70-5 . (x-3) = 5.3²

=> 70-5.(x-3)=5.9

=> 70-5.(x-3)=45

=> 5.(x-3)=70-45

=> 5.(x-3)=25

=> x-3=25:5

=> x-3=5

=> x=5+3

=> x=8

\(6^2-\left(x+3\right)=45\)

\(36-\left(x+3\right)=45\)

\(x+3=35-45\)

\(x+3=-10\)

\(x=-13\)

lớp 6 mà bạn

\(6^2-\left(x+3\right)=45\)

\(\Rightarrow36-\left(x+3\right)=45\)

\(\Rightarrow x+3=36-45\)

\(\Rightarrow x+3=-9\)

\(\Rightarrow x=-9-3=-12\)

\(125-5\left(3x-1\right)=5^5.5^3\)

\(\Rightarrow5^3-5\left(3x-1\right)=5^5.5^3\)

\(\Rightarrow5^3-15x+5=5^5.5^3\)

\(\Rightarrow5\left(5^2-3x+1\right)=5^5.5^3\)

\(\Rightarrow5^2-3x+1=5^5.5^3:5\)

\(\Rightarrow25-3x+1=5^7\)

Từ đây làm nốt nhé

\(4^x+1+4^0=65\)

\(\Rightarrow4^{x+1}+1=65\)

\(\Rightarrow4^{x+1}=64\)

\(\Rightarrow4^{x+1}=4^3\)

\(\Rightarrow x+1=3\)

\(\Rightarrow x=2\)

\(70-5\left(x-3\right)=5.3^2\)

\(\Rightarrow70-5\left(x-3\right)=5.9=45\)

\(\Rightarrow5\left(x-3\right)=70-45=25\)

\(\Rightarrow x-3=25:5=5\)

\(\Rightarrow x=8\)

Chúc em học tốt hơn nhé!!

5.3^x = 5.3⁴

=> x = 4

5.3⁴ = 7.3⁵ - 2.3⁵

       = 3⁵ . (7 - 2)

       = 5. 3⁵

  => 3^x = 3⁵

=> x = 5

a) Ta có: \(5\cdot3^x=5\cdot3^4\)

\(\Leftrightarrow3^x=3^4\)

hay x=4

2(x⁴+3)-(9)=17

⇒2x⁴+6+9=17

⇒2x⁴+15=17

⇒ 2x⁴=2

⇒ x⁴=1

⇒ x=\(\pm1\)

b) 5x².x+1-3.4²=-47

⇒5x³+1-48=-47

⇒5x³-47=-47

⇒5x³=0

⇒x³=0

⇒x=0

a) \(2\left(x^4+3\right)-\left(-9\right)=17\)

              \(2x^4+6+9=17\)

                           \(2x^4=2\)

                             \(x^4=1\)

                       ⇒     \(x=1\)

a) 2*(x⁴+3)-(-9)=17

=>2x⁴+2*3+9=17

=>2x⁴+6=17-9=8

=>2x⁴=8-6=2

=>x⁴=2/2=1

=>x=1

c, \(5^{x+4}-3\cdot5^{x+3}=2\cdot5^{11}\)

\(\Leftrightarrow5^{x+3}\cdot5-3\cdot5^{x+3}=2\cdot5^{11}\)

\(\Leftrightarrow5^{x+3}\left(5-3\right)=2\cdot5^{11}\)

\(\Leftrightarrow5^{x+3}\cdot2=2\cdot5^{11}\)

\(\Leftrightarrow5^{x+3}=5^{11}\)

\(\Leftrightarrow x+3=11\)

\(\Leftrightarrow x=8\)

Vậy x = 8

d, \(2^x+2^{x+1}+2^{x+2}+2^{x+3}+2^{x+4}+2^{x+5}=480\)

\(\Leftrightarrow2^x\left(1+2+2^2+2^3+2^4+2^5\right)=480\)

\(\Leftrightarrow2^x\cdot63=480\)

\(\Leftrightarrow2^x=\frac{160}{21}\)

\(\Leftrightarrow x\approx2,93\)

bạn nào chơi ff ko?

bn nào trả lời hộ mk ik

đang gấp !!!

a: Ta có: \(x\left(2x-3\right)-\left(2x-1\right)\left(x+5\right)=17\)

\(\Leftrightarrow2x^2-3x-2x^2-10x+x+5=17\)

\(\Leftrightarrow-12x=12\)

hay x=-1

giúp mk vs xin các bạn 

please

=(((((

1; 5.2² + (\(x\) + 3) = 5²

   5.4  +  (\(x\) + 3) = 25

    20 + (\(x\) + 3) = 25

             \(x\) + 3 = 25 - 20

             \(x+3\) = 5

             \(x\)       = 5  - 3

            \(x\)        = 2

            Vậy \(x=2\)

2; 2³ + (\(x\) - 3²) = 5³ - 4³

   8 +  (\(x\) - 9)    = 125 - 64

   8 + (\(x\) - 9) = 61

         \(x\) - 9 = 61 - 8

         \(x\) - 9 = 53

        \(x\)        = 53  + 9

        \(x\)       = 62

        Vậy \(x\) = 62

3; 3.2 + (\(x\) + 5²) = 10²

       6 + (\(x\) + 25) = 100

              \(x\) + 25 = 100 - 6

              \(x\) + 25  = 94

               \(x\)          = 94 - 25

               \(x\)          = 69

Vậy \(x\) = 69

a) 3x-1=-17

<=>3x=-16

<=>x=-16/3

Vậy...

b) 40-(3x-8)=3(3-5x)

<=>40-3x+8=9-15x

<=>12x = -39

<=> x = -13/4

Vậy ... 

c) x/2(x-2) + x/2x+2 = 2x/(x+1)(x-2)

<=> x/2(x-2) + x/2(x+1) = 2x/(x+1)(x-2)

<=> x(x+1)/2(x-2)(x+1) + x(x-2)/2(x+1)(x-2) = 4x/2(x+1)(x-2)

=>x(x+1) + x(x-2) = 4x

<=> x2 + x + x2 -2x = 4x

<=> 2x^2 -5x = 0

<=> x(2x-5) = 0

<=>x=0 hoặc 2x-5=0

<=>x=0     <=>x=5/2

Vậy...

(Nhớ tick mik nha)

a: =>3x=-16

=>x=-16/3

b: =>40-3x+8=9-15x

=>-3x+48=9-15x

=>12x=-39

=>x=-13/4

c: =>x(x+1)+x(x-2)=4x

=>x^2+x+x^2-2x-4x=0

=>2x^2-5x=0

=>x=0 hoặc x=5/2