\(2^2\cdot3\left(x+5\right)-6^2=\left(2^3+2^2\right)\cdot2^2\)

\(\Rightarrow4\cdot\left(3x+15\right)-36=12\cdot4\)

\(\Rightarrow12x+60-36=48\)

\(\Rightarrow12x+24=48\)

\(\Rightarrow12x=24\)

\(\Rightarrow x=24:12=2\)

22⋅3(x+5)−62=(23+22)⋅22

$\Rightarrow 4\cdot \left(3x+15\right)-36=12\cdot 4$

$\Rightarrow 12x+60-36=48$

$\Rightarrow 12x+24=48$

$\Rightarrow 12x=24$

$\Rightarrow x=24:12=2$

\(\left(x+6\right)^3=64\)

\(\Leftrightarrow\left(x+6\right)^3=4^3\)

\(\Leftrightarrow x+6=4\)

\(\Leftrightarrow x=-2\)

\(\left(x+6\right)^3=64\)

\(\sqrt[3]{\left(x+6\right)^3}=\sqrt[3]{64}\)

\(x+6=4\)

\(x=-2\)

`@` `\text {Ans}`

`\downarrow`

`(2^2+1) \times (x+14) = 5^2 \times 4 + (2^5 + 3^2 + 7^2) \div 2`

` \Rightarrow (4+1) \times (x+14) = 5^2\times 2^2 + ( 32 + 9 + 49) \div 2`

`\Rightarrow 5 \times (x+14) = (5*2)^2 + (32+58) \div 2`

`\Rightarrow 5 \times (x+14) = 10^2+90 \div 2`

`\Rightarrow 5 \times (x+14) = 100 + 45`

`\Rightarrow 5 \times (x+14) = 145`

`\Rightarrow x+14 = 145 \div 5`

`\Rightarrow x+14=29`

`\Rightarrow x=29-14`

`\Rightarrow x=15`

Vậy, `x=15.`

\(\left(2^2+1\right)\cdot\left(x+14\right)=5^2\cdot4+\left(2^5+3^2+7^2\right):2\)

\(\Rightarrow\left(4+1\right)\cdot\left(x+14\right)=25\cdot4+\left(32+9+49\right):2\)

\(\Rightarrow5\cdot\left(x+14\right)=100+45\)

\(\Rightarrow5x+70=145\)

\(\Rightarrow5x=75\)

\(\Rightarrow x=\dfrac{75}{5}=15\)

a) \(a^2\cdot a^3\cdot a^7\cdot b^2\cdot b\)

\(=\left(a^2\cdot a^3\cdot a^7\right)\cdot\left(b^2\cdot b\right)\)

\(=a^{12}\cdot b^3\)

b) \(b^6\cdot b\cdot c^7\cdot c^8\)

\(=\left(b^6\cdot b\right)\cdot\left(c^7\cdot c^8\right)\)

\(=b^7\cdot c^{15}\)

c) \(a^8\cdot a^9\cdot a\cdot c\cdot c^{20}\)

\(=\left(a^8\cdot a^9\cdot a\right)\cdot\left(c\cdot c^{20}\right)\)

\(=a^{18}\cdot c^{21}\)

d) \(a^2\cdot a^3\cdot b^4\cdot c\cdot c^3\)

\(=\left(a^2\cdot a^3\right)\cdot b^4\cdot\left(c\cdot c^3\right)\)

\(=a^5\cdot b^4\cdot c^4\)

a) Kiểm tra lại nhé

b) \(b^6.b^7.c^8\)

\(=b^{6+7}.c^8=b^{13}.c^8\)

c) \(a^8.a^9.a.c.c^{20}\)

\(=a^{8+9+1}.c^{1+20}\)

\(=a^{18}.c^{21}\)

d) \(a^2.a^3.b^4.c.c^3\)

\(=a^{2+3}.b^4.c^{1+3}\)

\(=a^5.b^4.c^4\)

\(#WendyDang\)

Câu b mình cũng không hiểu nha ( phần b mình làm bị sai á ).

`4x^2=13`

`<=>x^2=13/4`

`<=>x=[+-\sqrt{13}]/2`

Vậy `S={[+-\sqrt{13}]/2}`

`4x^2 = 13`.

`=> x^2 = 13/4`.

`=> x = (sqrt 13)/(sqrt 4)`

`=> x = (+-sqrt 13)/2`.

Vậy `S = (+-sqrt 13)/2`.

\(4x^2=13\)

\(x^2=52\)

\(x=\sqrt{52}\)

\(2^{x+1}-2^x=3^2\)

\(\Rightarrow2^x\cdot\left(2-1\right)=9\)

\(\Rightarrow2^x=9\)

\(\Rightarrow x\in\varnothing\)

\(2^{x+1}-2^x=3^2\)

=>2^x*2-2^x=9

=>2^x=9

=>\(x\in\varnothing\)

a)\(3^8:3^4+2^2.2^3\)\(=3^4+2^5\)

                                    \(=81+32\)

                                    \(=113\)

b)\(3.4^2-2.3=3.\left(4^2-3\right)\)

                          \(=3.13\)

                          \(=39\)

Học tốt nha!!!

a: \(=25x^4-10x^3+5x^2\)

c: \(=2x^3-3x-5x^3-x^2+x^2=-3x^3-3x\)