a) \(3^x-27.3^5.3^2=0\)

\(3^x-3^3.3^5.3^3=0\)

\(3^x=3^{13}\)

\(x=13\)

b) \(\left(-5+3x\right):4=16\)

\(-5+3x=64\)

\(3x=69\)

\(x=23\)

a: \(\Rightarrow10x^2+9x-\left(10x^2+15x-2x-3\right)=8\)

\(\Leftrightarrow10x^2+9x-10x^2-13x+3=8\)

=>-4x=5

hay x=-5/4

b: \(\Leftrightarrow21x-15x^2-35+25x+15x^2-10x+6x-4-2=0\)

=>42x=41

hay x=41/42

`a)(10x+9)x-(5x-1)(2x+3)=8`

`<=>10x^2+9x-10x^2-15x+2x+3=8`

`<=>-4x=5`

`<=>x=-5/4`     Vậy `S={-5/4}`

`b)(3x-5)(7-5x)+(5x+2)(3x-2)-2=0`

`<=>21x-15x^2-35+25x+15x^2-10x+6x-4-2=0`

`<=>42x=41`

`<=>x=41/42`       Vậy `S={41/42}`

a: 

=>-4x=5

hay x=-5/4

b: 

=>42x=41

hay x=41/42

\(\dfrac{4}{5}\times\dfrac{5}{8}=\dfrac{20}{40}=\dfrac{1}{2}\)

\(\dfrac{7}{15}+\dfrac{4}{5}=\dfrac{7}{15}+\dfrac{12}{15}=\dfrac{19}{15}\)

\(\dfrac{2}{3}-\dfrac{3}{8}=\dfrac{16}{24}-\dfrac{9}{24}=\dfrac{7}{24}\)

\(\dfrac{1}{2}\div\dfrac{2}{5}=\dfrac{1}{2}\times\dfrac{5}{2}=\dfrac{5}{4}\)

1/2

19/15

7/24

5/4

4/5 x 5/8

= 20/40

= 1/2

7/15 + 4/5

= 7/15 + 12/15

= 19/15

2/3 - 3/8

= 16/24 - 9/24

= 7/24

1/2 : 2/5

= 1/2 x 5/2

= 5/4

1) 2x.(5x-3x)+2x.(3x-5)-3.(x-7)=3

   10x-6x^2+6x^2-10x-3x+21=3

    -3x                             =-18

suy ra x=6

2) 3x.(x+1) -2x.(x+2)=-1-x

     3x^2 +3x-2x^2-4x =-1-x

     x^2 =-1

suy ra không có giá trị nào của x thỏa mãn đề bài

3) 2x^2 +3.(x^2-1)=5x(x+1)

  2x^2 +3x^2-3 =5x^2+5x

  -5x      =3

x=-3/5

giải rồi đấy

nhớ tích đúng nha :)

bạn coi lại đề câu 1 đi

a) \(5\times x-123=12\)

\(\Rightarrow5\times x=135\)

\(\Rightarrow x=27\)

b) \(x+3x+5x+7x=96\)

\(\Rightarrow16x=96\)

\(\Rightarrow x=6\)

a) \(5\times x-123=12\)

\(5x=12+123\)

\(5x=135\)

\(x=135:5\)

\(x=27\)

________

b) \(x+3x+5x+7x=96\)

\(x\left(1+3+5+7\right)=96\)

\(x.16=96\)

\(x=96:16\)

\(x=6\)

a)

\(5\times x-123=12\\\Rightarrow 5\times x=12+123\\\Rightarrow 5\times x=135\\\Rightarrow x=135:5\\\Rightarrow x=27\\---\)

b) 

\(x+3x+5x+7x=96\\\Rightarrow16x=96\\\Rightarrow x=96:16\\\Rightarrow x=6\)

\(5x\left(x-2018\right)-x+2018=0\)

\(5x\left(x-2018\right)-\left(x-2018\right)=0\)

\(\left(x-2018\right)\left(5x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-2018=0\\5x-1=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=2018\\x=\frac{1}{5}\end{cases}}\)

Vậy.........

x = 2018

x = 1/5

t i c k nha

\(5x\left(x-2018\right)-x+2018=0\)

\(\Leftrightarrow5x\left(x-2018\right)-\left(x-2018\right)=0\)

\(\Leftrightarrow\left(x-2018\right)\left(5x-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-2018=0\\5x-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=2018\\x=\frac{1}{5}\end{cases}}\)

+)  -11-|25-x|=(-8).2

      -11-|25-x|=-16

      |25-x|=5

       \(\Leftrightarrow\)\(\orbr{\begin{cases}25-x=5\\25-x=-5\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=20\\x=30\end{cases}}\)

Vậy x \(\in\){20;30}

+)  3x²-53=-5

      3x²=48

      x²=16

       x=\(\pm\)4

Vậy x=\(\pm\)4

+)   5x⁵+12=-148

       5x⁵ = -160

           x⁵= -32

           x= -2

Vậy x= -2

+)   3.(-2)^x -5 = -101

      3.(-2)^x = -96

       (-2)^x = -32

         (-2)^x= (-2)⁵

          x=5

Vậy x=5

Chúc bạn học tốt

\(-11-\left|25-x\right|=\left(-8\right).2\)

\(\Rightarrow\left|25-x\right|=5\)

\(\Leftrightarrow\orbr{\begin{cases}25-x=5\\25-x=-5\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=20\\x=30\end{cases}}\)

\(3x^2-53=-5\)

\(\Rightarrow3x^2=48\)

\(\Rightarrow x^2=16\)

\(\Rightarrow x=\pm4\)

\(5x^5+12=-148\)

\(5x^5=-160\)

\(\Rightarrow x^5=-32\)

\(\Rightarrow x=-2\)

\(3\left(-2\right)^x-5=-101\)

\(\Rightarrow3.\left(-2\right)^x=-96\)

\(\Rightarrow\left(-2\right)^x=-32=\left(-2\right)^5\)

\(\Rightarrow x=5\)