e) (x+5) + (x-9) = x+2

     x+5 + x -9    = x+2

     2x + 5 - 9     = x+2

            2x - 4    = x +2

               3x      = 2 +4

                3x     =6

                   x    = 2

f) (27-x) + ( 15+x) = x-24

   27-x + 15 +x      = x-24

   27 + 15 - (x - x) = x - 24

                     42   = x-24

                       x = 24 + 42

                        x = 66

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) . ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`( 2019 - x ) . ( 3x - 12 ) =0` `?`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}`

`e) `

`57 . ( 9x - 27 ) = 0`

`=>`\(9x-27=0\div57\)

`=> 9x - 27 = 0`

`=> 9x = 27`

`=> x = 27 \div 9`

`=> x = 3`

Vậy, `x = 3`

`f)`

`25 + ( 15 - x ) = 30`

`=> 15 - x = 30 - 25`

`=> 15 - x = 5`

`=> x = 15 -5 `

`=> x = 10`

Vậy, `x = 10`

`g) `

`43 - ( 24 - x ) = 20`

`=> 24 - x = 43 - 20`

`=> 24 - x = 23`

`=> x = 24 - 23`

`=> x = 1`

Vậy, `x = 1`

`h) `

`2 . ( x - 5 ) - 17 = 25`

`=> 2 ( x - 5) = 25+17`

`=> 2 ( x - 5) = 42`

`=> x - 5 = 42 \div 2`

`=> x - 5 = 21`

`=> x = 21 + 5`

`=> x = 26`

Vậy, `x = 26`

`i)`

`3 . ( x + 7 ) - 15 = 27`

`=> 3(x + 7) = 27 + 15`

`=> 3(x + 7) = 42`

`=> x +7 = 42 \div 3`

`=> x + 7 = 14`

`=> x = 14 - 7`

`=> x = 7`

Vậy, `x = 7`

`j)`

`15 + 4 . ( x - 2 ) = 95`

`=> 4(x - 2) = 95 - 15`

`=> 4(x - 2) = 80`

`=> x - 2 = 80 \div 4`

`=> x - 2 = 20`

`=> x = 20 + 2`

`=> x = 22`

Vậy, `x = 22`

`k)`

`20 - ( x + 14 ) = 5`

`=> x + 14 = 20 - 5`

`=> x + 14 = 15`

`=> x = 15 - 14`

`=> x = 1`

Vậy, `x = 1`

`l) `

`14 + 3 . ( 5 - x ) = 27`

`=> 3(5 - x) = 27 - 14`

`=> 3(5 - x) = 13`

`=> 5 - x = 13 \div 3`

`=> 5 - x = 13/3`

`=> x = 5- 13/3`

`=> x = 2/3`

Vậy, `x = 2/3.`

`@` `\text {Kaizuu lv uuu}`

nhanh mik tick cho nha

a)

\(x-5=-1\)

\(x=-1+5\)

\(x=4\)

b)

\(x+30=4\)

\(x=4-30\)

\(x=-26\)

c)

\(x-(-24)=3\)

\(x+24=3\)

\(x=3-24\)

\(x=-21\)

d)

\(22-(-x)=12\)

\(22+x=12\)

\(x=12-22\)

\(x=-10\)

e)

\(( x + 5 ) + ( x - 9 ) = x + 2\)

\(x+5+x-9=x+2\)

\(x+x-x=2+9-5\)

\(x=6\)

f)

\(( 27 - x ) + ( 15 + x ) = x - 24\)

\(27-x+15+x=x-24\)

\(-x+x-x=-24-15-27\)

\(-x=-66\)

\(x=66\)

x - 5 = -1                                         x  - (-24) = 3

x      = -1 + 5                                    x + 24 = 3

x     = 4                                             x         = 3 - 24

x + 30 =  4                                        x        = - 21

x         = 4 - 30                            22  - ( -x) = 12

x         = - 26                               22 + x     =  12

x + 5 + ( x - 9) = x + 2                         x     = 12 - 22          

x + 5 + x - 9    =  x + 2                         x    = -10

2x  - x             = 2 - 5 + 9              ( 27 - x) + ( 15 + x) = x - 24

x                     = - 3 + 9                    27 - x + 15 + x    = x - 24

x                     = 6                             27 + 15              = x - 24

                                                               x - 24 = 42  

                                                               x          = 42 + 24

                                                                x           = 66

(27-X)+(15+x)=x-24

27-x+15+x=x-24

-x+x-x=-24-27-15

-x=-66

x=-(-66)

x=66

a) x – 5 = - 1 ;

=>  x = -1 + 5 = 4

Vậy x = 4 

b) x + 30 = - 4;

=>  x = - 4 - 30 = - 34

Vậy x = - 34

c) x – ( - 24) = 3 ;

=> x + 24 = 3

=> x = 3 - 24 

=> x = - 21

Vậy x = - 21 

d) 22 – ( - x ) = 12;

=> 24 + x  = 12

=> x = 12 

Vậy x = 12

e) ( x + 5 ) + ( x – 9 ) = x + 2 ;

=> x + 5 +x - 9 = x + 2

=>  2x - x = 1 + 9 - 5

=> x = 5

Vậy x = 5

f) ( 27 – x ) + ( 15 + x ) = x – 24 .

=> 27 - x + 15 + x = x - 24

=> x + 42 = x - 24

=> x - x = 42 - 24

=> 0 = 8  ( vô lí)

Vậy x thuộc rỗng 

Rảnh nhỉ

@@ Học tốt

## Chiyuki Fujito

a) \(x-5=-1\Rightarrow x=\left(-1\right)+5=4\)

b) \(x+30=-4\Leftrightarrow x=\left(-4\right)-30=-34\)

c) \(x-\left(-24\right)=3\Rightarrow x+24=3\Leftrightarrow x=3-24=-21\)

d) \(22-\left(-x\right)=12\Leftrightarrow22+x=12\Leftrightarrow x=12-22=-10\)

e) \(\left(x+5\right)+\left(x-9\right)=x+2\Leftrightarrow x+5+x-9=x+2\)

\(\Rightarrow x+x-x=2-5+9\Leftrightarrow x=6\) Vậy \(x=6\)

f) \(\left(27-x\right)+\left(15+x\right)=x-24\Leftrightarrow27-x+15+x=x-24\)

\(\Leftrightarrow27+15+24=x+x-x=x\Leftrightarrow x=66\)   Vậy \(x=66\)

a) \(5\left(x-7\right)=0\)

\(\Rightarrow x-7=0\)

\(\Rightarrow x=7\)

b) \(25\left(x-4\right)=0\)

\(\Rightarrow x-4=0\)

\(\Rightarrow x=4\)

c) \(\left(34-2x\right)\left(2x-6\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

d) \(\left(2019-x\right)\left(3x-12\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)

e) \(57\left(9x-27\right)=0\)

\(\Rightarrow9x-27=0\)

\(\Rightarrow9\left(x-3\right)=0\)

\(\Rightarrow x-3=0\)

\(\Rightarrow x=3\)

a) 5.(x-7)=0⇔x-7=0⇔x=7

b) 25(x-4)=0⇔x-4=0⇔x=4

c) (34-2x).(2x-6)=0

⇔ 34-2x=0 hoặc 2x-6=0

⇔2x=34 hoặc 2x=6

⇔ x=17 hoặc x=3

d) (2019-x).(3x-12)=0

⇔ 2019-x=0 hoặc 3x-12=0

⇔ x=2019 hoặc x=4

e) 57.(9x-27)=0

⇔ 9x-27=0

⇔ x=3

f) 25+(15-x)=30

⇔ 15-x=5

⇔ x=10

g) 43-(24-x)=20

⇔ 24-x=23

⇔ x=1

h) 2.(x-5)-17=25

⇔ 2(x-5)=42

⇔x-5=21

⇔ x=26

i) 3(x+7)-15=27

⇔ 3(x+7)=42

⇔ x+7=14

⇔ x=7

j) 15+4(x-2)=95

⇔ 4(x-2)=80

⇔ x-2=20

⇔ x=22

k) 20-(x+14)=5

⇔ x+14=15

⇔ x=1

l) 14+3(5-x)=27

⇔ 3(5-x)=13

⇔ 5-x=13/3

⇔ x=5-13/3

⇔ x=2/3

Ta tách 9 x 24 ra 27 x 8

(77 + 8 + 15) x 27

= 100 x 27

= 2700

\(\left(27-x\right)+\left(15+x\right)=x-24\)

\(\Rightarrow27-x+15+x=x-24\)

\(\Rightarrow\left(27+15\right)-\left(x-x\right)=x-24\)

\(\Rightarrow42=x-24\)

\(\Rightarrow x=42+24\)

\(\Rightarrow x=66\)

Vậy \(x=66\)

\( 27 - x + 15 + x = x - 24\\ \Leftrightarrow 42 = x - 24\\ \Leftrightarrow x = 66 \)

(27 - x) + (15 + x) = x - 24

⇔ x - 24 = 42

⇔ x = 66

Vậy x = 66 là nghiệm của pt

tui lam dc roi :((((

a) 25. (x-4) = 0

=> x -4 =0 

x = 4

b) 43 - (24-x) = 20

43 - 24 + x = 20

19 + x = 20

x = 1

c) 3.(x+7) - 15 = 27

3.x + 21 - 15 = 27

3.x + 6 = 27

3.x = 21

x = 7

d)... bn ghi thiếu đề r

e) (2.x-6).(x-7) = 0

=> 2.x -6 = 0 => 2x = 6 => x = 3

x - 7 = 0 => x  = 7

KL: x = 3 hoặc x = 7

phần d lm tương tự như phần f nha bn!
 

a,25(x-4)=0

x-4=0

x=4

b,43-(24-x)=20

43-24+x=20

x=1

c,3(x+7)-15=27

3x+21-15=27

3x=21

x=7

d,(x-4)(x-12)=0

x-4=0=>x=4

x-12=0=>x=12

e,(2x-6)(x-7)=0

2x-6=0=>x=3

x-7=0=>x=7

f,(5x-10)(2x-8)=0

5x-10=0=>x=2

2x-8=0=>x=2

a) 25 ( x - 4 ) = 0

<=>     x - 4   = 0

<=>      x       = 4

Vậy x = 4

b) 43 - ( 24 - x ) = 20 

<=>       24 - x   = 43 - 20

<=>       24 - x   = 23

<=>              x   = 1

Vậy x = 1

c) 3( x + 7 ) - 15 = 27 

<=> 3 ( x + 7 )    = 27 + 15

<=> 3 ( x + 7 )    = 42

<=>       x + 7     = 42 : 3

<=>       x + 7     = 14

<=>        x          = 7

Vậy x = 7

d)

e) ( 2x - 6 ) ( x - 7 ) = 0

\(\Leftrightarrow\) \(\orbr{\begin{cases}2x-6=0\\x-7=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}2x=6\\x=7\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=7\end{cases}}\)

Vậy x = 3 ; x = 7

f) ( 5x - 10 ) ( 2x - 8 ) = 0

\(\Leftrightarrow\orbr{\begin{cases}5x-10=0\\2x-8=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}5x=10\\2x=8\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=4\end{cases}}\)

Vậy x = 2 ; x = 4