\(10\left(2+5+3\right)=10.10=100\)

31

100

\(a,2004^2-16=2004^2-4^2=\left(2004-4\right)\left(2004+4\right)=2000.2008=4016000\)\(b,892^2+892.216+108^2=892^2+2.892.108+108^2=\left(892+108\right)^2=1000^2=1000000\)\(c,10,2.9,8-9,8.02+10,2^2-10,2.0,2=9,8\left(10,2-0,2\right)+10,2\left(10,2-0,2\right)=9,8.10+10,2.10=98+102=200\)\(d,36^2+26^2-52.36=36^2-2.36.26+26^2=\left(36-26\right)^2=10^2=100\)\(e,99^3+1+3.\left(99^2+99\right)=99^3+3.99^2+3.99+1^3=\left(99+1\right)^3=100^3=1000000\)

\(f.37.43=\left(40-3\right)\left(40+3\right)=40^2-3^2=1600-9=1591\)

10.5+10.3+10.2

=10.(5+3+2)

=10.10

=10^2

=100

10 . 5 + 10 . 3 + 10 . 2
Cách 1:
10 . 5 + 10 . 3 + 10 . 2
= 50 + 30 + 20
= 80 + 20
= 100
Cách 2:
10 . 5 + 10 . 3 + 10 . 2
= 10 . (5 + 3 + 2)
= 10 . 10
= 100

10 . 5 + 10 . 3 + 10 . 2
Cách 1:
10 . 5 + 10 . 3 + 10 . 2
= 50 + 30 + 20
= 80 + 20
= 100
Cách 2:
10 . 5 + 10 . 3 + 10 . 2
= 10 . (5 + 3 + 2)
= 10 . 10
= 100

\(10.1+10.2+10.3+10.4=10\left(1+2+3+4\right)=10.10=100\)

10.1+10.2+10.3+10.4

=  10 . ( 1 + 2 + 3 + 4 )

= 10 . 10

= 100

=10(1+2+3+4)

=10.10

=100

10 + 10 + 10.2 + 3 + 5

= 20 + 20 + 3 +5

= 40 + 8

= 48

=48 nha bn

=10+10+20+3+5

=48

49.3=147

10.2=20

49.3=147

10.2=20

49.3=147

10.2=20 

\(\approx6,8\)

(3x-2).5⁷ = 5¹⁰.2

=> 3x-2 = 5¹⁰.2/5⁷

=> 3x-2 = 5³.2

=> 3x-2 = 125.2

=> 3x-2 = 250

=> 3x = 250+2

=> 3x = 252

=> 3x = 252:3

=> x = 84

Vậy x=84

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