\(\left\{210:\left[16+3\cdot\left(6+3\cdot2^2\right)\right]\right\}\)

\(=210:\left[16+3\cdot\left(6+3\cdot4\right)\right]\)

\(=210:\left[16+3\cdot\left(6+12\right)\right]\)

\(=210:\left(16+3\cdot18\right)\)

\(=210:\left(16+54\right)\)

\(=210:70\)

\(=3\)

#Urushi

{210:[16+3.(6+3. 2^2)]}
={210:[16+3.(6+12)]}
={210:[16+3.18]}
={210:70}
=3

\(\left\{210:\left[16+3.\left(6+3.2^2\right)\right]\right\}-3\)

\(=\left\{210:\left[16+3.\left(6+12\right)\right]\right\}-3\)

\(=\left\{210:\left[16+3.18\right]\right\}-3\)

\(=\left\{210:\left[16+54\right]\right\}-3\)

\(=\left\{210:70\right\}-3=3-3=0\)

{210:[16+3.(6+3.2^2)]}-3
={210:[16+3.(6+3.4)]}-3
={210:[16+3.(6+12)]}-3
={210:[16+3.18)]}-3
={210:[16+54)]}-3
={210:70)]}-3
=30-3
=27

=27 nhớ tít

{210:[16+3.(6+3.2^2)]}-3

{210:[16+3.(6+3.4)]}-3

{210:[16+3.(6+12)]}-3

{210:[16+3.18)]}-3

{210:[16+54)]}-3

{210:70)]}-3

30-3

27

a: Ta có: \(142-\left[50-\left(2^3\cdot10-2^3\cdot5\right)\right]\)

\(=142-\left[50-80+40\right]\)

=142-10

=132

a. 142 - [50-(2³.10-2³.5)]

= 142 - [ 50 - ( 8 . 10 - 8 . 5 )]

= 142 - [ 50 - ( 80 - 40 )]

= 142 - [ 50 - 40 ]

= 142 - 10 = 132

b. 375 : { 32[ 4+(5.3² - 42 )]} - 14

= 375 : { 32[4+(5.9 - 42 )]} - 14

= 375 : { 32[4 + ( 45 - 42 )]} - 14

= 375 : {32[4+3]} - 14

= 375 : 224 - 14

c.{210 : [ 16+3.(6+3.2^2)]} - 3

= {210 : [ 16 + 3.(6+3.4)]} - 3

= { 210 :[16+3.(6+12)]}-3

= {210 : [ 16+3.18)]} - 3

= { 210 : [ 16 + 54]} - 3

= { 210 : 70 } - 3

= 30 - 3 = 27

d.500-{5.[409-(2^3 . 3-21^2)] - 1724}

= 500-{5.[409-(8 . 63 - 21^2] - 1724}

= 500 - { 5.[409- (504 -  441) - 1724}

= 500 -{ 5.[ 409 - 63 ] - 1724}

= 500 - { 5.346 - 1724}

= 500 - { 1720 - 1724 }

= 500 - 6 

= 494

a) 210:[16+3.(6+3.2^2)]-3

=210:[16+3.(6+3.4)]-3

=210:[16+3.(6+12)]-3

=210:[16+3.18]-3

=210:[16+54]-3

=210:70-3

=3-3

=0

\(500-\left\{5.\left[409.\left(2^3.3-21\right)^2\right]\right\}-3\)

500-{5.[409.(8.3-21)^2]}-3

500-{5.[409.(24-21)^2]}-3

500-{5.[409.3^2]}-3

500-{5.[409.9]}-3

500-{5.3681}-3

500-18405-3

...............

tự làm nốt nha

\(\left\{210:\left[16+3.\left(6+3.22\right)\right]\right\}-3\)

\(=\left\{210:\left[16+3.\left(6+66\right)\right]\right\}-3\)

\(=\left\{210:\left[16+3.72\right]\right\}-3\)

\(=\left\{210:\left[16+216\right]\right\}-3\)

\(=\left\{210:232\right\}-3\)

\(=\dfrac{105}{116}-3\)

\(=\dfrac{-243}{116}\)

1 , 10

2 , 8

3 , 5

4 , 2

5 , 1

6 ,

1/ `|x|=10<=> x=\pm 10`

2/ `|x-8|=0<=>x-8=0<=>x=8`

3/ `7+|x|=12<=>|x|=5<=>x=\pm 5`

4/ `|x+1|=3`

$\Leftrightarrow\left[\begin{array}{1}x+1=3\\x+1=-3\end{array}\right.\\\Leftrightarrow\left[\begin{array}{1}x=3\\x=-4\end{array}\right.$

5/ `15-x=16-(14-42)`

`<=>15-x=16+28`

`<=>15-x=44`

`<=>x=-29`

6/ `210-(x-12)=168`

`<=>210-x+12=168`

`<=>222-x=168`

`<=>x=54`

1.

\(\left|x\right|=10\Leftrightarrow x=\pm10\)

2.

\(\left|x-8\right|=0\Leftrightarrow x-8=0\Leftrightarrow x=8\)

3.

\(7+\left|x\right|=12\Leftrightarrow\left|x\right|=5\Leftrightarrow x=\pm5\)

\(\left\{210:\left[16+3.\left(6+3.2^2\right)\right]\right\}-3\)

\(=\left\{210:\left[16+3.\left(6+3.4\right)\right]\right\}-3\)

\(=\left\{210:\left[16+3.\left(6+12\right)\right]\right\}-3\)

\(=\left\{210:\left[16+3.18\right]\right\}-3\)

\(=\left\{210:\left[16+54\right]\right\}-3\)

\(=\left\{210:70\right\}-3\)

\(=3-3\)

\(=0\)