10101 x ( \(\frac{5}{111111}+\frac{5}{222222}+\frac{5}{3x7x11x13x37}\) )
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\(C=10101\left(\frac{5}{111111}+\frac{5}{222222}+\frac{4}{111111}\right)\)
C=10101(10/222222+5/222222+8/222222)
C=10101.23/222222
C=232323/222222
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10101.(\(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\))
111111=3.7.11.13.37
222222=2.3.7.11.13.37
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10101 x \(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
B= 10101.\(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(B=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)
\(=10101\cdot\left(\dfrac{2}{222222}+\dfrac{5}{222222}\right)\)
\(=10101\cdot\dfrac{1}{31746}=\dfrac{7}{22}\)
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\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)
\(A=10101.\left(\frac{10}{222222}+\frac{5}{222222}-\frac{8}{222222}\right)\)
\(A=10101.\left(\frac{7}{222222}\right)\)
\(A=\frac{70707}{222222}\)
\(A=\frac{7}{22}\)
Vậy A = \(\frac{7}{22}\)
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Xem thêm câu trả lời
Tính:
10101 . \(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
10101 . \(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
= 10101 . \(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)
= 10101 . \(\frac{7}{222222}\)
= \(\frac{7}{22}\)
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Lời giải:
Ta có:
\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)
\(=10101.\left(\frac{10}{222222}+\frac{5}{222222}-\frac{8}{222222}\right)\)
\(=10101.\left(\frac{10+5-8}{222222}\right)\)
\(=10101.\frac{7}{222222}\)
\(=\frac{7.10101}{22.10101}=\frac{7}{22}\)
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\(10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)
\(=10101.\frac{7}{222222}\)
\(=\frac{7}{22}.\)
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\(10101.\left(\frac{5}{111111}+\frac{5}{222222}\frac{4}{3.7.11.13.37}\right)\)
=\(10101.\left(\frac{5}{111111}+\frac{5}{222222}.\frac{4}{111111}\right)\)
=\(10101.\left(\frac{5}{111111}+\frac{20}{24691308642}\right)\)
=\(10101.\frac{1111130}{24691308642}\)
=0,4545........
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\(C=10101\left(\frac{5}{111111}+\frac{5}{222222}+\frac{4}{3.7.11.13.37}\right)\)