a) \(5x+x=39-3^{11}:3^9\)    

\(\Leftrightarrow6x=39-3^2\)                    

\(\Leftrightarrow6x=30\)

\(\Leftrightarrow x=5\)

b) \(2^x:2^5=16\)

\(\Leftrightarrow2^x:2^5=2^4\)

\(\Leftrightarrow2^x=2^4.2^5\)

\(\Leftrightarrow2^x=2^9\)

\(\Leftrightarrow x=9\)

c) \(7x-x=5^{21}:5^{19}+3.2^2-7^0\)

\(\Leftrightarrow6x=5^2+3.4-1\)

\(\Leftrightarrow6x=36\)

\(\Leftrightarrow x=6\)

d) \(7x-2x=6^{17}:6^{15}+44:11\)

\(\Leftrightarrow5x=6^2+4\)

\(\Leftrightarrow5x=40\)

\(\Leftrightarrow x=8\)

a)⇔6x=39-3²                                             

   ⇔6x=30                                             

   ⇔ x=5                                                

b)2^x:2⁵=16

⇔2^x=2⁴.2⁵ 

⇔ 2^x=2⁹                                                   

⇔ x=9

c)⇔6x=5²+3.2²-1

  ⇔ 6x= 36

  ⇔ x=6

d)⇔5x=6²+4

   ⇔ 5x=40

   ⇔ x=8

a: \(\Leftrightarrow6x=30\)

hay x=5

b: \(\Leftrightarrow6x=25+12-1=36\)

hay x=6

A x=5

B x = 6 (36)

a: \(\Leftrightarrow8x=108+12=120\)

hay x=15

b: \(\Leftrightarrow6x=60\)

hay x=10

a) 5x + 3x = 120
    x . (5+3)= 120
    x . 8       = 120
    x            = 120 : 8
    x            = 15

c) 7x - 2x = 40
    x .(7-2)= 40
    x . 5     = 40

    x          = 40 : 5
    x          = 8

=>6x=30

hay x=5

7x - x = 30
7.x - 1.x = 30
x . (7-1) = 30
x . 6 = 30

x      = 30 : 6
x      = 5

DỄ ƠI LÀ DỄ

\(7x-x=5^{21}:5^{19}+3.2^2-7^0\)

\(6x=5^2+3.2-1\)

\(6x=25+12-1\)

\(6x=36\)

\(x=6\)

K bt đk:))
Ta có :
7x - x = 5²¹ : 5¹⁹ . 3 . 2² - 70

=> 6x = 5²¹: 5¹⁹ + 3 . 2² - 70

=> 6x = 5² + 3. 4 - 1

=> 6x = 25 + 3 . 2 - 1

=> 6x = 25 + 6 - 1

=> 6x = 30

=> x = 30 : 6

=> x = 5

7x−x=521:519+3.22−70

6x=52+3.2−16x=52+3.2−1

6x=25+12−16x=25+12−1

6x=366x=36

x=6

a) 89-(73-x) = 20

=> 73+x =89-20

=> 73+x=69

=> x=69-73

=> x=-4

b) (x+7)-25=13

=> x+7=13+25

=> x+7=38

=> x=38-7

=> x=31

c) 98-(x+4)=20

=> x+4=98-20

=> x+4=78

=> x=78-4

=> x=73

d) 140:(x-8)=7

=> x-8=140:7

=> x-8=20

=> x=20+8

=> x=28

e) 4(x+41)=400

=> x+41=400:4

=> x+41=100

=> x=100-41

=> x=59

f) x-[42+(-28)]=-8

=> x-14=-8

=> x=-8+14

=> x=6

g) x+5=20-(12-7)

=> x+5=20-5

=> x+5=15

=> x=15-5

=> x=10

h) \(x-11=2.2^3+20:5\)

=> x-11=2.8+4

=> x-11=16+4

=> x-11=20

=> x=20+11

=> x=31

i) \(4\left(x-3\right)=7^2-1^3\)

=> 4(x-3)=49-1

=> 4(x-3)=48

=> x-3=48:4

=> x-3=12

=> x=12+3

=> x=15

\(7x-2x=6^{17}:6^{15}+4:11\\ \Rightarrow5x=6^2+\dfrac{4}{11}\\ \Rightarrow5x=36+\dfrac{4}{11}\\ \Rightarrow5x=\dfrac{400}{11}\\ \Rightarrow x=\dfrac{80}{11}\)

Phân tích đa thức thành nhân tử(tách hạng tử)
1)x^2+2x-3=x^2-x+3x-3=x(x-1)+3(x-1)=(x-1)(x+3)
2)x^2-5x+6=x^2-2x-3x+6=x(x-2)-3(x-2)=(x-2)(x-3)
3)x^2+7x+12=(x+3)(x+4)
4)x^2-x-12=(x-4)(x+3)
5)3x^2+3x-36=3[(x-3)(x+4)]
6)5x^2-5x-10=5[(x-2)(x+1) ]       
7)3x^2-7x-6=(x-3)(3x+2)
8)4x^2+4x-3=4x^2+6x-2x-3=(2x-1)(2x+3)
9)8x^2-2x-3=8x^2+4x-6x-3=(4x-3)(2x+1)
 

1: \(x^2+2x-3=\left(x+3\right)\left(x-1\right)\)

2: \(x^2-5x+6=\left(x-2\right)\left(x-3\right)\)

3: \(x^2+7x^2+12x=4x\left(2x+3\right)\)

4: \(x^2-x-12=\left(x-4\right)\left(x+3\right)\)

5: \(3x^2+3x-36=3\left(x^2+x-12\right)=3\left(x+4\right)\left(x-3\right)\)

6: \(5x^2-5x-10=5\left(x^2-x-2\right)=5\left(x-2\right)\left(x+1\right)\)

a) x=60

b) x=107

f) x=2

.....

CHO MÌNH BIẾT CẢ CÁCH LÀM NHA

a) 315 + ( 146 - x ) = 401

<=> 146 - x = 401 - 315

<=> 146 - x = 86

<=> x = 60

Vậy x  = 60