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= (-3/17+ -32/17)+(2/15+15/15+1)
=-2+2
=0

Giúp tớ với tớ cần gấp

a: \(=\dfrac{-5}{7}-\dfrac{2}{7}+\dfrac{3}{4}+\dfrac{1}{4}-\dfrac{1}{5}=-\dfrac{1}{5}\)

b: \(=\dfrac{-3}{31}-\dfrac{28}{31}+\dfrac{-6}{17}-\dfrac{11}{17}+\dfrac{1}{29}-\dfrac{1}{5}=\dfrac{-24}{145}\)

\(a)\)

\(\left(-31\right)+\left(50-19\right)-\left(150-31\right)\)

\(=\left(-31\right)+50-19-150+31\)

\(=\left(-150\right)-19\)

\(=-169\)

\(b)\)

\(25.\left(45-17\right)-45.\left(25-17\right)\)

\(=25.45-25.17-45.25+45.17\)

\(=0\)

\(c)\)

\(\frac{-1}{12}+\frac{4}{3}=\frac{5}{4}\)

\(d)\)

\(3+\frac{-5}{20}+\frac{30}{75}+\frac{-7}{4}\)

\(=\left(\frac{3}{5}+\frac{30}{75}\right)-\left(\frac{5}{20}+\frac{7}{4}\right)\)

\(=1-2\)

\(=-1\)

a) (-31)+(50-19)-(150-31)

= (-31)+50+(-19)-150+(-31)
= (-31)+50-150+(-19)-(-31)
= (-31)+(-100)+12
= -119
b) 25(45-17)-45(25-17)
= 25.45-25.17-45.25-45.17
= 25(45-45)-25(17-17)
= 0
c) -1/12 + 4/3
= -1/12 + 16/12
= 15/12
= 5/4
d) 3/5+(-5)/20+30/75+(-7)/4
= 45/75+30/75+(-5)/20+(-35)/20
= 1+(-2)
= -1

\(a.\)

\(\dfrac{27}{13}-\dfrac{106}{111}+-\dfrac{5}{111}=\dfrac{27}{13}-\dfrac{106}{111}-\dfrac{5}{111}=\dfrac{27}{13}-\left(\dfrac{106+6}{111}\right)=\dfrac{27}{13}-1=\dfrac{14}{13}\)

\(b.\)

\(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+1=\dfrac{23}{11}\)

\(c.\)

\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+-\dfrac{6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)-\left(\dfrac{25}{31}+\dfrac{6}{31}\right)=1-1=0\)

a) \(\dfrac{27}{13}-\dfrac{106}{111}+\dfrac{-5}{111}=\dfrac{27}{13}+\left(\dfrac{-106}{111}+\dfrac{-5}{111}\right)=\dfrac{27}{13}+-1=\dfrac{14}{13}\) 

b) \(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\left(\dfrac{7}{19}+\dfrac{12}{19}\right)=\dfrac{12}{11}+1=\dfrac{23}{11}\) 

c)\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+\dfrac{-6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{-25}{31}+\dfrac{-6}{31}\right)=1+-1=0\)

a) 4.(1 930 + 2 019) + 4.(-2 019)

= 4.(1 930 + 2 019 - 2 019)

= 4.1 930

= 7 720

b) (-3).(-17) + 3.(120 - 17)

= 3.17 + 3.(120 - 17)

= 3.(17 + 120 - 17)

= 3.120

= 360

\(\dfrac{5}{3}\times\dfrac{3}{17}+\dfrac{3}{17}\times\dfrac{1}{3}-\dfrac{3}{17}\times2\)

\(=\dfrac{3}{17}\times\left(\dfrac{5}{3}+\dfrac{1}{3}+2\right)=\dfrac{3}{17}\times4=\dfrac{12}{17}\)

\(a,18.17-3.6.7\)

\(=18.17-18.7\)

\(=18.\left(17-7\right)\)

\(=18.10\)

\(=180\)

\(b,54-6.\left(17+9\right)\)

\(=54-6.17+6.9\)

\(=54-102+54\)

\(=\left(54+54\right)-102\)

\(=108-102\)

\(=6\)

\(c,33.\left(17-5\right)-17.\left(33-5\right)\)

\(=33.17-33.5-17.33-17.5\)

\(=\left(33.17-17.33\right)-\left[5\left(33-17\right)\right]\)

\(=0-5.16\)

\(=-80\)

a) \(18.17-3.6.7\)

\(=18.17-18.7\)

\(=18.\left(17-7\right)\)

\(=18.10\)

\(=180\)

b) \(54-6.\left(17+9\right)\)

\(=54-102-54\)

\(=-102\)

c) \(33.\left(17-5\right)-17.\left(33-5\right)\)

\(=561-165-561+85\)

\(=-80\)

a , 18 . 17 - 3 . 6 . 7

= 18 .17 - 18 . 7

= 18 . ( 17 - 7 )

= 18 . 10

= 180

b , 54 - 6 . ( 17 + 9 )

= 54 - 6 . 17 + 6 . 9

= 54 - 102 + 54

= ( 54 - 54 ) - 102

= 0 - 102

= - 102

c , 33 . ( 17 - 5 ) - 17 . ( 33 - 5 )

= 33 . 17 - 33 . 5 - 17 . 33 - 17 .5

= 0 - 5 . 16

= 0 - 80

= - 80

Lời giải:

$=3.17+(3.120-3.17)=3.17+3.120-3.17$

$=(3.17-3.17)+3.120=3.120=360$

-3.(-17)+3.(120-17)

= 3.17 + 3.120 - 3.17

= (3.17-3.17) + 3.120

= 0 + 360 = 360

Lời giải:

$-3(-17)+3(120-17)=3.17+3.120-3.17=3.120=360$