\(a,\left(x^2+4\right)^2-16x^2=\left(x^2+4\right)-\left(4x\right)^2=\left(x^2+4-4x\right).\left(x^2+4+4x\right)=\left(x-2\right)^2.\left(x+2\right)^2\)

\(b,\left(x+3\right)^3-8x^3=\left(x+3\right)^3-\left(2x\right)^3=\left(x+3-2x\right).\left[x^2+\left(x+3\right).2x+\left(2x\right)^2\right]=\left(3-x\right).\left(x^2+2x^2+6x+4x^2\right)\)

\(c,\left(4x^2-3x-18\right)^2-\left(4x^2+3x\right)^2=\left(4x^2-3x-18-4x^2-3x\right).\left(4x^2-3x-18+4x^2+3x\right)=\left(-6x-18\right).\left(8x^2-18\right)\)

\(A=4^4\cdot9^5=\left(2^2\right)^4\cdot\left(3^2\right)^5=2^8\cdot3^{10}\)

\(A=4^4\cdot9^5=2^8\cdot3^{10}\)

\(A=4^4\cdot9^5=\left(2^2\right)^4\cdot\left(3^2\right)^5=2^8\cdot3^{10}\)

\(A=4^4\cdot9^5\)

\(A=\left(2^2\right)^4\cdot\left(3^2\right)^5\)

\(A=2^{2\cdot4}\cdot3^{2\cdot5}\)

\(A=2^8\cdot3^{10}\)

=36 mũ 9 nhé

<=> [(x + 2)(x + 5)][(x + 3)(x + 4) - 24 = (x² + 7x + 10) (x² + 7x + 12) - 24 (1)

đặt x² + 7x + 11 = t

=> ( 1 ) <=> (t - 1)(t + 1) - 24 = t² - 1 - 24 = t² - 25 = (t - 5)(t + 5)

=> (x² + 7x + 11 - 5) (x² + 7x + 11 + 5) = (x² + 7x + 6) (x² + 7x + 16) (x + 1) (x + 6) (x² + 7x + 16)

chúc you học tốt!! ^^

ok mk nhé!! 4545454353434636565454676345345346654767567567587676345346334534534565646756

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A

Tham khảo :

TL

= 4 mũ 4 = 2 mũ 8

= 9 mũ 5 = 3 mũ 10

= 2 mũ 8 . 3 mũ 10

HT