q+1/q-3= .../q^2-4q+3= .../q^3-27 với q # 1 và q # 3
Hoàn thành chuỗi đẳng thức sau: q + 1 q − 3 = . .. q 2 − 4 q + 3 = . .. q 3 − 27 với q ≠ 1 và q ≠ 3.
\(\sqrt{27}-\sqrt{5\frac{1}{3}}\)\(+4,5\sqrt{2\frac{2}{3}}\)\(+2\sqrt{27}\)
giúp mk với
Ta có:
\(\sqrt{27}-\sqrt{5\frac{1}{3}}+4,5\sqrt{2\frac{2}{3}}+2\sqrt{27}\)
\(=3\sqrt{3}-\sqrt{\frac{16}{3}}+4,5\sqrt{\frac{8}{3}}+6\sqrt{3}\)
\(=9\sqrt{3}+\frac{4\sqrt{3}}{3}+3\sqrt{6}\)
\(=\frac{9\sqrt{6}+31\sqrt{3}}{3}\)
\(\sqrt{27}-\sqrt{5\frac{1}{3}}+4,5\sqrt{2\frac{2}{3}}+2\sqrt{27}\)
\(=\sqrt{27}-\sqrt{16.\frac{1}{3}}+4,5.\sqrt{4.\frac{1}{3}}+2\sqrt{27}\)
\(=\sqrt{27}-4\sqrt{\frac{1}{3}}+9\sqrt{\frac{1}{3}}+2\sqrt{27}\)
\(=\sqrt{27}-4\sqrt{\frac{1}{3}}+\sqrt{27}+2\sqrt{27}\)
\(=4\sqrt{27}-4\sqrt{\frac{1}{3}}\)
\(=\sqrt{54}-\sqrt{\frac{2}{3}}\)
1.\(\frac{10+2\sqrt{10}}{\sqrt{5}+\sqrt{2}}\) + \(\frac{8}{1-\sqrt{5}}\)
2.\(\frac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}\)- \(\frac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\)
3.\(\sqrt{\frac{2-\sqrt{3}}{2+\sqrt{3}}}\)+\(\sqrt{\frac{2+\sqrt{3}}{2-\sqrt{3}}}\)
4.\(2\sqrt{\frac{16}{3}}\)- \(3\sqrt{\frac{1}{27}}\)-\(6\sqrt{\frac{4}{75}}\)
5.\(2\sqrt{27}\)- \(6\sqrt{\frac{4}{3}}\)+\(\frac{3}{5}\sqrt{75}\)
6.\(\frac{\sqrt{3-\sqrt{5}}\times\left(3+\sqrt{5}\right)}{\sqrt{10}+\sqrt{2}}\)
Mn giúp mình với ạ mình cần gấp
1. \(\sqrt{3}\) - \(2\sqrt{12}\) + \(3\sqrt{27}\) - \(4\sqrt{48}\) + \(5\sqrt{75}\)
2. \(\sqrt{175}\) - \(2\sqrt{112}\) - \(3\sqrt{63}\) - \(2\sqrt{28}\) + \(\sqrt{7}\)
3. \(3\sqrt{75}\) - \(\frac{12}{\sqrt{2}}\) - \(30\sqrt{1\frac{1}{3}}\) + \(\sqrt{75}\)
4. (\(2\sqrt{3}\) -\(\sqrt{12}\) +\(2\sqrt{27}\) ) : \(3\sqrt{3}\)
5. (\(4\sqrt{2}\) - \(\sqrt{72}\) - \(3\sqrt{50}\) ) \(\sqrt{2}\) -\(4\sqrt{25}\) + \(1\)
1/ \(=\sqrt{3}-4\sqrt{3}+9\sqrt{3}-16\sqrt{3}+25\sqrt{3}=15\sqrt{3}\)
2/ \(=5\sqrt{7}-8\sqrt{7}-9\sqrt{7}-4\sqrt{7}+\sqrt{7}=-15\sqrt{7}\)
3/ \(=15\sqrt{3}-6\sqrt{2}-20\sqrt{3}+5\sqrt{3}=6\sqrt{2}\)
4/ \(=\left(2\sqrt{3}-2\sqrt{3}+6\sqrt{3}\right):3\sqrt{3}=2\)
5/ \(=\left(4\sqrt{2}-6\sqrt{2}-15\sqrt{2}\right)\sqrt{2}-20+1=-53\)
Rút gọn biểu tính giá trị biểu thức
a/ \(\left(x-10\right)^2-x\left(x+80\right)\) với \(x=0,98\)
b/ \(\left(2x+9\right)^2-x\left(4x+31\right)\) với \(x=-16,2\)
c/ \(4x^2-28x+49\) với \(x=4\)
d/ \(x^3-9x^2+27x-27\) với \(x=5\)
e/ \(9x^2+42x+49\)với \(x=1\)
f/ \(25x^2-2xy+\frac{1}{25}y^2\) với \(x=-\frac{1}{5}\), \(y=-5\)
g/ \(27+\left(x-3\right)\left(x^2+3x+9\right)\) với \(x=-3\)
h/ \(x^3+3x^2+3x+1\) với \(x=99\)
\(\sqrt[3]{2+10\sqrt{\frac{1}{27}}}\) + \(\sqrt[3]{2+10\sqrt{\frac{1}{27}}}\)
E = \(\sqrt[3]{4+\frac{5}{3}\sqrt{\frac{31}{3}}}\)+ \(\sqrt[3]{4-\frac{5}{3}\sqrt{\frac{31}{3}}}\)
\(E=\)( ghi đề vào đây )
\(E=\sqrt[3]{4+\frac{5}{3}.\frac{\sqrt{31}}{\sqrt{3}}}+\sqrt[3]{4-\frac{5}{3}.\frac{\sqrt{31}}{3}}\)
\(E=\sqrt[3]{4+\frac{5\sqrt{31}}{3\sqrt{3}}}+\sqrt[3]{4+\frac{5.\sqrt{31}}{3\sqrt{3}}}\)
\(E\approx1\)
\(E^3=4+\frac{5}{3}\sqrt{\frac{31}{3}}+4-\frac{5}{3}\sqrt{\frac{31}{3}}+3\sqrt[3]{\left(16-\frac{25}{9}.\frac{31}{3}\right)}\left(\sqrt[3]{4+\frac{5}{3}\sqrt{\frac{31}{3}}}+\sqrt[3]{4-\frac{5}{3}\sqrt{\frac{31}{3}}}\right)\)
\(\Leftrightarrow E^3=8-7E\)
\(\Leftrightarrow E^3+7E-8=0\)
\(\Leftrightarrow\left(E-1\right)\left(E^2+E+8\right)=0\)
\(\Leftrightarrow E=1\)
Tính giá trị biểu thức
A = \(\sqrt[3]{6\sqrt{3}+10}\)TRỪ \(\sqrt[3]{6\sqrt{3}-10}\)
B= \(\sqrt[3]{45+29\sqrt{2}}\) + \(\sqrt[3]{45-29\sqrt{2}}\)
C=\(\sqrt[3]{2+10\sqrt{\frac{1}{27}}}\)+ \(\sqrt[3]{2-10\sqrt{\frac{1}{27}}}\)
A = \(\sqrt[3]{10+6\sqrt{3}}+\sqrt[3]{10-6\sqrt{3}}\)
<=> A3 = 20 - 3×2A
<=> A3 + 6A - 20 = 0
<=> A = 2
bài 1 tính nhanh
a) 3\(\frac{1}{417}\). \(\frac{1}{762}\)-\(\frac{1}{139}\).\(4\frac{761}{762}\)-\(\frac{4}{417.762}\)+\(\frac{5}{139}\)
b) \(5\frac{4}{23}\). \(27\frac{3}{27}\)+ \(4\frac{8}{27}\).\(-5\frac{4}{23}\)
c) \(3\frac{10}{99}\). \(6\frac{1}{4}\)+ \(3\frac{2}{5}\).\(3\frac{3}{4}\)
bài 2 tính tổng
S= 1+2+5+14+...+ \(\frac{3^n+1}{2}\)
Bài 1:Tính
a) \((\frac{1}{2})^3.\left(\frac{1}{4}\right)^2\)
b)\(27^3:9^3\)
c)\(125^2:25^3\)
d)\(\frac{27^2.8^5}{6^6.32^3}\)
a,=1/8*1/16=1/108
b,=(27/9)^3=3^3=27
c,=125^2/25^2*25=5^2*25=25*25=225