`#3107.101107`

\(\dfrac{1}{4}\times x+\dfrac{4}{5}=-\dfrac{7}{10}\)

\(\Rightarrow\dfrac{1}{4}\times x=-\dfrac{7}{10}-\dfrac{4}{5}\)

\(\Rightarrow\dfrac{1}{4}\times x=-\dfrac{3}{2}\)

\(\Rightarrow x=-\dfrac{3}{2}\div\dfrac{1}{4}\)

\(\Rightarrow x=-6\)

Vậy, `x = -6.`

1/4 . x + 4/5 = -7/10

1/4 . x = -7/10 - 4/5

1/4 . x = -3/2

x = -3/2 : 1/4

x = -6

1,4 x 15/49 + 4/5 + 2/3 : 21/5

= 3/7 + 4/5 + 10/63

= 3/7 + 10/63 + 4/5

= 37/63 + 4/5

= 437/315

    \(18,2:x=1,4\times4\)

\(\Rightarrow18,2:x=5,6\)

\(\Rightarrow x=3,25\)

    \(\frac{3}{5}\times x=\frac{2}{3}-\frac{2}{7}\)

\(\Rightarrow\frac{3}{5}\times x=\frac{8}{21}\)

\(\Rightarrow x=\frac{40}{63}\)

tíc nha

18,2 : x =1,4 x 4

18,2 : x =5,6

x = 18,2 ; 5,6

x = 3,25

\(18,2:x=1,4\cdot4\)

             \(x=5,6\)

             \(x=18,2:5,6\)

             \(x=3,25\)   

\(\frac{3}{5}\cdot x=\frac{2}{3}-\frac{2}{7}\)

         \(x=\frac{8}{21}\)

         \(x=\frac{8}{21}:\frac{3}{5}\)

         \(x=\frac{40}{63}\)

a)(3/4-5/6+7/12).(-12/7)=1/2.(-12/7)

=6/7

b)1,4.15/49-(4/5+2/3):11/5=1,4.15/49-22/15:11/5

=3/7-2/3=-5/21

(3/4-5/6+7/12)×(-12/7)

=(9/12-10/12+7/12)×(-12/7)

=(-1/12+7/12)×(-12/7)

=6/12×(-12/7)

=1/2×(-12/7)

=-12/14

=-6/7

a: \(=\dfrac{7}{5}\cdot\dfrac{15}{49}-\dfrac{12+10}{15}:\dfrac{11}{5}\)

\(=\dfrac{3}{7}-\dfrac{22}{15}\cdot\dfrac{5}{11}=\dfrac{3}{7}-\dfrac{2}{3}=\dfrac{9-14}{21}=\dfrac{-5}{21}\)

b: =>2,8x-32=-60

=>2,8x=-28

hay x=-10

Giải:

B=1,4 .15/49 - (4/5+2/3) :2 1/5

B=7/5.15/49 - 22/15 : 11/5

B=3/7 - 2/3

B=-5/21

Chúc bạn học tốt!

\(1,4x\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right):2\frac{1}{5}\)

\(=\frac{3}{7}-\frac{22}{15}:2\frac{1}{5}\)

\(=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)

học tốt ~~~

\(1,4\times\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right)\div2\frac{1}{5}\)

\(=\frac{14}{10}\times\frac{15}{49}-\frac{22}{15}\div\frac{11}{5}\)

\(=\frac{7}{5}\times\frac{15}{49}-\frac{22\times5}{15\times11}\)

\(=\frac{7\times15}{5\times49}-\frac{22\times5}{15\times11}\)

\(=\frac{7\times7\times3\times5}{5\times7\times7}-\frac{11\times2\times5}{3\times5\times11}\)

\(=3-\frac{2}{3}\)

\(=\frac{7}{3}\)