Tìm X
X x 6 = 30
Tìm số nguyên xx thỏa mãn:
-3x + 30/21 = 6/7
\(\Rightarrow-3x=\dfrac{6}{7}-\dfrac{30}{21}\\ \Rightarrow-3x=\dfrac{18}{21}-\dfrac{30}{21}\\\Rightarrow-3x=\dfrac{-12}{21}\\ \Rightarrow x=\dfrac{-12}{21}:3\\ \Rightarrow x=\dfrac{-12}{63}=\dfrac{-4}{21} \)
-3x+\(\dfrac{30}{21}=\dfrac{6}{7}\)
=>-3x=\(\dfrac{6}{7}-\dfrac{30}{21}\)
=>-3x=\(\dfrac{18-30}{21}\)
=>-3x=\(\dfrac{-12}{21}\)
=>x=\(\dfrac{-12}{21}.\dfrac{1}{3}\)
=>x=\(\dfrac{-12}{63}=\dfrac{-4}{21}\)
Vậy ......
TÌM X:75%xX+3/4xX+X=30
\(75\%x+\frac{3}{4}x+x=30\)
\(\Leftrightarrow\left(75\%+\frac{3}{4}+1\right)x=30\)
\(\Leftrightarrow\frac{5}{2}x=30\)
\(\Leftrightarrow x=30:\frac{5}{2}\)
\(\Leftrightarrow x=12\)
Tìm X biết : 75%xX+3/4xX+X=30
đổi 75%=3/4.Ta có:
3/4xX+3/4xX+X=30
(3/4+3/4+1)xX=30
5/2 x X=30
X = 30:5/2
X = 12
\(75\%\times x+\frac{3}{4}\times x+x=30\)
\(\frac{3}{4}\times x+\frac{3}{4}\times x+1\times x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}+1\right)\times x=30\)
\(\frac{5}{2}\times x=30\)
\(x=30\div\frac{5}{2}\)
\(x=12\)
giá xăng từ 20 000 đồng lên 21 000 đồng 1 lít . hỏi giá xăng tăng bao nhiêu phần trăm?
Tìm x biết
30%xX+X=52
(30% + 1) x X = 52
130% x X = 52
X = 52 : 130%
X = 40
75%xX+3/4xX+X=30
tìm X
0,75 x X + 0,75 x X + X = 30
X x ( 0,75 + 0,75 + 1 ) = 30
X x 2,5 = 30
X = 30 : 2,5
X = 12
75%xX+3/4xX+X=30
<=>3/4xX+3/4xX+X=30
<=>10/4xX=30
<=>10xX=120
<=>X=120/10=12
Vậy X=12
75%xX+3/4xX+x=30
toán tìm X
0,75x + 0,75x = 30
0,75 . 2x = 30
2x = 40
x = 20
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(x\cdot\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)
\(x\cdot\frac{5}{2}=30\)
\(x=30\cdot\frac{2}{5}\)
\(x=12\)
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(\frac{3}{4}\cdot x+\frac{3}{4}\cdot x+x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}\right)\cdot x+x=30\)
\(\frac{3}{2}\cdot x+x=30\)
\(\frac{3}{2}\cdot x+\frac{1}{1}\cdot x=30\)
\(\left(\frac{3}{2}+\frac{1}{1}\right)\cdot x=30\)
\(\frac{5}{2}\cdot x=30\)
\(x=30\text{ : }\frac{5}{2}\)
\(x=12\)
Bài 5: Tìm X
X x 27 + X x 30 + X x 43 = 210500 | 128 x X - 12 x X – 16 x X = 5208000 |
……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………..
……………………………………………………………………………………………………………………………………………………………………………………………………………….
……………………………………………………………………………………………………………………………………………………………………………………………………………….
a)\(\Leftrightarrow\)\(x(27+30+43)=210500\)
\(\Leftrightarrow\)\(100x=210500\)
\(\Leftrightarrow\)\(x=2105\)
b)\(\Leftrightarrow\)\(x(128-12-16)=5208000\)
\(\Leftrightarrow\)\(100x=5208000\)
\(\Leftrightarrow\)\(x=52080\)
\(x\times27+x\times30+x\times43=210500\)
\(\Leftrightarrow x\times\left(27+30+43\right)=210500\)
\(\Leftrightarrow x\times100=210500\)
\(\Leftrightarrow x=2105\)
a: 27x+30x+43x=210500
nên 100x=210500
hay x=2105
b: 128x-12x-16x=5208000
nên 100x=5208000
hay x=52080
Tìm x
x+30%.x=-1,3
Giải thích rõ vì sao lại làm như vậy
cảm ơn nhé
x+ \(\dfrac{30}{100}\)x=-1,3
x(1+\(\dfrac{30}{100}\))= -1,3
x. 1,3= -1,3
x = -1
1/2+1/6+1/12+1/20+1/30+.......+1/Xx[X+1]2016/2017
tìm x
x+1=6\(-\sqrt{x+1}\)
ĐKXĐ: \(x\ge-1\)
\(\Leftrightarrow6-\sqrt{x+1}-x-1=0\\ \Leftrightarrow5-x=\sqrt{x+1}\\ \Leftrightarrow25-10x+x^2=x+1\left(x\le5\right)\\ \Leftrightarrow x^2-11x+24=0\\ \Leftrightarrow\left(x^2-3x\right)-\left(8x-24\right)=0\\ \Leftrightarrow x\left(x-3\right)-8\left(x-3\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x-8\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\left(tm\right)\\x=8\left(ktm\right)\end{matrix}\right.\)
Vậy \(x=3\)