Tính tổng: 30 + 12 + (-20) + (-12)
Tính tổng:
a. (-17)+5+8+17
b. 30+12+(-20)+(-12)
a,(-17)+5+8+17=[(-17)+17]+5+8=0+13=13
b. 30+12+(-20)+(-12)=[12+(-12)]+30+(-20)=0+10=10
Nho k minh nha
a, (-17) + 5 + 8 + 17
= -12 + 8 + 17
= -4 + 17
= 17 - 4
= 13
b, 30 + 12 + (-20) + (-12)
= 42 + (-20) + (-12)
= 42 - 20 - 12
= (42 - 12) - 20
= 30 - 20
= 10
Tính tổng
1/12 + 1/20 + 1/30 + ... + 1/9702
\(=\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+...+\dfrac{1}{98\cdot99}\)
\(=\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{98}-\dfrac{1}{99}=\dfrac{1}{3}-\dfrac{1}{99}=\dfrac{32}{99}\)
1/3.4 + 1/4.5 + ...+1/98.99
= 1/3-1/4+1/4-1/5+...+1/98-1/99
= 1/3-1/99= 32/99
Tính tổng: 1/6 + 1/12 + 1/20 + 1/30 + 1/42.
tính tổng A = 1/12 + 1/20 + 1/30 +... + 1/506 + 1/552
Tính tổng
(-17) + 5 + 8 +17
30 +12 +(-20) + (-12)
(-4) + (-440) + (-6) + 440
(-5) + (-10) +16 + (-1)
(-17) + 5 + 8 + 17
= (-17) + 17 + (5 + 8)
= 0 + 13
= 13
30 + 12 + (-20) + (-12)
= [30 + (-20)] + [12 + (-12)]
= 10 + 0
= 10
(-4) + (-440) + (-6) + 400
= [(-4) + (-6)] + [(-400) + 400]
= -10 + 0
= -10
(-5) + (-10) + 16 + (-1)
= [(-5) + (-10) + (-1)] + 16
= -16 + 16
= 0
(-17)+5+8+17 30+12+(-20)+(-12) (-4)+(-440)+(-6)+440 (-5)+(-10)+16+(-1)
=(-17+17)+(5+8) =(-12+12)+(-20+30) =[(-4)+(-6)]+(-440+440) =[(-5)+(-1)+(-10)]+16
=0+13 =0+10 =(-10)+0 =(-16)+16
=13 =10 = -10 = 0
tính tổng S= 1/6+1/12+1/20+1/30+1/42+1/56
S= \(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)
S= 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 -1/6 +1/6 - 1/7 + 1/7 - 1/8
S= 1/2 - 1/ 8
S= 3/8
S= 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8
= 1/2 - 1/3 + 1/3 - ...+ 1/7 - 1/8
= 1/2 - 1/8
= 3/8
S=(1/2.3) +(1/3.4) + (1/4.5) +...+1/7.8
S=1/2-1/3+1/3-1/4 +1/4-1/5+...+1/7-1/8
S=1/2-1/8
S=3/8
tính tổng : A = 1/2 + 5/6 + 11/12 + 19/20 + 29/30 + 41/42 + 55/56
`= 1 - 1/2 + 1 - 1/6 + ... + 1 - 1/56`
`= 1 - 1/(1.2) + 1 - 1/(2.3) + ... + 1 - 1/(7.8)`
`= 7 - (1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4+ 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8`.
`= 8 - 1/8`
`= 63/64`.
`A=1/2+5/6+11/12+19/20+29/30+41/42+55/56`
`A=1-1/2+1-1/6+1-1/12+1-1/20+1-1/30+1-1/42+1-1/56`
`A=(1+1+1+1+1+1+1)-(1/2+1/6+1/12+....+1/56)`
`A=7-(1/[1xx2]+1/[2xx3]+1/[3xx4]+....+1/[7xx8])`
`A=7-(1-1/2+1/2-1/3+1/3-1/4+....+1/7-1/8)`
`A=7-(1-1/8)`
`A=7-(8/8-1/8)`
`A=7-7/8`
`A=56/8-7/8=49/8`
tính tổng sau
1/2+1/6+1/12+1/20+1/30+1/42+1/56
giải giúp mik vs
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}\)
\(=\dfrac{1}{182}\)
1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 = 1/182
TÍNH NHANH TỔNG SAU :
1/42 +1/30 +1/20 +1/12 +1/6
CÁC BẠN ƠI GIÚP MÌNH !
BẠN NÀO LÀM ĐƯỢC THÌ MÌNH K CHO NHÉ !
A=1/6 +1/12 +1/20 +1/30 +1/42
=1/2.3 +1/3.4 +1/4.5 +1/5.6 +1/6.7
=1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7
=1/2 - 1/7 = 5/14
\(\frac{1}{42}+\frac{1}{30}+\frac{1}{20}+\frac{1}{12}+\frac{1}{6}\)
\(=\frac{1}{7\cdot6}+\frac{1}{6\cdot5}+\frac{1}{5\cdot4}+\frac{1}{4\cdot3}+\frac{1}{3\cdot2}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)
\(=\frac{1}{2}-\frac{1}{7}\)
\(=\frac{5}{14}\)