a: =>x^2-25-x^2-3x=10

=>-3x=35

=>x=-35/3

b: =>4x^2-9-4(x^2+4x+4)=5

=>4x^2-9-4x^2-16x-16-5=0

=>-16x-30=0

=>x=-15/8

c: =>9x^2+45x-9x^2+4=7

=>45x=3

=>x=1/15

d: =>x^3+3x^2+3x+1-x^3-3x^2+5x=8

=>8x=7

=>x=7/8

Câu a) -3 phần 1/2 

Câu a) 2 mũ 2

a: =>-7/2:(4/5-1/2x)=4

=>4/5-1/2x=-7/2:4=-7/8

=>1/2x=4/5+7/8=67/40

=>x=67/20

b: =>5x=5

=>x=1

c: =>x(-2/3-1/3)=-2

=>-x=-2

=>x=2

d: =>-2/3(x+1)=-1/3+1/2=1/6

=>x+1=-1/6:2/3=-1/6*3/2=-3/12=-1/4

=>x=-1/4-1=-5/4

a) (x-2)³+6(x+1)²-x³+12=0

\(\Rightarrow\)x³-6x²+12x-8+6(x²+2x+1)-x³+12=0

\(\Rightarrow\)x³-6x²+12x-8+6x²+12x+6-x³+12=0

\(\Rightarrow\)24x+10=0

\(\Rightarrow\)24x=-10

\(\Rightarrow\)x=\(\dfrac{-10}{24}=\dfrac{-5}{12}\)

b)(x-5)(x+5)-(x+3)²+3(x-2)²=(x+1)²-(x-4)(x+4)+3x²

\(\Rightarrow\)x²-25-(x²+6x+9)+3(x²-4x+4)=x²+2x+1-(x²-16)+3x²

\(\Rightarrow\)x²​-25-x²-6x-9+3x²-12x+12=x²+2x+1-x²+16+3x²

\(\Rightarrow\)3x²-18x-22=3x²+2x+17

\(\Rightarrow\)3x²-18x-22-3x²-2x-17=0

\(\Rightarrow\)-20x-39=0

\(\Rightarrow\)-20x=39

\(\Rightarrow\)x=\(-\dfrac{39}{20}\)

c) (2x+3)² +(x-1)(x+1)=5(x+2)²-(x-5)(x+1)+(x+4)

⇒4x²+12x+9+x²-1=5(x²+4x+4)-(x²+x-5x-5)+x+4

⇒5x²+12x+8=5x²+20x+20-x²-x+5x+5+x+4

⇒5x²+12x+8-5x²-20x-20+x²+x-5x-5-x-4=0

⇒x²-13x-21=0

1. Thu gọn biểu thức - Hoc24 làm rồi mà bạn?

1.

a) \(=x^2-6x+9+3x^2-15x=4x^2-21x+9\)

b) \(=9x^2+12x+4-x^2+9=8x^2+12x+13\)

2.

a) \(\Leftrightarrow x^2+8x+16-x^2+4-5=0\\ \Leftrightarrow8x=-15\\ \Leftrightarrow x=-\dfrac{15}{8}\)

b) \(\Leftrightarrow9x^2-6x+1-8x^2+12x-2x+3-5-x^2=0\\ \Leftrightarrow4x=1\\ \Leftrightarrow x=\dfrac{1}{4}\)

1,a,=x2−6x+8+3x2−15x=4x2−21x+8b,=9x2+12x+4−x2+9=8x2+12x+132,a,⇔x2+8x+16−x2+4=5⇔8x=−15⇔x=−158b,⇔9x2−6x+1−8x2−2x+12x+3−x2=5⇔4x=1⇔x=14

đối với bạn là khó nhưng với mình lại là quá đơn giản

a. \(\frac{1}{3}x-\frac{2}{5}=\frac{2}{3}x+1\)

\(\Leftrightarrow\frac{1}{3}x-\frac{2}{3}x=1+\frac{2}{5}\)

\(\Leftrightarrow-\frac{1}{3}x=\frac{7}{5}\)

\(\Leftrightarrow x=\frac{7}{5}\div\frac{-1}{3}\)

\(\Leftrightarrow x=\frac{21}{-5}\)

b. \(\frac{-4}{5}x+\frac{1}{3}=\frac{2}{3}x+\frac{1}{2}\)

\(\Leftrightarrow\frac{1}{3}-\frac{1}{2}=\frac{2}{3}x+\frac{4}{5}x\)

\(\Leftrightarrow\frac{-1}{6}=\frac{22}{15}x\)

\(\Leftrightarrow x=\frac{-1}{6}\div\frac{22}{15}\)

\(\Leftrightarrow x=\frac{-15}{132}\)

c. \(\frac{5}{6}x-\frac{2}{3}=\frac{1}{2}-\frac{1}{3}\)

\(\Leftrightarrow\frac{5}{6}x-\frac{2}{3}=\frac{1}{6}\)

\(\Leftrightarrow\frac{5}{6}x=\frac{1}{6}+\frac{2}{3}\)

\(\Leftrightarrow\frac{5}{6}x=\frac{5}{6}\)

\(\Leftrightarrow x=1\)

f.\(\frac{3}{7}x-\frac{4}{9}=\frac{1}{7}.2\)

\(\Leftrightarrow\frac{3}{7}x-\frac{4}{9}=\frac{2}{7}\)

\(\Leftrightarrow\frac{3}{7}x=\frac{2}{7}+\frac{4}{9}\)

\(\Leftrightarrow\frac{3}{7}x=\frac{46}{63}\)

\(\Leftrightarrow x=\frac{46}{63}\div\frac{3}{7}\)

\(\Leftrightarrow x=\frac{46}{21}\)

2:

a: =>x^2+3x-4x-12-(x^2-5x+x-5)=8

=>x^2-x-12-x^2+4x+5=8

=>3x-7=8

=>3x=15

=>x=5

b: =>3x^2+3x-2x-2-3x^2-21x=13

=>-20x=15

=>x=-3/4

c: =>x^2-25-x^2-2x=9

=>-2x=25+9=34

=>x=-17

d: =>x^3-1-x^3+3x=1

=>3x-1=1

=>3x=2

=>x=2/3