các bạn tham khảo nhé
a, Cho \(a^{2018}+b^{2018}+c^{2018}=\left(ab\right)^{1009}+\left(bc\right)^{1009}+\left(ca\right)^{1009}\)
Tính \(P=\left(a-b\right)^{2018}+\left(b-c\right)^{2018}+\left(c-a\right)^{2018}\)
b, Cho \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=2\)và \(\frac{2}{ab}-\frac{1}{c^2}=9\)
Tính \(P=\left(a+2b+c\right)^{2018}\)