a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)

\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)

\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)

b) \(\dfrac{39}{7}:x=13\)

\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)

c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)

\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)

\(\dfrac{14}{5}x=34+50=84\)

\(x=\dfrac{84}{\dfrac{14}{5}}=30\)

d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)

e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)

\(\dfrac{1}{6}x=\dfrac{5}{12}\)

\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)

g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)

\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)

\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)

\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)

\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)

h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)

\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)

\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)

\(x=1\)

Mỏi tay woa bn làm nốt nha!!

a)

   \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)

   \(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}\)

    \(\frac{1}{3}:x=\frac{-1}{15}\)

     \(x=\frac{1}{3}:\frac{-1}{15}\)

    \(x=-5\)

b)

     \(\frac{10}{3x}+\frac{67}{4}=-13.25\)

      \(\frac{10}{3x}+\frac{67}{4}=\frac{-53}{4}\)

       \(\frac{10}{3x}=\frac{-53}{4}+\frac{67}{4}\)

       \(\frac{10}{3x}=\frac{7}{2}\)

      \(\Rightarrow10.2=7.3x\)

            \(20=21x\)

            \(x=\frac{20}{21}\)

c)

        x+30%x=-1.3

        x+0.3x=-1.3

        x (1+0.3) = -1.3

        x . 1.3 = -1.3

        x = -1.3 : 1.3

        x = 1

d)

          \(\left(\frac{14}{5x}-50\right):\frac{2}{3}=51\)

           \(\frac{14}{5x}-50=51.\frac{2}{3}\)

             \(\frac{14}{5x}-50=34\)

             \(\frac{14}{5x}=34+50\)

              \(\frac{14}{5x}=84\)

               \(84.5x=14\)

              420x = 14

                   \(x=\frac{1}{30}\)

a, \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)

=> \(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}\)

=>\(\frac{1}{3}:x=\frac{-1}{15}\)

=> \(x=\frac{1}{3}:\frac{-1}{15}\)

=> \(x=\frac{-1}{5}\)

mình sai chỗ kết quả cuối bằng -5 nhé

1/S=-1+3-5+7-....-53+55

Có số cặp là :[(55-1)/2+1]/2=14

Mà khoảng cách giữa 2 số liền nhau là:-1+3=2;-5+7=2;.....

=>S=14*2=28(số cặp nhân với khoảng cách giữa 2 số)

2/S=2-5+8-11+....-29+32

Có số cặp là:5 dư 32

Mà khoảng cách giữa 2 số liền nhau là:2-5=-3;8-11=-3;....

=>S=[5*(-3)]+32=17

3/-1+5-9+13-....-41+45

Có số cặp là:[(45-1)/4+1]/2=6

Mà khoảng cách giữa 2 số liền nhau là:-1+5=4;-9+13=4;.....

=>S=6*4=24

4/S=1-5+9-13-...-41+45

Có số cặp là:[(45-1)/4+1]/2=6

Mà khoảng cách giữa 2 số là:1-5=-4;9-13=-4;...

=>S=6*(-4)=-24

Còn câu 5 mk ko biết làm nha!

1. \(S=-1+3-5+7-...-53+55\)

Số cặp là \(13\)

Mà \(3-5=-2\)

\(\Rightarrow S=-1+-2+...+-2+55\)

\(\Rightarrow S=-1+\left(-25\right)+55\)

\(\Rightarrow S=-27+55\)

\(\Rightarrow S=28\)

a) (26-6)*(-4)+31*(-7-13)

=-80+-620

=-700

hacker 2k6

giúp mik đi mà, gấp lắm, mik phải đi học ngay r, huhuhu

1. Áp dụng TCDTSBN ta có:

$\frac{x-1}{3}=\frac{y-2}{4}=\frac{z+5}{6}=\frac{x-1+(y-2)-(z+5)}{3+4-6}$

$=\frac{x+y-z-8}{1}=\frac{8-8}{1}=0$

$\Rightarrow x-1=y-2=z+5=0$

$\Rightarrow x=1; y=2; z=-5$

2.

Có:

$\frac{x+1}{2}=\frac{y+3}{4}=\frac{z+5}{6}=\frac{2x+2}{4}=\frac{3y+9}{12}=\frac{4z+20}{24}$

Áp dụng tính chất dãy tỉ số bằng nhau ta có:

$\frac{x+1}{2}=\frac{y+3}{4}=\frac{z+5}{6}=\frac{2x+2}{4}=\frac{3y+9}{12}=\frac{4z+20}{24}=\frac{2x+2+3y+9+4z+20}{4+12+24}=\frac{2x+3y+4z+31}{40}=\frac{9+31}{40}=1$

Suy ra:

$x+1=2.1=2\Rightarrow x=1$

$y+3=1.4=4\Rightarrow y=1$

$z+5=6.1=6\Rightarrow z=1$

$

3.

Có:

$\frac{x+1}{3}=\frac{y+2}{-4}=\frac{z-3}{5}=\frac{3x+3}{9}=\frac{2y+4}{-8}=\frac{4z-12}{20}$

Áp dụng TCDTSBN:

$\frac{x+1}{3}=\frac{y+2}{-4}=\frac{z-3}{5}=\frac{3x+3}{9}=\frac{2y+4}{-8}=\frac{4z-12}{20}=\frac{3x+3+2y+4+4z-12}{9+(-8)+20}=\frac{3x+2y+4z-5}{21}=\frac{47-5}{21}=2$

Suy ra:

$x+1=3.2=6\Rightarrow x=5$

$y+2=(-4).2=-8\Rightarrow y=-10$

$z-3=5.2=10\Rightarrow z=13$