\dfrac{-64}{343}\)=(\(\dfrac{-4^x}{7}\))
c)\(\dfrac{9}{144}\)=\(\dfrac{3^x}{12}\) d)\(\dfrac{-1}{32}\)=(\(\dfrac{-1^x}{2}\))
Giúp với ạ bài khó quá . Em cảm ơn ạ !
a) \(\dfrac{49}{81}=\dfrac{7^x}{9^x}\)(sửa đề)
\(\Leftrightarrow\left(\dfrac{7}{9}\right)^2=\left(\dfrac{7}{9}\right)^x\)\(\Rightarrow x=2\)
b) \(\dfrac{-64}{343}=\left(-\dfrac{4^x}{7^x}\right)\)(sửa đề)
\(\Leftrightarrow\left(-\dfrac{4}{7}\right)^3=\left(-\dfrac{4}{7}\right)^x\) \(\Rightarrow x=3\)
c) \(\dfrac{9}{144}=\dfrac{3^x}{12^x}\)(sửa đề)
\(\Leftrightarrow\left(\dfrac{3}{12}\right)^2=\left(\dfrac{3}{12}\right)^x\Rightarrow x=2\)
d) \(-\dfrac{1}{32}=\left(-\dfrac{1^x}{2^x}\right)\)(sửa đề)
\(\Leftrightarrow\left(-\dfrac{1}{2}\right)^5=\left(-\dfrac{1}{2}\right)^x\Rightarrow x=5\)
Mong bạn xem lại đề bài.
Tìm x,y,z
a/ -8/5=x/15=16/y=z/-75
b/ -4/8=x/-10= -7/y=x/-24
c/ x/4= -15/y=z/52= -32/64
GIÚP TỚ Với
dấu '' / '' là phân số
Câu 4: Biết 2 x+ 32=32 . Số x cần tìm là: A. x= 0 B. x= 64 C. x= 30 D. x=20
Tìm số tự nhiên x biết:
a) x – 32 : 16 = 48
b) 88 – 3.(7+x) = 64
c) (5+4x) : 3 – 121 : 11 = 4
d) 15 – 2(3x+1) = 11.13 – 130
a) x – 32 : 16 = 48 ó x – 2 = 48 ó x = 48 + 2 ó x = 50
b) 88 – 3.(7+x) = 64 ó 3.(7+x) = 88 – 64 ó 7 + x = 24:3 ó x = 8 – 7 ó x = 1
c) (5+4x) : 3 – 121 : 11 = 4 ó (5+4x) : 3 – 11 = 4 ó (5+4x) : 3 = 4 + 11 ó 5+4x = 15.3 ó 4x = 45 – 5 ó 4x = 40 ó x = 10
d) 15 – 2(3x+1) = 11.13 – 130 ó 15 – 2(3x+1) = 143 – 130 ó 15 – 2(3x+1) = 13
ó 2(3x+1) = 15 – 13 ó 3x + 1 = 2:2 ó 3x = 1 – 1 ó 3x = 0 ó x = 0