A = - 3\(x\).(\(x-5\)) + 3(\(x^2\) - 4\(x\)) - 3\(x\) - 10

A = - 3\(x^2\) + 15\(x\) + 3\(x^2\) - 12\(x\) - 3\(x\) - 10

A = (- 3\(x^2\) + 3\(x^2\)) + (15\(x\) - 12\(x\) - 3\(x\)) - 10

A = 0 + (3\(x-3x\)) - 10

A = 0  - 10

A = - 10 

x=-36

x=11

x=100

x=14

x=-36

x=11

x=100

x=14

2: \(\Leftrightarrow\left(\dfrac{x+1}{12}-1\right)+\left(\dfrac{x+2}{13}-1\right)=\left(\dfrac{x+3}{14}-1\right)+\left(\dfrac{x+4}{15}-1\right)\)

=>x-11=0

=>x=11

3: \(\Leftrightarrow\left(\dfrac{x-85}{15}-1\right)+\left(\dfrac{x-74}{13}-2\right)+\left(\dfrac{x-67}{11}-3\right)+\left(\dfrac{x-64}{9}-4\right)=0\)

=>x-100=0

=>x=100

1) PT \(\Leftrightarrow\left(\dfrac{x+1}{35}+1\right)+\left(\dfrac{x+3}{33}+1\right)=\left(\dfrac{x+5}{31}+1\right)+\left(\dfrac{x+7}{29}+1\right)\)

\(\Leftrightarrow\dfrac{x+36}{35}+\dfrac{x+36}{33}=\dfrac{x+36}{31}+\dfrac{x+36}{29}\)

\(\Leftrightarrow\left(x+36\right)\left(\dfrac{1}{29}+\dfrac{1}{31}-\dfrac{1}{33}-\dfrac{1}{35}\right)=0\)

\(\Leftrightarrow x+36=0\) (Do \(\dfrac{1}{29}+\dfrac{1}{31}-\dfrac{1}{33}-\dfrac{1}{35}>0\))

\(\Leftrightarrow x=-36\).

Vậy nghiệm của pt là x = -36.

2) x(x+1)(x+2)(x+3)= 24

⇔ x.(x+3)  .   (x+2).(x+1)  = 24

⇔(\(x^2\) + 3x) . (\(x^2\) + 3x + 2) = 24

Đặt \(x^2\)+ 3x = b

⇒ b . (b+2)= 24

Hay: \(b^2\) +2b = 24

⇔\(b^2\) + 2b + 1 = 25

⇔\(\left(b+1\right)^2\)= 25

+ Xét b+1 = 5 ⇒ b=4 ⇒  \(x^2\)+ 3x = 4 ⇒ \(x^2\)+4x-x-4=0 ⇒x(x+4)-(x+4)=0

⇒(x-1)(x+4)=0⇒x=1 và x=-4

+ Xét b+1 = -5 ⇒ b=-6 ⇒ \(x^2\)+3x=-6 ⇒\(x^2\) + 3x + 6=0

⇒\(x^2\) + 2.x.\(\dfrac{3}{2}\) + (\(\dfrac{3}{2}\))² = - \(\dfrac{15}{4}\)  Hay ( \(x^2\) +\(\dfrac{3}{2}\) )²= -\(\dfrac{15}{4}\) (vô lí)

⇒x= 1 và x= 4

a, 5^x+7 = 125

<=> 5^x+7 = 5³

=> x+7 = 3

<=> x = 3-7

<=> x = -4

b,

<=> 7^-10-x = 50-1

<=> 7^-10-x = 49

<=> 7^-10-x = 7²

=> -10-x = 2

<=> x = -10-2

<=> x = -12

c,

<=> x = 35-45

<=> x = -10

d,

<=> 6x = -5,6

<=> x = -5,6 ( Vô lí vì -5,6 không chia hết cho 6)

Vậy không tồn tại giá trị của x thỏa mãn đề bài

e,

<=> 7-10 = 3x-2x

<=> x = -3

f, 

<=> -15-9 = 3x-2x

<=> x = -24

a, 4x+18:2 = 13

4x+9 = 13

x = 1

b, 48 – 3(x+5) = 24

3(x+5) = 24

x + 5 = 8

x = 3

c,  2 x - 2 0 = 3 5 : 3 3

2x – 1 =  3 2

2x = 10

x = 5

d, (15+x):3 =  3 15 : 3 12

(15+x):3 =  3 3

(15+x):3 = 27

15 + x = 54

x = 39

\(17\left(5-2x\right)-3\left(4x+1\right)-5x=-9.\)

\(85-34x-12x-3-5x=-9\)

\(85+9-3=34x+12x+5x\)

\(91=51x\)

\(x=\frac{91}{51}\)

\(35-\left(x-7\right)=-7-\left(27-8\right)\)

\(35-x+7=-7-27+8\)

\(35+7+7+27-8=x\)

\(x=68\)