13/15.0,25+(8/15-1 19/60) : 1 23/24
2)B=13/15.0,25,3+{8/15-1 19/60}:1 23/24
\(1\dfrac{13}{15}\).(0,5)2.3+\(\left(\dfrac{8}{15}-1\dfrac{19}{60}\right)\):\(1\dfrac{23}{24}\)
\(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\\ =\dfrac{28}{15}.0,25.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\\ =\dfrac{7}{15}.3+\dfrac{-47}{60}:\dfrac{47}{24}\\ =\dfrac{7}{5}+\dfrac{-2}{5}\\ =\dfrac{5}{5}=1\)
a) 1 13/15 . (0,5)^2 . 3 + ( 8/15 -1 19/60 ) : 1 23/24
Giải:
\(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}.\dfrac{1}{4}.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{5}+\left(-\dfrac{47}{60}\right).\dfrac{24}{47}\)
\(=\dfrac{7}{5}+\left(-\dfrac{2}{5}\right)\)
\(=\dfrac{7}{5}-\dfrac{2}{5}\)
\(=1\)
Vậy ...
a) 1/13/15.(0,5)^2.3+3+(8/15-1/19/60):1/23/24
1 13/15 . (0,5)2 . 3 + ( 8/15 - 1 19/60 ) : 1 23/24
(-3,2).-15/64 + (0,8-2 và 4/15 ):1 và 23/24
1 và 13/15 .3.(0,5) mũ 2.3+(8/15-1 và 19/60):1 và 23/24
Thực hiện dãy tính:
1\(\dfrac{13}{15}\).(0,5)\(^2\)+3.(\(\dfrac{8}{15}\)+1\(\dfrac{19}{60}\)):1\(\dfrac{23}{24}\)
\(1\dfrac{13}{15}\cdot\left(0,5\right)^2+3\cdot\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}\cdot\dfrac{1}{4}+3\cdot\left(\dfrac{8}{15}+\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{15}+3\cdot\dfrac{37}{20}\cdot\dfrac{24}{47}\)
\(=\dfrac{7}{15}+\dfrac{666}{235}=\dfrac{2327}{705}\)
\(1\dfrac{13}{15}.\left(0,5\right)^2+3.\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}.\dfrac{1}{4}+3.\left(\dfrac{8}{15}+\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{15}+3.\dfrac{37}{20}:\dfrac{47}{24}\)
\(=\dfrac{7}{15}+\dfrac{666}{235}\)
\(=\dfrac{2327}{705}\)
Thực hiện phép tính sau:
2) \(B=\dfrac{13}{15}.0,15.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(B=\dfrac{13}{15}\cdot0,15\cdot3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):\left(1\dfrac{23}{24}\right)\)
\(=\dfrac{13}{15}\cdot\dfrac{15}{100}\cdot3+\left(\dfrac{32}{60}-1-\dfrac{19}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{39}{100}+\dfrac{-47}{60}\cdot\dfrac{24}{47}\)
\(=\dfrac{39}{100}-\dfrac{24}{60}=\dfrac{39}{100}-\dfrac{40}{100}=-\dfrac{1}{100}\)
E=1/13/15 × 0,25 × 3 +(8/15+1/19/60) : 1/23/24 - 81/235
Mấy pạn giúp mk với !!! Please