1D 2D 3C 4A 5D 6D 7C 8A 9C 104A 5D 6D 7C 8A 9C 10D

D D C A D D C A C A D D C A C D

1. English is more interesting than music.

2. Today they are not as happy as they were yesterday.

3. Ha Noi is not as small as Hai Duong.

4. Mai's sister is not as pretty as her.

6. You have got more money than me.

7. Art is not as difficult as French.

8. Nam's father is more careful than him.

9. No one in our town is as rich as Mr Ron.

10. He is the most intelligent in my class.

11. Everest is the highest mountain in the world.

12. Minh is the fattest person in my group.

13. I can't swim as far as Jan.

14B 15C 16A 17C 18B 19C 20B

bạn có thể chụp thẳng đc hong?????

\(a,x+\dfrac{1}{2}=\dfrac{3}{4}\\ x=\dfrac{3}{4}-\dfrac{1}{2}\\ x=\dfrac{1}{2}\\ b,-\dfrac{2}{3}-x=1\\x=-\dfrac{2}{3}-1\\ x=-\dfrac{5}{3}\\ d,\dfrac{1}{4}+\dfrac{3}{4}:x=\dfrac{5}{2}\\ \dfrac{3}{4}:x=\dfrac{5}{2}-\dfrac{1}{4}\\ \dfrac{3}{4}:x=\dfrac{9}{4}\\ x=\dfrac{3}{4}:\dfrac{9}{4}\\ x=\dfrac{1}{3}\\ e,\left(x+\dfrac{1}{4}\right)\cdot\dfrac{3}{4}=-\dfrac{5}{8}\\ x+\dfrac{1}{4}=-\dfrac{5}{8}:\dfrac{3}{4}\\ x+\dfrac{1}{4}=\dfrac{5}{6}\\ x=\dfrac{5}{6}-\dfrac{1}{4}\\ x=\dfrac{7}{12}\)

\(g,\dfrac{x-3}{15}=\dfrac{-2}{5}\\ 5\left(x-3\right)=-30\\ x-3=-6\\ x=-6+3\\ x=-3\\ h,\dfrac{x}{-2}=\dfrac{-8}{x}\\ x^2=16\\ x=\pm\sqrt{16}\\ x=\pm4\\ k,\dfrac{x+2}{3}=\dfrac{x-4}{5}\\ 5\left(x+2\right)=3\left(x-4\right)\\ 5x+10=3x-12\\ 5x-3x=-12-10\\ 2x=-22\\ x=-11\)

\(m,\left(2x-1\right)^2=4\\ \Rightarrow\left[{}\begin{matrix}2x-1=2\\2x-1=-2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=3\\2x=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)

Đánh giá giúp nhá cảm ơn

à câu c ý

Bài 2: 

a: AD=12cm

MN=12cm

11)11) 3x(x-5)²-(x+2)³+2(x-1)³-(2x+1)(4x²-2x+1)=3x(x²-10x+25)-(x³+6x²+12x+8)+2(x³-3x²+3x-1)-(8x³+1)=3x³-30x²+75x-x³-6x²-12x-8+2x³-6x²+6x-2-8x³-1=-4x³-42x²+63x-11

nhìn khó thế

a: \(x^2-4x-5=\left(x-5\right)\left(x+1\right)\)

b: \(x^2-3x+2=\left(x-2\right)\left(x-1\right)\)

d: \(2x^2-3x+1=\left(x-1\right)\left(2x-1\right)\)

k: \(4x^2-9=\left(2x-3\right)\left(2x+3\right)\)